Explanation:
It is given that,
Resistance, R = 20 ohms
Voltage of the battery, V = 10 V
We can find current flowing through the circuit using Ohm's law as follows :
V = IR
\begin{gathered}I=\dfrac{V}{R}\\\\I=\dfrac{10}{20}\\\\I=0.5\ A\end{gathered}I=RVI=2010I=0.5 A
It can be seen from the Ohm's law, that the current is directly proportional to the voltage. It means that if the battery is replaced by a battery that provides a larger voltage, the current through the circuit will be more than 0.5 A i.e. it increases
what are adaptations needed for animals to survive on grassland?
Answer:
short teeth, short hair, camoflauge, and speed
Explanation:
Answer:
speed and awareness
Explanation:
Water is used to fill hot water bottles for
warming beds. A hot block of concrete
wrapped in a cloth can also be used.
Why are these two materials the best for
warming something up?
Worth 25 points!!!
Answer:
Because they both hold the heat
40. What is the acceleration of a 10 kg object if a force of 3 N is applied to it?
Potential energy is due to_blank_?
Answer:
To summarize, potential energy is the energy that is stored in an object due to its position relative to some zero position. An object possesses gravitational potential energy if it is positioned at a height above (or below) the zero height.
Explanation:
if it helped plz mark brainiest
PLEASEEEEEE HELPPPPPPP MEEEEEEEE!!!!!!!!!!!!!
Answer:
[tex]2 \\ because \\ 2 - 2 = 0 \\ 5 - 5 = 0[/tex]
the position of an ant and a spider in a room are A(2,3,5) and B(6,0,8) determine the distance
Answer:
[tex] |d| = \sqrt{ {(x_{2} -x_{1})}^{2} + {(y_{2} -y_{1})}^{2} + {(z_{2} -z_{1})}^{2}} \\ = \sqrt{ {(6 - 2)}^{2} + {(3 - 0)}^{2} +{(5 - 8)}^{2} } \\ = \sqrt{16 + 9 + 9} \\ = \sqrt{34} [/tex]
The position of an ant and a spider in a room are A(2,3,5) and B(6,0,8) the distance between ant and spider is 5.83 m.
What is Distance between two points?The distance formula states that the distance between two points in xyz-space is the square root of the sum of the squares of the differences between corresponding coordinates A( [tex]x_{1}[/tex] , [tex]y_{1}[/tex] , [tex]z_{1}[/tex] ) and B( [tex]x_{2}[/tex] , [tex]y_{2}[/tex] ,[tex]z_{2}[/tex]),
AB² = ([tex]x_{2}[/tex] - [tex]x_{1}[/tex])² + ([tex]y_{2}[/tex] - [tex]y_{1}[/tex])² + ( [tex]z_{2}[/tex] - [tex]z_{1}[/tex] )²
In reality, the Pythagorean Theorem is nothing more than the distance formula. Draw a right triangle using the segment AB as its hypotenuse in order to get the distance AB between points A( [tex]x_{1}[/tex] , [tex]y_{1}[/tex] ) and B( [tex]x_{2}[/tex] , [tex]y_{2}[/tex] ).
Given that in the question two points are A(2,3,5) and B(6,0,8), so the distance between them is
AB² = ([tex]x_{2}[/tex] - [tex]x_{1}[/tex])² + ([tex]y_{2}[/tex] - [tex]y_{1}[/tex])² + ( [tex]z_{2}[/tex] - [tex]z_{1}[/tex] )²
AB² = 4² + 3² + 3²
AB² = 34
AB = 5.83 m
Position of an ant and a spider in a room are A(2,3,5) and B(6,0,8) the distance between ant and spider is 5.83 m.
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PLEASEEEEE HELPPPPPPPPP ASAPP
Answer:
Its the last one.
Explanation:
Massive objects such as earth generate gravity, and the moon orbits the earth as it is smaller and close enough.
Anne pushed a cart by 12 N. How far did the cart move if the work done was 9 J?
[tex]\\ \sf\longmapsto W=Fd[/tex]
[tex]\\ \sf\longmapsto d=\dfrac{W}{F}[/tex]
[tex]\\ \sf\longmapsto d=\dfrac{9}{12}=0.72m[/tex]
Answer:
Anne pushed a cart by 12 N.
