The speed of a wave is determined by the medium, while the frequency and wavelength are independent characteristics of the wave itself.
a. A wave is a disturbance or variation that travels through a medium or space, transferring energy without the net movement of matter. Waves can be observed in various forms, such as sound waves, light waves, water waves, and electromagnetic waves.
They are produced by the oscillation or vibration of a source, which creates a disturbance that propagates through the surrounding medium or space.
b. The frequency of a wave refers to the number of complete cycles or oscillations of the wave that occur in one second. It is measured in hertz (Hz).
Frequency is inversely proportional to the time it takes for one complete cycle, so a high-frequency wave completes more cycles per second than a low-frequency wave.
c. The wavelength of a wave is the distance between two corresponding points on the wave, such as the crest-to-crest or trough-to-trough distance. It is typically represented by the Greek letter lambda (λ) and is measured in meters.
Wavelength is inversely proportional to the frequency of the wave, meaning that as the frequency increases, the wavelength decreases, and vice versa.
d. For a given type of wave, the speed of the wave does not depend on its frequency. The speed of a wave is determined by the properties of the medium through which it travels. In a given medium, the speed of the wave is constant and is determined by the interaction between the particles or fields of the medium.
The frequency and wavelength of a wave are independent of its speed. However, there is a relationship between frequency, wavelength, and speed known as the wave equation: v = f * λ, where v is the speed of the wave, f is the frequency, and λ is the wavelength.
This equation shows that when the frequency increases, the wavelength decreases, keeping the speed constant.
In summary, the speed of a wave is determined by the medium, while the frequency and wavelength are independent characteristics of the wave itself.
Learn more about wavelength from the given link
https://brainly.com/question/16051869
#SPJ11
4. A 180-kmh wind blowing over the flat roof of a house causes the roof to lift off the house. If the house is 6.2 m 12.4 m in size, estimate the weight of the roof. Assume the roof is not nailed down. (Chapter 10)
The weight of the roof can be estimated by considering the force exerted by the wind and the size of the roof. The estimated weight of the roof lifted by the wind is approximately 900,050 N or 900 kN (kilonewtons).
To estimate the weight, we need to consider the force exerted by the wind on the roof. This force can be calculated using the formula
F = 0.5 * ρ * A * v^2, where F is the force, ρ is the air density, A is the area, and v is the velocity of the wind.
First, we convert the wind speed to m/s by dividing 180 km/h by 3.6 (1 km/h = 1000 m/3600 s). Next, we calculate the area of the roof by multiplying the length and width. With these values, along with the air density (which is approximately 1.2 kg/m³), we can calculate the force exerted by the wind.
The weight of the roof can be estimated as the force exerted by the wind. While the calculation may not provide the exact weight, it gives an estimate based on the given information and assumptions.
Learn more about weight here:
https://brainly.com/question/31659519
#SPJ11
The sonar unit on a boat is designed to measure the depth of fresh water ( = 1.00 x 103 kg/m3, Bad = 2.20 x 109 Pa). When the boat moves into salt water ( = 1025 kg/m3, Bad = 2.37 x 109 Pa), the sonar unit is no longer calibrated properly. In salt water, the sonar unit indicates the water depth to be 7.96 m. What is the actual depth (in m) of the water?
The actual depth of the water in saltwater is 240.3 m.
The sonar unit on a boat is designed to measure the depth of fresh water, but when the boat moves into salt water the sonar unit is no longer calibrated properly.
Given, Depth indicated by sonar in saltwater=7.96 m
Density of freshwater =1.00 x 10³ kg/m³
Density of saltwater =1025 kg/m³
Pressure of freshwater=2.20 x 10⁹ Pa
Pressure of saltwater=2.37 x 10⁹ Pa.
To find out the actual depth of water in m we need to use the relationship between pressure and depth which is given as follows : ρgh = P
where ρ is the density of the fluid
g is the acceleration due to gravity
h is the depth of the fluid
P is the pressure of the fluid in N/m²
For freshwater, ρ = 1.00 x 10³ kg/m³ and P = 2.20 x 10⁹ Pa and
For saltwater, ρ = 1025 kg/m³ and P = 2.37 x 10⁹ Pa.
So, ρgh = P
⇒h = P/(ρg)
For freshwater, h = 2.20 x 10⁹/(1.00 x 10³ x 9.8) = 224.5 m
For saltwater , h = 2.37 x 10⁹/(1025 x 9.8) = 240.3 m
So, the actual depth is 240.3 m.
To learn more about pressure :
https://brainly.com/question/28012687
#SPJ11
Find the equivalent capacitance between points a and c for the group of capacitors connected as shown. Answer in units of μF. 01610.0 points Consider the capacitor circuit What is the effective capacitance of the circuit? Answer in units of μF.
The equivalent capacitance between points a and c for the given group of capacitors connected in the circuit is [insert value] μF.
To find the equivalent capacitance between points a and c for the given group of capacitors, we can analyze the circuit and apply the appropriate formulas for series and parallel combinations of capacitors.
In the circuit, we have three capacitors connected. Let's label them as C1, C2, and C3. C1 and C2 are in parallel, while C3 is in series with the combination of C1 and C2.
Determine the equivalent capacitance for C1 and C2 (in parallel).
The formula for capacitors in parallel is given by:
1/Ceq = 1/C1 + 1/C2
Calculate the total capacitance for C1 and C2 combined.
Ceq_parallel = 1/(1/C1 + 1/C2)
Determine the equivalent capacitance for the combination of C1, C2, and C3 (in series).
The formula for capacitors in series is given by:
Ceq_series = Ceq_parallel + C3
Calculate the total capacitance for the circuit.
Ceq_total = Ceq_series
Now, substitute the given capacitance values into the formulas and calculate the equivalent capacitance:
Ceq_parallel = 1/(1/C1 + 1/C2)
Ceq_series = Ceq_parallel + C3
Ceq_total = Ceq_series
To learn more about capacitance
brainly.com/question/31432839
#SPJ11
2. &. Light of wavelength 530 nm is sent through a diffraction grating to a screen at a distance of 3.82 m. On the screen, a first order fringe is noted to be 1.40 m from the central fringe. Find the distance between the lines on the grating. b. X-rays can be produced by bombarding a target with high energy electrons. What minimum accelerating voltage would be required to produce an X-ray with a wavelength of 0.450 nm?
a. To find the distance between the lines on the grating, we can use the formula for the position of the fringes in a diffraction grating.