● Force = 12 N
Work done is 9 J
● Work = 9 J
=> Work = Force × distance
[tex]=> distance = \frac{work}{force} [/tex]
[tex]=> distance = \frac{9}{2} [/tex]
[tex]=> distance = 0.72m[/tex]
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Suppose that John lives on a square block that is 180 yards per side, and in the evenings, he walks with his dog around the block for a little exercise.
A) If John walks once around the block, what distance does he travel?
B) If John walks once around the block, what is his final displacement?
Answer:
It's A
Explanation:
Although I'm not sure about the second one, I'm sure the first one is A
A machine has an efficiency of 15% . If the energy inputs is 300 joules, how much useful energy is generated
Answer:
you made with your performance, and then consider whether you would do anything differently if yo
Explanation:
The useful energy generated by the machine having an efficiency of 15% and an energy input of 300 J is 45 J
From the question given above, the following data were obtained:Efficiency = 15% = 0.15
Work input = 300 J
Work output =?The useful energy generated (i.e work output) by the machine can be obtained as follow:
[tex]Efficiency = \frac{workout}{workin} * 100\\\\0.15 = \frac{Workout}{300}[/tex]
Cross multiply
Work output = 0.15 × 300
Work output = 45 JTherefore, the useful energy generated by the machine is 45 J
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A spring scale is used to measure the weight of various objects. When a 100 g empty glass bottle is placed on the scale, the spring stretches down 1.8 cm. How much water should be poured into the glass bottle to stretch the spring down by 2.7 cm?
A: 44 mL
B: 50 mL
C: 33 mL
D: 150 mL
50 mL of water have to poured to the glass bottle of 100 g to increase the stretching of the spring from 1.8 cm to 2.7 cm.
What is spring stretching?A spring can hang when it loads a weight. The stretching of spring is the change in length of the spring end from its initial length. Spring balance works with the principle of Hooks law.
The stretching is made by the elasticity of the spring which make it in a wave like motion.
Given that the glass bottle with 100 g weight when loaded on the spring scale, it will stretch down to 1.8 cm. Then the weight required to make a stretch of 2.7 cm is calculated as follows:
weight required = (100 g × 1.8 cm) /2.7 cm
= 150 g.
A total of 150 g is needed to stretch into 2.7 cm. Thus we have to add 50 g of water to the glass weighing 100 g . 50 g is equivalent to 50 ml, since density of water is 1 g/L.
Hence, 50 ml of water should be poured to the glass.
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a stone is dropped down an empty mine shaft. it takes 3 seconds to reach the bottom. assuming that the stone falls from rest and accelerates at 10m/s^2, calculate.
a) the maximum speed reached by the stone before hitting the bottom.
b) the average speed of the stone in flight.
c) the depth of the mine shaft.
Answer:
I think A. I had a similar question
Explanation:
31) what is the energy required to change 20g of copper, whose specific heat is 0.39j/gc,
change from 20 to 40 degrees?
Explanation:
given :
m = 20 g
sh = 0.39 J/g°C
∆T = 40-20 = 20°C
Find the Energy!
solution :
E =m. sh. ∆T
= 20 × 0.39 × 20
= 156 J
So, energy required is
Energy = mass*sh*∆T
Energy = 20g*0.39j/g°c*20°
Energy = 156joule✅
~Physics#1
I am completely braindead on how to calculate the time first.
A flowerpot falls from a window sill 31.3m from a sidewalk. What is the velocity of the flowerpot when it hits the ground? (hint: Use d=1/2at^2 to find "t" first, then find velocity using v=at. Remember, ay= -9.8 m/s2).
24.8 m/s
Explanation:
You don't have to solve for time first. You can use the equation below to solve for the velocity before impact:
[tex]v_y^2 = v_{0y}^2 + 2a_yy[/tex]
We know that [tex]v_{0y} = 0[/tex] so the equation above becomes
[tex]v_y^2 = 2a_yy \Rightarrow v_y = \sqrt{-2a_yy}[/tex]
Plugging in the numbers, we get
[tex]v_y = \sqrt{-2(-9.8\:\text{m/s}^2)(31.3\:\text{m})}[/tex]
[tex]\:\:\:\:\:=24.8\:\text{m/s}[/tex]
METHOD 2:
If you insist on using that equation for d, we can do that too. So solving for t from the equation for d. we get
[tex]t = \sqrt{\dfrac{2d}{g}} = \sqrt{\dfrac{2(31.3\:\text{m})}{9.8\:\text{m/s}^2}}[/tex]
[tex]\:\:\:\:= 2.53\:\text{s}[/tex]
So using the equation [tex]v_y = gt,[/tex] we get
[tex]v_y = (9.8\:\text{m/s}^2)(2.53\:\text{s}) = 24.8\:\text{m/s}[/tex]
So you get the same result regardless of the method you use.
help me plzzz
The punter on a football team tries to kick a football so that it stays in the air for a long "hang
time". If the ball is kicked with an initial velocity of 30 m/s at an angle of 60 degrees above the
ground.
a. Calculate the "hang time".
b. How far does the ball go in the horizontal direction?
c. What is the maximum altitude (height) the ball reaches?
first resolve the initial velocity of the ball into two components
1)one parallel to ground(u)
2)another perpendicular to ground(v)
call the initial velocity=p=25.4 m/s at 58.0° deg to ground
so the horizontal component of velocity=25.4cos58=13.46 m/s
so the vertical component of velocity=25.4sin58=21.54 m/s
we have nothing to do with the horizontal component of velocity as it plays no part in the hang time
only vertical component of velocity determines the hang time
hang time=2*(vertical component of velocity)/(acceleration due to gravity)
==>hang time=2*21.54/9.8=4.39 s
==>hang time =4.39 s
If I'm wrong please let me know, thank you.
Kelvin is a unit of temperature, whereas ampere is a unit of current.
True or False
Answer:
Kelvin is a unit of temperature, whereas ampere is a unit of current.
True or False
Explanation:
true
An engine raises 120kg of water through a height of 40m in 30s.What is the power of the engine take gravity to be = 10m/s.
Answer:
1600 W
Explanation:
Power is the product of force and distance, divided by time.
P = (120 kg)(10 m/s²)(40 m)/(30 s) = 1600 kg·m²/s³ = 1600 W
A particular car can go from rest to 90 kmh in 10 seconds. What is its
acceleration. (Show your calculation
Answer:
Im sorry i dont know But thank you for the points
the velocity of an object must include these two things ________ and _________
will give brainlest
Answer:
The velocity of an object must include these two things displacement and time.
Explanation:
Hope this helps you. Have a nice day^_^
Please mark as brainliest. It helps a lot. :)
Si la fuerza de repulsión entre dos cargas es 18 × 1013
Answer:
Explanation:
F = kQq/r²
r = √(kQq/F)
a) r = √(8.899(10⁹)(8)(4) / 18(10¹³)) = 0.0397749... m
r = 40 mm
b) r = √(8.899(10⁹)(12)(3) / 18(10¹³)) = 0.0421876... m
r = 42 mm
Which component that makes up the bulk of all galaxies?
A. gas
B. dark matter
C. dust
D. stars
Answer: B Dark matter
We have that for the Question "Which component that makes up the bulk of all galaxies? A. gas B. dark matter C. dust D. stars" it can be said that Invariably the dark matter makes up the bulk of all galaxies
Option B
From the question we are told
Which component that makes up the bulk of all galaxies?
A. gas
B. dark matter
C. dust
D. stars
Generally
the Galaxy have a mass of about 2*10^{12} mass of sun
This is made up of 95% of dark matter
Therefore
Invariably the dark matter makes up the bulk of all galaxies
Option B
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if 2 magnets were forced together vertically on the same poles and suddenly released, how high would the top magnet travel? The magnets are disc-shaped with a circumference of 6.5" and a mass of 8 lbs, the combined force of the magnets is 13,200lbs.
a father and his son are racing down a mountain. if they're traveling at the same velocity who has more kinetic energy
Answer:
I think it's the son
Explanation:
bcs he might love it
What is the magnitude of the momentum of a 1000 kg car traveling
at 5 m/s?