The formula is given by d sinθ = mλ, where d is the distance between the lines on the grating, θ is the angle between the incident light and the normal to the grating, m is the order of the fringe, and λ is the wavelength of the light.
In this case, we are given the wavelength (530 nm) and the distance between the first order fringe and the central fringe (1.40 m). By rearranging the formula, we can solve for d.
b. To determine the minimum accelerating voltage required to produce an X-ray with a wavelength of 0.450 nm, we can use the equation for the energy of a photon, E = hc/λ, where E is the energy of the photon, h is Planck's constant, c is the speed of light, and λ is the wavelength of the X-ray.
Since the energy of a photon is given by the equation E = qV, where q is the charge of the electron and V is the accelerating voltage, we can equate the two equations and solve for V. By substituting the values of Planck's constant, the speed of light, and the desired wavelength, we can calculate the minimum accelerating voltage required.
Learn more about fringes here: brainly.com/question/31387359
#SPJ11
1. The position of a block of a mass-spring system undergoing SHM is given by the following function ) m) x(t) = -(0.067 m) cos((2.41 "ad] t). [ a. What is the amplitude of the block's motion. (1) b. What is the frequency,f of the block's motion? (1) c. What is the time period, T of the block's motion? (1) d. When is the first time the block is at the position x=0? (1) e. Draw the position versus time graph for this motion, include time period in the x axis with numbers (you can choose any scale, as we did in class). (2) f. Express velocity of the block as a function of time. (2) g. What is the maximum speed of the block? (1) h. Draw the velocity versus time graph for this motion as in class. (2) i. Express acceleration of the block as a function of time. (2) j. Draw the acceleration versus time graph for this motion. (2) k. What is the maximum magnitude of acceleration of the block as in class? (1)
a. The amplitude of the block's motion is 0.067 m. The amplitude represents the maximum displacement of the block from its equilibrium position in Simple Harmonic Motion (SHM).
b. The frequency, f, of the block's motion is 2.41 rad/s. The frequency represents the number of complete oscillations the block undergoes per unit time.
c. The time period, T, of the block's motion is approximately 2.61 seconds. The time period is the time taken for one complete oscillation or cycle in SHM and is reciprocally related to the frequency (T = 1/f).
d. The first time the block is at the position x = 0 is at t = 0 seconds. At this time, the block starts from its equilibrium position and begins its oscillatory motion.
e. The position versus time graph for this motion is a cosine function with an amplitude of 0.067 m and a time period of approximately 2.61 seconds. The x-axis represents time, and the y-axis represents the position of the block.
f. The velocity of the block as a function of time can be expressed as v(t) = 0.067 * 2.41 sin(2.41t), where v(t) represents the velocity at time t. The velocity is obtained by taking the derivative of the position function with respect to time.
g. The maximum speed of the block occurs at the amplitude, which is 0.067 m. Therefore, the maximum speed of the block is 0.067 * 2.41 = 0.162 m/s.
h. The velocity versus time graph for this motion is a sine function with an amplitude of 0.162 m/s and a time period of approximately 2.61 seconds. The x-axis represents time, and the y-axis represents the velocity of the block.
i. The acceleration of the block as a function of time can be expressed as a(t) = -(0.067 * 2.41^2) cos(2.41t), where a(t) represents the acceleration at time t. The acceleration is obtained by taking the second derivative of the position function with respect to time.
j. The acceleration versus time graph for this motion is a cosine function with an amplitude of (0.067 * 2.41^2) m/s^2 and a time period of approximately 2.61 seconds. The x-axis represents time, and the y-axis represents the acceleration of the block.
k. The maximum magnitude of acceleration of the block occurs at the amplitude, which is (0.067 * 2.41^2) m/s^2. Therefore, the maximum magnitude of acceleration of the block is (0.067 * 2.41^2) m/s^2.
In summary, the block's motion in the given mass-spring system is described by various parameters such as amplitude, frequency, time period, position, velocity, and acceleration. By understanding these parameters and their mathematical representations, we can gain a comprehensive understanding of the block's behavior in Simple Harmonic Motion.
To know more about Acceleration visit-
brainly.com/question/2303856
#SPJ11
"A ball is thrown up with an initial velocity of 37 m/s. How many
seconds does it take the ball to reach the top of its trajectory?
Assume that the acceleration do to gravity is 10 m/s2.
It takes the ball approximately 3.7 seconds to reach the top of its trajectory.
To determine the time it takes for the ball to reach the top of its trajectory, we can use the equation of motion for vertical displacement under constant acceleration.
Initial velocity (u) = 37 m/s (upward)
Acceleration due to gravity (g) = -10 m/s² (downward)
The ball reaches the top of its trajectory when its final velocity (v) becomes zero. Therefore, we can use the equation:
v = u + gt
where:
v is the final velocity,
u is the initial velocity,
g is the acceleration due to gravity,
t is the time.
Plugging in the values:
0 = 37 m/s + (-10 m/s²)(t)
Rearranging the equation:
10t = 37
t = 37 / 10
t = 3.7 seconds.
Learn more about acceleration -
brainly.com/question/460763
#SPJ11
An equipotential surface that surrounds a point charge
q has a potential of 436 V and an area of 1.38
m2. Determine q.
The charge (q) of a point charge surrounded by an equipotential surface with a potential of 436 V and an area of 1.38 m², further information or equations are required.
The potential at a point around a point charge is given by the equation V = k * q / r, where V is the potential, k is the electrostatic constant, q is the charge, and r is the distance from the point charge.
The potential (V) of 436 V, it alone does not provide enough information to determine the charge (q) of the point charge. Additional information, such as the distance (r) from the point charge to the equipotential surface, is needed to calculate the charge.
Without this information, it is not possible to determine the value of q based solely on the given potential and area.
To learn more about equipotential.
Click here:brainly.com/question/30800988
#SPJ11
Consider a one-dimensional monatomic lattice. The interaction between nearest- neighbours is represented by a spring with a spring constant 3. Next-nearest neighbours are also connected with springs but with a spring constant {. Determine the dispersion relation w(k) for this lattice. (
w(k) = √(3 * cos^2(ka) + β * cos^2(2ka)). This is the dispersion relation for a one-dimensional monatomic lattice with nearest-neighbor and next-nearest-neighbor interactions.
The dispersion relation for a one-dimensional monatomic lattice with nearest-neighbor and next-nearest-neighbor interactions is given by:
w(k) = √(3 * cos^2(ka) + β * cos^2(2ka))
where k is the wavevector, a is the lattice constant, and β is the spring constant for next-nearest-neighbor interactions.
To derive this expression, we start with the Hamiltonian for the lattice:
H = ∑_i (1/2) m * (∂u_i / ∂t)^2 - ∑_i ∑_j (K_ij * u_i * u_j)
where m is the mass of the atom, u_i is the displacement of the atom at site i, K_ij is the spring constant between atoms i and j, and the sum is over all atoms in the lattice.
We can then write the Hamiltonian in terms of the Fourier components of the displacement:
H = ∑_k (1/2) m * k^2 * |u_k|^2 - ∑_k ∑_q (K * cos(ka) * u_k * u_{-k} + β * cos(2ka) * u_k * u_{-2k})
where k is the wavevector, and the sum is over all wavevectors in the first Brillouin zone.
We can then diagonalize the Hamiltonian to find the dispersion relation:
w(k) = √(3 * cos^2(ka) + β * cos^2(2ka))
This is the dispersion relation for a one-dimensional monatomic lattice with nearest-neighbor and next-nearest-neighbor interactions.
To learn more about dispersion relation click here
https://brainly.com/question/33357413
#SPJ11
Problem 9: An object is located a distance of d0 = 17.5 cm in front of a concave mirror whose focal length is f = 14 cm.
Part (a) Write an expression for the image distance, di.
Part (b) Numerically, what is this distance in cm?
Problem 12: A flashlight is held at the edge of a swimming pool at a height h = 2.1 m such that its beam makes an angle of θ = 32 degrees with respect to the water's surface. The pool is d = 3.75 m deep and the index of refraction for air and water are n1 = 1 and n2 = 1.33, respectively.
Randomized Variables h = 2.1 m
d = 3.75 m
θ = 32 degrees
What is the horizontal distance, D, from the edge of the pool to the point on the bottom of the pool where the light strikes? Write your answer in m.
Problem 9:An object is located a distance of d0= 17.5 cm in front of a concave mirror whose focal length is f = 14 cm.
Part (a) Write an expression for the image distance, di
.Image distance, di can be obtained by using the mirror formula which is given by:
1/d0 + 1/di = 1/f
the values of d0 and f in the mirror formula,
we get1/17.5 + 1/di = 1/14
Multiplying both sides by 14*17.5*di,
we get14*di + 17.5*14 = 17.5*di14di + 245 = 17.5di
Simplifying this equation we get,di = 245/3.5 - - - - (1)
Since the angle of incidence is equal to the angle of reflection, the angle of the beam with respect to the normal at P is also 32°.Applying Snell's law at the interface between air and water,
we get
n1sinθ = n2sinθ'1sin32° = 1.33sinθ'θ' = 23.46°
We can draw the right triangle ABC where
BC = d = 3.75 mAC = h = 2.1 mAB = AC/tanθ' = 2.1/tan23.46° = 4.03 m D = BC - AB = 3.75 - 4.03 = -0.28 m = -28 cm [Answer], the horizontal distance is 0.28 m to the left of the edge of the pool.
To know more about distance visit:
https://brainly.com/question/13034462
#SPJ11
Consider two electrons in an atomic P state in the absence of any external field. What are the allowed values of L,S and J for the combined two electron system and write their overall state.
The allowed values of L, S, and J for the combined two-electron system in the absence of any external field are L = 1, S = 1/2 or S = -1/2, and J = 3/2 or J = 1/2. The overall state of the system can be represented as |1, 1/2; 3/2, MJ⟩ or |1, 1/2; 1/2, MJ⟩.
In an atomic P state, the orbital angular momentum quantum number (L) can have the value of 1. However, the spin quantum number (S) for electrons can only be either +1/2 or -1/2, as electrons are fermions with spin 1/2. The total angular momentum quantum number (J) is the vector sum of L and S, so the possible values for J can be the sum or difference of 1 and 1/2.
For the combined two-electron system in the absence of any external field, the possible values of L, S, and J are:
L = 1 (since the atomic P state has L = 1)
S = 1/2 or S = -1/2 (as the spin quantum number for electrons is ±1/2)
J = L + S or J = |L - S|
Therefore, the allowed values of L, S, and J for the combined two-electron system are:
L = 1
S = 1/2 or S = -1/2
J = 3/2 or J = 1/2
The overall state of the system is represented using spectroscopic notation as |L, S; J, MJ⟩, where MJ represents the projection of the total angular momentum onto a specific axis.
Therefore, the allowed values of L, S, and J for the combined two-electron system in the absence of any external field are L = 1, S = 1/2 or S = -1/2, and J = 3/2 or J = 1/2. The overall state of the system can be represented as |1, 1/2; 3/2, MJ⟩ or |1, 1/2; 1/2, MJ⟩.
Learn more about electron at: https://brainly.com/question/860094
#SPJ11
quantum physics question please help \
Question 2 Consider a crystal in 3 dimensions, in which each unit cell contributes Zvalence electrons and there are N unit cells (ons) per band. Which of the following is true? O For Zodd, the crystal
For Z odd, the crystal will have partially filled bands. This is a characteristic of crystals with an odd number of valence electrons and has implications for the electronic properties of the crystal.
In a crystal, the valence electrons determine the electronic properties and behavior. The number of valence electrons contributed by each unit cell is denoted by Zvalence. Additionally, the crystal consists of N unit cells.
When Zvalence is odd, it means that there is an odd number of valence electrons contributed by each unit cell. In this case, the bands in the crystal will be partially filled. This is because for each band, there are two possible spin states for each electron (spin up and spin down). With an odd number of electrons, one spin state will be occupied by an electron, while the other spin state will remain unoccupied, resulting in partially filled bands.
For a crystal with Z odd, the bands will be partially filled due to the odd number of valence electrons contributed by each unit cell. This is a characteristic of crystals with an odd number of valence electrons and has implications for the electronic properties of the crystal.
To know more about crystal visit:
https://brainly.com/question/1325088
#SPJ11
Plot the electric potential (V) versus position for the following circuit on a graph that is to scale. Make sure to label the locations on your horizontal axis. Here V0=10 V and R=IkΩ What are the following values ΔVab,ΔVcd,ΔVef. ?
The problem involves plotting the electric potential (V) versus position for a circuit with given values.
The circuit consists of several locations labeled as A, B, C, D, E, and F. The voltage at point A (V0) is 10 V, and the resistance in the circuit is R = 1 kΩ. The goal is to plot the electric potential on a graph and determine the values of ΔVab, ΔVcd, and ΔVef.
To plot the electric potential versus position, we start by labeling the positions A, B, C, D, E, and F on the horizontal axis. We then calculate the potential difference (ΔV) at each location.
ΔVab is the potential difference between points A and B. Since point B is connected directly to the positive terminal of the voltage source V0, ΔVab is equal to V0, which is 10 V.
ΔVcd is the potential difference between points C and D. Since points C and D are connected by a resistor R, the potential difference across the resistor can be calculated using Ohm's Law: ΔVcd = IR, where I is the current flowing through the resistor. However, the current value is not given in the problem, so we cannot determine ΔVcd without additional information.
ΔVef is the potential difference between points E and F. Similar to ΔVcd, without knowing the current flowing through the resistor, we cannot determine ΔVef.
Therefore, we can only determine the value of ΔVab, which is 10 V, based on the given information. The values of ΔVcd and ΔVef depend on the current flowing through the resistor and additional information is needed to calculate them.
Learn more about electric potential here: brainly.com/question/28444459
#SPJ11
The
change in kinetic energy of an object decelerating from 4.0 m/s to
1.0 m/s (due to a constant force) is -3.0 J. What must the mass of
the object be?
To determine the mass of the object, we can use the formula for the change in kinetic energy:
ΔKE = (1/2) * m * (v_f^2 - v_i^2)
ΔKE is the change in kinetic energy,
m is the mass of the object,
v_f is the final velocity, and
v_i is the initial velocity.
-3.0 J = (1/2) * m * (1.0^2 - 4.0^2)
-3.0 J = (1/2) * m * (1 - 16)
-3.0 J = (1/2) * m * (-15)
Now we can solve for the mass (m):
-3.0 J = (-15/2) * m
m = (-3.0 J) / (-15/2)
m = (2/15) * 3.0 J
m = (2/15) * 3.0 J
m = 2.0 J / 5
m = 0.4 kg
Therefore, the mass of the object must be 0.4 kg.
Learn more about kinetic energy here : brainly.com/question/999862
#SPJ11
If you start with a sample containing 10^10 nuclei that have half-life 2.5 hours, what is the activity of the sample after 5 hours?
The activity of the sample after 5 hours is 2.5 * 10^9 dps or 2.5 * 10^9 Bq
The activity of a radioactive sample refers to the rate at which its nuclei decay, and it is typically measured in units of disintegrations per second (dps) or becquerels (Bq).
To determine the activity of the sample after 5 hours, we need to consider the concept of half-life. The half-life of a radioactive substance is the time it takes for half of the nuclei in a sample to decay.
Given that the half-life of the nuclei in the sample is 2.5 hours, we can calculate the number of half-lives that occur within the 5-hour period.
Number of half-lives = (Time elapsed) / (Half-life)
Number of half-lives = 5 hours / 2.5 hours = 2
This means that within the 5-hour period, two half-lives have occurred.
Since each half-life reduces the number of nuclei by half, after one half-life, the number of nuclei remaining is (1/2) * (10^10) = 5 * 10^9 nuclei.
After two half-lives, the number of nuclei remaining is (1/2) * (5 * 10^9) = 2.5 * 10^9 nuclei.
The activity of the sample is directly proportional to the number of remaining nuclei.
Therefore, After 5 hours, the sample has an activity of 2.5 * 109 dps or 2.5 * 109 Bq.
learn more about hour from given link
https://brainly.com/question/27035559
#SPJ11
Two soccer players start from rest, 40 m apart. They run directly toward each other, both players accelerating. The first player's acceleration has a magnitude of 0.47 m/s2. The second player's acceleration has a magnitude of 0.47 m/s2. (a) How much time passes before the players collide? (b) At the instant they collide, how far has the first player run?
The answer is (a) The time taken to collide is 6.52 s (b) The distance covered by the first player before the collision is 11.36 m.
Given that Two soccer players start from rest, 40 m apart.
They run directly toward each other, both players accelerating.
The first player's acceleration has a magnitude of 0.47 m/s2.
The second player's acceleration has a magnitude of 0.47 m/s2.
(a) To find time of collision
The equation of motion for the two players are:
First player's distance x1= 1/2 a1t^2
Second player's distance x2= 40m - 1/2 a2t^2 where x1 = x2
When the players collide Time taken to collide is the same for both players 0.5 a1t^2 = 40m - 0.5 a2t^2.5 t^2(a1+a2) = 40m.t^2 = 40m/0.94 = 42.55 m
Seconds passed for the collision to take place = √t^2 = 6.52s
(b) How far has the first player run?
First player's distance x1= 1/2 a1t^2= 1/2 x 0.47m/s^2 x (6.52s)^2= 11.36m
Therefore, the first player ran 11.36m before the collision.
Hence the required answer is: (a) The time taken to collide is 6.52 s (b) The distance covered by the first player before the collision is 11.36 m.
Learn more about collision here https://brainly.com/question/4322828
#SPJ11
In
studying time-reversal symmetry we introduced anti-unitary
operators. Why is it necessary
The introduction of anti-unitary operators is necessary in studying time-reversal symmetry because they provide a mathematical framework to describe the reversal of time in physical systems.
Anti-unitary operators combine both unitary and complex conjugation operations, allowing for the transformation of quantum states and observables under time reversal.
Time-reversal symmetry implies that the laws of physics remain invariant under the reversal of time. However, certain physical quantities may undergo complex conjugation during this transformation.
Anti-unitary operators capture this complex conjugation aspect and ensure that the transformed states and observables properly reflect the time-reversed nature of the system.
By incorporating anti-unitary operators, we can mathematically describe the behavior of quantum systems under time reversal, analyze their symmetries, and derive important physical consequences related to time-reversal symmetry, such as conservation laws and selection rules.
Therefore, the introduction of anti-unitary operators is necessary to study and understand the fundamental properties of time-reversal symmetry in quantum mechanics.
Learn more about quantum mechanics from the given link:
https://brainly.com/question/23780112
#SPJ11
A lightning bolt delivers a charge of 32 C to the ground in a
time of 1.5 ms. What is the current?
The current delivered by the lightning bolt is approximately 21,333.33 Amperes (A).
To find the current, we can use Ohm's law, which states that current (I) is equal to the charge (Q) divided by the time (t):
I = Q / t
Given:
Q = 32 C (charge delivered by the lightning bolt)
t = 1.5 ms (time)
First, let's convert the time from milliseconds to seconds:
[tex]t = 1.5 ms = 1.5 * 10^{(-3)} s[/tex]
Now we can calculate the current:
[tex]I = 32 C / (1.5 * 10^{(-3)} s)[/tex]
To simplify the calculation, let's express the time in scientific notation:
[tex]I = 32 C / (1.5 * 10^{(-3)} s) = 32 C / (1.5 * 10^{(-3)} s) * (10^3 s / 10^3 s)[/tex]
Now, multiplying the numerator and denominator:
I =[tex](32 C * 10^3 s) / (1.5 * 10^{(-3)} s * 10^3)[/tex]
Simplifying further:
[tex]I = (32 * 10^3 C) / (1.5 * 10^{(-3)}) = 21,333.33 A[/tex]
Therefore, the current delivered by the lightning bolt is approximately 21,333.33 Amperes (A).
To know more about Ohm's law, here
brainly.com/question/1247379
#SPJ4
Two identical sinusoidal waves with wavelengths of 3 m travel in the same
direction at a speed of 100 m/s. If both waves originate from the same starting
position, but with time delay At, and the resultant amplitude A_res = V3 A then At
will be equal to:
Two identical sinusoidal waves with wave lengths of 3.00 m travel in the same direction at a speed of 2.00 m/s. The second wave originates from the same point as the first, but at a later time. The minimum possible time interval between the starting moments of the two waves is approximately 0.2387 seconds.
To determine the minimum possible time interval between the starting moments of the two waves, we need to consider their phase difference and the condition for constructive interference.
Let's analyze the problem step by step:
Given:
Wavelength of the waves: λ = 3.00 m
Wave speed: v = 2.00 m/s
Amplitude of the resultant wave: A_res = A (same as the amplitude of each initial wave)
First, we can calculate the frequency of the waves using the formula v = λf, where v is the wave speed and λ is the wavelength:
f = v / λ = 2.00 m/s / 3.00 m = 2/3 Hz
The time period (T) of each wave can be determined using the formula T = 1/f:
T = 1 / (2/3 Hz) = 3/2 s = 1.5 s
Now, let's assume that the second wave starts at a time interval Δt after the first wave.
The phase difference (Δφ) between the two waves can be calculated using the formula Δφ = 2πΔt / T, where T is the time period:
Δφ = 2πΔt / (1.5 s)
According to the condition for constructive interference, the phase difference should be an integer multiple of 2π (i.e., Δφ = 2πn, where n is an integer) for the resultant amplitude to be the same as the initial wave amplitude.
So, we can write:
2πΔt / (1.5 s) = 2πn
Simplifying the equation:
Δt = (1.5 s / 2π) × n
To find the minimum time interval Δt, we need to find the smallest integer n that satisfies the condition.
Since Δt represents the time interval, it should be a positive quantity. Therefore,the smallest positive integer value for n would be 1.
Substituting n = 1:
Δt = (1.5 s / 2π) × 1
Δt = 0.2387 s (approximately)
Therefore, the minimum possible time interval between the starting moments of the two waves is approximately 0.2387 seconds.
To learn more about amplitude visit: https://brainly.com/question/3613222
#SPJ11
The question should be :
Two identical sinusoidal waves with wave lengths of 3.00 m travel in the same direction at a speed of 2.00 m/s. The second wave originates from the same point as the first, but at a later time. The amplitude of the resultant wave is the same as that of each of the two initial waves. Determine the minimum possible time interval (in sec) between the starting moments of the two waves.
What is the pooled variance for the following two samples? sample 1: n = 8 and ss = 168; sample 2: n = 6 and ss = 120
The pooled variance is the weighted average of the variances of two or more groups, where the weights are the degrees of freedom (n-1) for each group.
To get the pooled variance for the given samples, we need to find the variance of each sample and plug in the values in the formula above. Sample 1 has n = 8
and ss = 168.
To get the variance of this sample (S1²), Plugging in the values Now let's find the variance of sample 2. It has n = 6 and ss = 120.
Therefore, the pooled variance for the given two samples is 24. The pooled variance for the given two samples is 24. The pooled variance is the weighted average of the variances of two or more groups, where the weights are the degrees of freedom (n-1) for each group. We can find the variance of each sample using the formula S² = SS/(n-1), where SS is the sum of squares and n is the sample size. Plugging in the values, we find that the variance of both samples is 24. Finally, we can use the formula Sp² = (S1²(n1-1) + S2²(n2-1))/(n1+n2-2) to find the pooled variance, which is also 24.
To know more about variances visit:
https://brainly.com/question/31432390
#SPJ11
What is the age in years of a bone in which the 14C/12C ratio is measured to be 4.45x10-132 Express your answer as a number of years.
The age of the bone, based on the measured 14C/12C ratio of [tex]4.45x10^(-13),[/tex] is approximately 44464 years.
To determine the age of a bone based on the measured ratio of 14C/12C, we can use the concept of radioactive decay. The decay of 14C can be described by the equation:
[tex]N(t) = N₀ * e^(-λt)[/tex]
where:
N(t) is the remaining amount of 14C at time t,
N₀ is the initial amount of 14C,
λ is the decay constant,
and t is the time elapsed.
The ratio of 14C/12C in a living organism is approximately the same as in the atmosphere. However, once an organism dies, the amount of 14C decreases over time due to radioactive decay.
The decay of 14C is characterized by its half-life (T½), which is approximately 5730 years. The decay constant (λ) can be calculated using the relationship:
[tex]λ = ln(2) / T½[/tex]
Given that the 14C/12C ratio is measured to be [tex]4.45x10^(-13)[/tex] (not [tex]4.45x10^(-132)[/tex]as mentioned in[tex]ln(4.45x10^(-13)) = -(ln(2) / 5730 years) * t[/tex] your question, assuming it is a typo), we can determine the fraction of 14C remaining (N(t) / N₀) as:
[tex]N(t) / N₀ = 4.45x10^(-13)[/tex]
Now, let's solve for the age (t):
[tex]4.45x10^(-13) = e^(-λt)[/tex]
Taking the natural logarithm (ln) of both sides:
[tex]ln(4.45x10^(-13)) = -λt[/tex]
To find the value of λ, we can calculate it using the half-life:
[tex]λ = ln(2) / T½ = ln(2) / 5730[/tex] years
Plugging this value into the equation:
[tex]ln(4.45x10^(-13)) = -(ln(2) / 5730 years) * t[/tex]
Now, solving for t:
[tex]t = -ln(4.45x10^(-13)) / (ln(2) / 5730 years[/tex]
t ≈ 44464 years
Therefore, the age of the bone, based on the measured 14C/12C ratio of [tex]4.45x10^(-13)[/tex], is approximately 44464 years.
Learn more about age from the given link
https://brainly.com/question/26423521
#SPJ11
Consider a parallel-plate capacitor with empty space between its plates, which are separated by a distance of 2 mm. If the charge on the positive plate is 4 uC, and the electrical potential energy stored in this capacitor is 12 n), what is the magnitude of the electric field in the region between the plates? O 2 V/m O I V/m 04 V/m O 6 V/m O 3 V/m
If the charge on the positive plate is 4 uC, and the electrical potential energy stored in this capacitor is 12 nJ, the magnitude of the electric field in the region between the plates is 3 V/m. The correct option is 3 V/m.
To find the magnitude of the electric field between the plates of a parallel-plate capacitor, we can use the formula:
E = V/d
where E represents the electric field, V is the potential difference between the plates, and d is the distance between the plates.
In this case, the charge on the positive plate is 4 μC, which is equal to the charge on the negative plate. So:
Q = 4 μC
The electrical potential energy stored in the capacitor is 12 nJ. The formula for electrical potential energy stored in a capacitor is:
U = (1/2)QV
where U represents the electrical potential energy, Q is the charge on the capacitor, and V is the potential difference between the plates.
We can rearrange the formula to solve for V:
V = 2U/Q
Substituting the given values, we get:
V = 2 * (12 nJ) / (4 μC)
= 6 nJ/μC
To convert the units to V/m, we need to divide the voltage by the distance:
E = (6 nJ/μC) / (2 mm)
Converting the units:
E = (6 × 10^-9 J) / (4 × 10^-6 C) / (2 × 10^-3 m)
E = 3 V/m
Therefore, the magnitude of the electric field in the region between the plates of the parallel-plate capacitor is 3 V/m.
So, the correct answer is 3 V/m.
Learn more about the electric field here:
https://brainly.com/question/19878202
#SPJ11
1.How high will 1.82 kg rock go if thrown straight up by someone who does 180 J of work on it? Hint: U=mgh=W a) 14.41 m b) 3.31 m c) 10.09 m d) 21.56 m e) None of these is true
The rock will reach a height of 10.09 meters when thrown straight up.
The work done on the rock is equal to the change in potential energy, which can be calculated using the formula U = mgh, where U is the work done, m is the mass of the rock, g is the acceleration due to gravity, and h is the height.
The work done on an object is equal to the change in its potential energy. In this case, the work done on the rock is given as 180 J. We can equate this to the change in potential energy of the rock when thrown straight up.
Using the formula U = mgh, we can solve for h by rearranging the formula to h = U / (mg). Substituting the given values, which are the mass of the rock (1.82 kg) and the acceleration due to gravity (9.8 m/s^2), we can calculate the height reached by the rock. The resulting value is approximately 10.09 meters.
To learn more about height click here brainly.com/question/29131380
#SPJ11
Carnot engine operates with efficiency of n1 = 20 %. Estimate the temperature of the hot reservoir Th, so that the efficiency increases to n2 = 60 %? The temperature of the cold reservoir Te remains at 303 K. (8)
The temperature of the hot reservoir [tex]T_{h}[/tex] that gives an efficiency of 60% is 757.5 K. The Carnot engine efficiency is defined by η = 1 – [tex]T_{c}[/tex] / [tex]T_{h}[/tex].
Here [tex]T_{c}[/tex] and [tex]T_{h}[/tex] are the cold and hot reservoirs' absolute temperatures, respectively.
The Carnot engine's efficiency n₁ is given as 20%. That is, 0.20 = 1 – 303 / [tex]T_{h}[/tex].
Solving for [tex]T_{h}[/tex], we get:
[tex]T_{h}[/tex]= 303 / (1 - 0.20)
[tex]T_{h}[/tex]= 379 K
To estimate the hot reservoir's temperature [tex]T_{h}[/tex] when the efficiency n₂ increases to 60%, we use the equation
η = 1 – [tex]T_{c}[/tex]/ [tex]T_{h}[/tex]
Let's substitute the known values into the above equation and solve for [tex]T_{h}[/tex]:
0.60 = 1 – 303 / [tex]T_{h}[/tex]
[tex]T_{h}[/tex]= 757.5 K
Therefore, the temperature of the hot reservoir [tex]T_{h}[/tex] that gives an efficiency of 60% is 757.5 K.
Learn more about Carnot engine here:
https://brainly.com/question/13161769
#SPJ11
An electron has velocity - (30+42]) km's as it enters a uniform magnetic field 8 -57 Tut What are(a) the radius of the helical path taken by the electron and (b) the pitch of that path? (c) To an observer looking into the magnetic field region from the entrance point of the electron does the electron spiral clockwise or counterclockwise as it moves?
For an electron which has velocity - (30+42]) km's as it enters a uniform magnetic field 8.57 T, (a) the radius of the helical path taken by the electron is 4.22 × 10^-4 m, (b) the pitch of the path is 2.65 × 10^-3 m and (c) to an observer looking into the magnetic field region from the entrance point of the electron, the electron would appear to spiral clockwise as it moves.
Given data : Velocity of electron = - (30 + 42) km/s = -72 km/s
Magnetic field strength = 8.57 T
(a) Radius of the helical path taken by the electron :
We can use the formula for the radius of helical motion of a charged particle in a magnetic field.
It is given by : r = mv/qB where,
m = mass of the charged particle
v = velocity of the charged particle
q = charge of the charged particle
B = magnetic field strength
On substituting the given values, we get : r = mv/qB = (9.11 × 10^-31 kg) × (72 × 10^3 m/s)/(1.6 × 10^-19 C) × (8.57 T)
r = 4.22 × 10^-4 m
(b) Pitch of the path : The pitch of the path is given by,P = 2πr
Since we have already found the value of 'r', we can directly substitute it to get,
P = 2πr = 2π × 4.22 × 10^-4 m = 2.65 × 10^-3 m or 2.65 mm
(c) To an observer looking into the magnetic field region from the entrance point of the electron, the electron would appear to spiral clockwise as it moves.
Thus, the correct options are :
(a) 4.22 × 10^-4 m
(b) 2.65 × 10^-3 m
(c) Clockwise
To learn more about magnetic field strength :
https://brainly.com/question/14411049
#SPJ11
9) Calculating with Faradays law and magnetic flux A flat circular coil of wire has a radius of 0.18 m and is made of 75 turns of wire. The coil is lying flat on a level surface and is entirely within a uniform magnetic field with a magnitude of 0.55 T, pointing straight into the paper. The magnetic field is then completely removed over a time duration of 0.050 s. Calculate the average magnitude of the induced EMF during this time duration. 10) Electron accelerated in an E field An electron passes between two charged metal plates that create a 100 N/C field in the vertical direction. The initial velocity is purely horizontal at 3.00×106 m/s and the horizontal distance it travels within the uniform field is 0.040 m. What is the vertical component of its final velocity?
The vertical component of the final velocity of the electron is - 2.33963×10^6 m/s.
the formula to calculate the magnitude of induced EMF is given as:
ε=−NΔΦ/Δtwhere,ε is the magnitude of induced EMF,N is the number of turns in the coil,ΔΦ is the change in magnetic flux over time, andΔt is the time duration.
So, first, let us calculate the change in magnetic flux over time.Since the magnetic field is uniform, the magnetic flux through the coil can be given as:
Φ=B*Awhere,B is the magnetic field andA is the area of the coil.
In this case, the area of the coil can be given as:
A=π*r²where,r is the radius of the coil.
So,A=π*(0.18 m)²=0.032184 m²And, the magnetic flux through the coil can be given as:Φ=B*A=0.55 T * 0.032184 m² = 0.0177012 Wb
Now, the magnetic field is completely removed over a time duration of 0.050 s. Hence, the change in magnetic flux over time can be given as:
ΔΦ/Δt= (0 - 0.0177012 Wb) / 0.050 s= - 0.354024 V
And, since there are 75 turns in the coil, the magnitude of induced EMF can be given as:
ε=−NΔΦ/Δt= - 75 * (- 0.354024 V)= 26.5518 V
So, the average magnitude of the induced EMF during this time duration is 26.5518 V.
10) Electron accelerated in an E fieldThe formula to calculate the vertical component of the final velocity of an electron accelerated in an E field is given as:
vfy = v0y + ayt
where,vfy is the vertical component of the final velocity,v0y is the vertical component of the initial velocity,ay is the acceleration in the y direction, andt is the time taken.In this case, the electron passes between two charged metal plates that create a 100 N/C field in the vertical direction.
The initial velocity is purely horizontal at 3.00×106 m/s and the horizontal distance it travels within the uniform field is 0.040 m.So, the time taken by the electron can be given as:t = d/v0xt= 0.040 m / 3.00×106 m/s= 1.33333×10^-8 sNow, the acceleration in the y direction can be given as:ay = qE/my
where,q is the charge of the electron,E is the electric field, andmy is the mass of the electron.In this case,q = -1.6×10^-19 C, E = 100 N/C, andmy = 9.11×10^-31 kgSo,ay = qE/my= (- 1.6×10^-19 C * 100 N/C) / 9.11×10^-31 kg= - 1.7547×10^14 m/s²
And, since the initial velocity is purely horizontal, the vertical component of the initial velocity is zero.
So,v0y = 0So, the vertical component of the final velocity of the electron can be given as:vfy = v0y + ayt= 0 + (- 1.7547×10^14 m/s² * 1.33333×10^-8 s)= - 2.33963×10^6 m/s
Therefore, the vertical component of the final velocity of the electron is - 2.33963×10^6 m/s.
Learn more about velocity with the given link,
https://brainly.com/question/80295
#SPJ11
In an electrically heated home, the temperature of the ground in contact with a concrete basement wall is 11.2°C. The temperature at the inside surface of the wall is 19.4°C. The wall is 0.20 m thick and has an area of 8.6 m2. Assume that one kilowatt hour of electrical energy costs $0.10. How many hours are required for one dollar's worth of energy to be conducted through the wall?
To determine the time required for one dollar's worth of energy to be conducted through the wall, we need additional information: the thermal conductivity of the concrete wall (k).
To determine the time required for one dollar's worth of energy to be conducted through the wall, we need to calculate the heat transfer rate through the wall and then divide the cost of one kilowatt hour by the heat transfer rate.
The heat transfer rate can be determined using the equation:
Q = k * A * (T2 - T1) / L
where Q is the heat transfer rate, k is the thermal conductivity of the wall, A is the area of the wall, T2 is the temperature at the inside surface, T1 is the temperature at the outside surface (ground temperature), and L is the thickness of the wall.
Once we have the heat transfer rate, we can divide the cost of one kilowatt hour (0.10 dollars) by the heat transfer rate to find the number of hours required for one dollar's worth of energy to be conducted through the wall.
Please note that the value of thermal conductivity (k) for the concrete wall is required to perform the calculation.
To know more about conductivity , click here:
brainly.com/question/31201773
#SPJ11
A positive charge moves in the x−y plane with velocity v=(1/2)i^−(1/2)j^ in a B that is directed along the negative y axis. The magnetic force on the charge points in which direction?
Given information:A positive charge moves in the x−y plane with velocity v=(1/2)i^−(1/2)j^ in a B that is directed along the negative y axis.We are to determine the direction of magnetic force on the charge.In order to find the direction of magnetic force on the charge, we need to apply right-hand rule.
We know that the magnetic force on a moving charge is given by the following formula:F=q(v×B)Here,F = Magnetic force on the chargeq = Charge on the chargev = Velocity of the chargeB = Magnetic fieldIn the given question, we are given that a positive charge moves in the x−y plane with velocity v=(1/2)i^−(1/2)j^ in a B that is directed along the negative y axis.Let's calculate the value of magnetic force on the charge using the above formula:F=q(v×B)Where,F = ?q = +ve charge v = (1/2)i^−(1/2)j^B = -ve y-axis= -j^The cross product of two vectors is a vector which is perpendicular to both the given vectors. Therefore,v × B= (1/2)i^ x (-j^) - (-1/2j^ x (-j^))= (1/2)k^ + 0= (1/2)k^. Therefore,F = q(v×B)= q(1/2)k^. Now, as the charge is positive, the magnetic force acting on the charge will be perpendicular to the plane containing velocity and magnetic field. The direction of magnetic force can be found using the right-hand rule.
Thus, the direction of magnetic force acting on the charge will be perpendicular to the plane containing velocity and magnetic field.
To know more about right-hand rule visit:
brainly.com/question/30641867
#SPJ11
A guitar string with mass density p - 2.4 x 10-4 kg/m is L - 1.08 m long on the guitar. The string is tuned by adjusting the tension to T. 121.9 N. 1) With what speed do waves on the string travet? m/
The waves on the guitar string travel at approximately 1391.6 m/s.
The speed of waves on a string can be calculated using the wave equation:
[tex]v = √(T/μ),[/tex]
where v is the wave speed, T is the tension in the string, and μ is the mass density of the string.
In this case, the tension T is given as 102.2 N, and the mass density μ is given as [tex]2.3 × 10^(-4) kg/m.[/tex]
Plugging these values into the equation, we can calculate the wave speed:
[tex]v = √(102.2 N / 2.3 × 10^(-4) kg/m)[/tex]
≈ √(445652.17 m^2/s^2 / 2.3 × 10^(-4) kg/m)
≈ √(1937601.69 m^2/s^2/kg)
≈ 1391.6 m/s.
To know more about waves refer here
brainly.com/question/29334933#
#SPJ4
In a box defined by the potential the eigenenergies and eigenfunctions are Un (x) Va sin n. 2a for even n Un (x)=√√√/1/0 Cos 2a; for odd n A particle in the box is in a state (x) = N sin 2 [√6-4i sin 5+2 cos bra 67x (a) Determine the normalization constant (b) Calculate the probability of each eigenstate and write down the corresponding eigenenergy of each state with non-zero probability. (c) What is the expected average value of energy? V (x) = En = 0; a< x
A. Normalization constant N = (2/√3)
B. Eigenenergy of nth state = En = (n²π²ħ²)/2ma²
C. the expected average value of energy is (28π²ħ²)/(3ma²).
(a). In a box defined by the potential, the eigenenergies and eigenfunctions are:
Un(x) = Va sin(nπx/2a) for even n,
Un(x) = √(2/2a) cos(nπx/2a) for odd n.
A particle in the box is in a state:
ψ(x) = N sin^2(√6-4i sin(5x) + 2 cos(67x))
To calculate the normalization constant, use the following relation:
∫|ψ(x)|^2 dx = 1
Where ψ(x) = N sin^2(√6-4i sin(5x) + 2 cos(67x))
N is the normalization constant.
|N|^2 ∫sin^2(√6-4i sin(5x)+2 cos(67x)) dx = 1
∫[1-cos(2(√6-4i sin(5x)+2 cos(67x)))]dx = 1
∫1dx - ∫(cos(2(√6-4i sin(5x)+2 cos(67x)))) dx = 1
x - (1/2)(sin(2(√6-4i sin(5x)+2 cos(67x))))|√6-4i sin(5x)+2 cos(67x) = a| = x - (1/2)sin(2a)0 to 2a = 1
∫2a = x - (1/2)sin(2a) = 1
x = 1 + (1/2)sin(2a)
Since the wave function is symmetric, we only need to integrate over the range 0 to a.
Normalization constant N = (2/√3)
(b) The probability of each eigenstate is given by |cn|^2.
Where cn is the coefficient of the nth eigenfunction in the expansion of the wave function.
We have,
ψ(x) = N sin^2(√6-4i sin(5x)+2 cos(67x) = N[(1/√3)sin(2x) - (2/√6)sin(4x) + (1/√3)sin(6x)]
Comparing with the given form, we get,
c1 = (1/√3)
c2 = - (2/√6)
c3 = (1/√3)
Probability of nth eigenstate = |cn|^2
Therefore,
Probability of first eigenstate (n = 1) = |c1|^2 = (1/3)
Probability of second eigenstate (n = 2) = |c2|^2 = (2/3)
Probability of third eigenstate (n = 3) = |c3|^2 = (1/3)
Eigenenergy of nth state = En = (n²π²ħ²)/2ma²
For even n, Un(x) = √(2/2a) cos(nπx/2a)
∴ n = 2, 4, 6, ...
For odd n, Un(x) = Va sin(nπx/2a)
∴ n = 1, 3, 5, ...
(c) The expected average value of energy is given by,
∫ψ(x)V(x)ψ(x)dx = ∫|ψ(x)|²En dx
For V(x) = E0 = 0, a < x < a
We have,
En = (n²π²ħ²)/2ma²
En for even n = 2, 4, 6...
En for odd n = 1, 3, 5...
We have already calculated |ψ(x)|² and En.
∴ ∫|ψ(x)|²En dx = ∑|cn|²En
∫(1/√3)sin²(2x)dx - (2/√6)sin²(4x)dx + (1/√3)sin²(6x)dx
= [(2/3)(π²ħ²)/(2ma²)] + [(8/3)(π²ħ²)/(2ma²)] + [(18/3)(π²ħ²)/(2ma²)]
= [(2+8+18)π²ħ²]/[3(2ma²)]
= (28π²ħ²)/(3ma²)
Hence, the expected average value of energy is (28π²ħ²)/(3ma²).
To learn more about constant, refer below:
https://brainly.com/question/31730278
#SPJ11
A puck moves on a horizontal air table. It is attached to a string that passes through a hole in the center of the table. As the puck rotates about the hole, the string is pulled downward very slowly and shortens the radius of rotation, so the puck gradually spirals in towards the center. By what factor will the puck's angular speed have changed when the string's length has decreased to one-third of its original length?
The puck's angular speed will increase by a factor of 3 when the string's length has decreased to one-third of its original length.
1. When the string is pulled downward, the puck's radius of rotation decreases, causing it to spiral in towards the center.
2. As the puck moves closer to the center, its moment of inertia decreases due to the shorter distance from the center of rotation.
3. According to the conservation of angular momentum, the product of moment of inertia and angular speed remains constant unless an external torque acts on the system.
4. Initially, the puck's moment of inertia is I₁ and its angular speed is ω₁.
5. When the string's length decreases to one-third of its original length, the puck's moment of inertia reduces to 1/9 of its initial value (I₁/9), assuming the puck's mass remains constant.
6. To maintain the conservation of angular momentum, the angular speed must increase by a factor of 9 to compensate for the decrease in moment of inertia.
7. Therefore, the puck's angular speed will increase by a factor of 3 (9/3) when the string's length has decreased to one-third of its original length.
To know more about angular speed click here:
https://brainly.com/question/29058152
#SPJ11