Answer:
5000 kg.m/sExplanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question
mass = 1000 kg
velocity = 5 m/s
We have
momentum = 1000 × 5 = 5000
We have the final answer as
5000 kg.m/sHope this helps you
3)(20pts) Un barco invasor se encuentra a 560m de un puerto de defensa, el puerto tiene cañones que
disparan con una velocidad de 82m/s. a) ¿Qué ángulo debe de tener el barco para poder golpear el
barco invasor? b) ¿Cuál es el tiempo de vuelo de las balas disparadas por el cañón utilizando el ángulo
de la respuesta "a"? c) ¿Qué tan lejos debe alejarse el barco invasor de la costa para lograr estar fuera
del alcance de los cañones?
a) Las balas de cañon disparadas desde el puerto deben tener una ángulo de 27.39° para que puedan impactar al barco, con una velocidad inicial de 82 m/s.
b) El tiempo de vuelo de las balas de cañon para alcanzar al barco que está a 560 m de distancia es de 7.69 s.
c) Sabiendo que el ángulo calculado en el inciso a) es para una distancia de 560 m, el barco debe estar a una distancia mayor para que las balas no lo alcancen.
a)
Podemos usar las ecuaciones de tiro parabólico para encontrar el ángulo que permita derribar al barco invasor.
[tex]x=\frac{v_{i}^{2}sin(2\alpha)}{g}[/tex] (1)
Donde:
v(i) es la velocidad inicial del cañon (82 m/s)α es el ángulo de tirog es la gravedad (9.81 m/s²)x es el desplazamiento total (560 m)Lo que debemos hacer es depejar α de la ecuación 1
[tex]sin(2\alpha)=\frac{xg}{v_{i}^{2}}[/tex]
[tex]sin(2\alpha)=\frac{560*9.81}{82^{2}}[/tex]
[tex]sin(2\alpha)=0.82[/tex]
[tex]\alpha=\frac{sin^{-1}(0.82)}{2}[/tex]
[tex]\alpha=27.39^{\circ}[/tex]
Por lo tanto, el ángulo para que el cañón impacte en el barco es de 27.39 °.
b)
Sabemos que la componente de la velocidad en el eje x es constante, así que podemo usar la siguiente ecuación.
[tex]v_{x}=\frac{x}{t}[/tex]
La componente x de la velocidad es V(x) = V(i)cos(α) y sabiendo la distancia total de 560 m, el tiempo será:
[tex]v_{i}cos(\alpha)=\frac{x}{t}[/tex]
[tex]t=\frac{x}{v_{i}cos(\alpha)}[/tex]
[tex]t=\frac{560}{82cos(27.39)}[/tex]
[tex]t=7.69\: s[/tex]
El tiempo total de vuelo de las balas de cañon es de 7.69 s.
c)
Sabemos que el ángulo calculado en el inciso a) es de 27.39 °, y ese valor fue calcualdo para una distancia de 560 m, por lo tanto el barco debe estar a una distancia mayor que esa para que las balas no lo alcancen.
Puedes encontrar más información sobre tiro parabólico aquí:
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Espero te haya sido de ayuda!
Draw a free body diagram of an 6.4 kg ball falling towards earth. Calculate the weight of the ball.
Diagram:-
[tex]\setlength{\unitlength}{2mm}\begin{picture}(0,0)\thicklines\put(3,6){\circle{3}}\put(2.9,4.5){\vector(0,-3){2cm}}\put(-3.9,-10){\line(3,0){3cm}}\multiput(-3.5,-10)(0.8,0){18}{\line(1,-2){2mm}}\put(-3.7,0){$\sf\footnotesize 9.8 ms^{-2}$}\put(6,0){\vector(0,3){1.2cm}}\put(5.5,6){\line(3,0){2mm}}\put(5,-1.2){\sf\footnotesize height}\put(6,-2){\vector(0,-3){1.2cm}}\put(5.5,-8){\line(1,0){2mm}}\end{picture}[/tex]
Here
m=6.4kg[tex]\\ \sf\longmapsto Weight=mg[/tex]
[tex]\\ \sf\longmapsto Weight=6.4(9.8)[/tex]
[tex]\\ \sf\longmapsto weight=62.72N[/tex]
A 500 kg airplane wing is hanging on a rope from the ceiling. What is the tension force being supplied by the rope?
a.5000
b.2500
c.250
d.500
Answer:
a. 5000 N
Explanation:
If gravity is 10 m/s² and the wing is motionless.
F = ma = 500(10) = 5000 N
Please explain tyyy!
Answer:
electromagnetic spectrum is the range of frequencies of electromagnetic radiation and their respective wavelengths and photon energies.
Explanation:
brainliest me
Answer:
The electromagnetic spectrum is the range of frequencies (the spectrum) of electromagnetic radiation and their respective wavelengths and photon energies.
ok write it
please answer me!!! asappp
Answer:
omg this is hard
Explanation:
Yes it is lol
label the longitudinal wave
Answer:
???
Explanation: