A 200N lamp is suspended from three cables as shown in the figure below. Find the tensions in each of the three cables.

Answers

Answer 1

Answer:

66.6N

Explanation:

Step one;

given data

the mass of the lamp = 200N

we are told that it is suspended by 3 cables.

Now we know that the weight will be distributed equally on the cables

Step two:

so, let the tension in each cable be T

T+T+T= 200

3T=200

T=200/3

T=66.6N

The tenion on each cable is 66.6N


Related Questions

What is the main organ of the circulatory system?

veins

arteries

heart

capillaries

Answers

It is the heart

if not im sorry

Question 18 of 20
Which situation results in the least attraction between two magnets?
A. The south pole of one magnet is near the south pole of the other
magnet
B. The north pole of one magnet is near the south pole of the other
magnet
C. The north pole of one magnet is far away from the north pole of
the other magnet
D. The north pole of one magnet is far away from the south pole of
the other magnet.

Answers

Answer:D

Explanation:

Answer:

Explanation: the answer is D.

A 6 kg bowling ball is on top of a building. It has 2,352 J of potential energy. What is the height of
the building?

Answers

Hello!

[tex]\large\boxed{ h = 40m}[/tex]

Use the formula below to solve:

[tex]\text{ Potential energy} = mgh[/tex]

Where:

m = mass of object (kg)

g = acceleration due to gravity (9.8 m/s²)

h = height of the building (m)

We are given the potential energy, mass, and gravity, so plug in those values into the equation to solve for the height:

[tex]2352 = 6 * 9.8 * h\\\\2352 = 58.8h\\\\2352/58.8 = 58.8h / 58.8\\\\h = 40 m[/tex]

A wheel rolling on a horizontal surface with an angular speed of 2.5 rad/s gets on a ramp and rolls down the ramp with a constant angular acceleration of 2.0 rad/s2. If it takes 11.5 us to reach the bottom of the ramp, what is the final angular speed of the wheel at the bottom

Answers

Answer:

the final angular speed of the wheel at the bottom is 25.5 rad/s

Explanation:

The computation of the final angular speed of the wheel at the bottom is as follows:

As we know that

[tex]W_f = W_{in} + \alpha t\\\\= 2.5 + (2 \times 11.5)\\\\= 2.5 + 23\\\\= 25.5 rad/s[/tex]

Hence, the final angular speed of the wheel at the bottom is 25.5 rad/s

We simply applied the above formula so that the final angular speed could come

An investigation has been completed similar to the one on latent heat of fusion, where steam is bubbled through a container of water. Steam condenses and the lost energy heats the water and container. Use the following data to answer the question below:
Mass of the aluminum container 50 g
Mass of the container and water 250 g
Mass of the water 200 g
Initial temperature of the container and water 20°C
Temperature of the steam 100°C
Final temperature of the container, water, and condensed steam 50°C
Mass of the container, water, and condensed steam 261 g
Mass of the steam 11 g Specific heat of aluminum 0.22 cal/g°C
Given the data above, determine the total heat energy gained by the container and water.

Answers

Answer:

[tex]Q_a=330 cal[/tex]

[tex]Q_w=6000cal[/tex]

Explanation:

From the question we are told that

Mass of the aluminum container 50 g

Mass of the container and water 250 g

Mass of the water 200 g

Initial temperature of the container and water 20°C

Temperature of the steam 100°C

Final temperature of the container, water, and condensed steam 50°C

Mass of the container, water, and condensed steam 261 g

Mass of the steam 11 g Specific heat of aluminum 0.22 cal/g°C

a) Heat energy on container

Generally the formula for mathematically solving heat gain

      [tex]Q_c=M_c *C_c*( \triangle T)[/tex]

Therefore imputing variables we have

      [tex]Q_a=50g *0.22*50-20[/tex]  

      [tex]Q_a=330 cal[/tex]

b) Heat energy on water

Generally the formula for mathematically solving heat gain

       [tex]Q_w=M_w *C_w*( \triangle T)[/tex]

Therefore imputing variables we have

       [tex]Q_w=200 *1* 50-204[/tex]

       [tex]Q_w=6000cal[/tex]

baseball player hits a line drive estimated to have traveled 145 meters the ball leaves the bat with a horizontal velocity of 40.0 m/s . how much time was the ball in the air

Answers

Answer:

3.63 s

Explanation:

Since distance d = vt where v = velocity and t = time taken to cover the distance.

Now, the baseball traveled a distance of d = 145 m with a horizontal velocity of 40.0 m/s.

So, making t subject of the formula,

t = d/v

Substituting the values of d and v we have

t = 145 m/40.0 m/s

= 3.625 s

≅ 3.63 s

So the time the ball was in the air is 3.63 s

A tennis ball (m=0.060 kg) is moving horizontally at 20 m/s toward a tennis player who hits it straight back at 26 m/s. What is the change in momentum (in kg m/s) delivered to the tennis ball? 20 m/s 26 m/s
A. 0.36
B. 12.2
C. 1.84
D. 2.76

Answers

Answer:

0.36 kg-m/s

Explanation:

Given that,

Mass of a ball, m = 0.06 kg

Initial velocity of the ball, u = 20 m/s

Final velocity of the ball, v = 26 m/s

We need to find the change in momentum of the tennis ball. It is equal to the final momentum minus initial momentum

[tex]\Delta p=m(v-u)\\\\=0.06\times (26-20)\\\\=0.36\ kg-m/s[/tex]

So, the change in momentum of the ball is 0.36 kg-m/s.

Three wheels each of radius 1 have their centers at respective verticies of an equilateral triangle of side length 4. A belt is wrapped continuously around the wheels. Find the length of the belt.

Answers

Answer:

L  = 6 * ( π + 1 )

Explanation:

The side of the equilateral triangle is  4, and each one of the circles is of radius 1. Then

Triangle vertex   A  B  and C

Trajectory of the belt, beginning in vertex A

1.-First circle  A  one turn

L₁  = 2*π*1   = 2*π

2.-Length between the circle A and B

L₂  = 2

3.- To wrap this circle we need to wrap the circle and to run the belt through the radius twice. The firs over the side AB and the second over the side BC, therefore

L₃ = 2*π*1 + 2*(1)

L₃ = 2*π + 2

4.-Length between two nearest points of circles B and C is 2 and length of the circle in C is 2*π*1. Then

L₄  = 2 + 2*π

Total length of the belt  is:

L  =  L₁ + L₂ + L₃ + L₄

L = 2*π + 2 + (2*π + 2 ) + ( 2 + 2*π )

L  = 6*π + 6

L  = 6 * ( π + 1 )

1. Add 17.35 g, 25.6 g and 8.498 g. chaper 1 physical quantity 11class .physic​

Answers

51.448 g is the required answer!

What us the difference in the ways objects move at a speed of a car and an object mkvinf close to the speed of light?​

Answers

Answer:

The difference is in who or what is observing the speed.

Explanation:

Giving that speed is relative between the objects and the reference point from which it is being observed.

It is concluded that speed alone has no direct effect on a moving object, hence it is just a determining unit for the difference in distance between two objects.

Therefore, in this case, the difference is in who or what is observing the speed.

After a collision between two different massed objects; the larger objects accelerate at a faster rate than the smaller object? If false please explain
why

Answers

Answer: Things continue doing what they are doing unless a force is applied to it. Objects have a natural tendency to resist change. This is INERTIA. Heavier objects (objects with more mass) are more difficult to move and stop. Heavier objects (greater mass) resist change more than lighter objects, so true

Explanation:

Pushing a bicycle or a Cadillac, or stopping them once moving. The more massive the object (more inertia) the harder it is to start or stop. The Cadillac has more of a tendency to stay stationary (or continue moving), and resist a change in motion than a bicycle.

In a perfectly inelastic one-dimensional collision between two objects, what initial condition alone is necessary so that all of the original kinetic energy of the system is gone after the collision

Answers

Answer:

The objects must have moments with the same magnitude but opposite directions.

Explanation:

The condition alone that is necessary in order to make the final kinetic energy of the system to be zero after the collision is that the objects must have moments that are the same in magnitude but have opposite directions.

which of the following is not a risk associated with using legal drugs without medical supervision

Answers

Answer:

paying too much on the black market instead of getting a prescription

Explanation:

i just took the quiz

Answer:

Paying too much on the black market instead of getting a prescription

Explanation:

The rest of the options are risks associated with using legal drugs without medical supervision.

in how many days the life cycle of honeybee complete​

Answers

Honey bees develop in four distinct life cycle phases: egg, larva, pupa, and adult. The total development time varies a bit among the three castes of bees, but the basic miraculous process is the same: 24 days for drones, 21 days for worker bees, and 16 days for queens.

If the interest of sum of money is 6 yrs in 3/8 of the principal . what is the rate of interest?​

Answers

Answer:

=6.25%

Explanation:

Simple interest can be calculated using the below formula

I=prt/100

=Interest

P=Principal

R=Rate

T=Time

T=6 yrs

R=3/8

Making R subject of the formula

R=(I ×100)/PT

Substitute the values

=(3/2 P×100)/P×6

The "P" in the numerator cancelled out the "P" in denominator then we have

=(3/2×100)/6

=6.25%

Hence the rate is 6.25%

From the gravitational law calculate the weight W (gravitational force with respect to the earth) of a 89-kg man in a spacecraft traveling in a circular orbit 261 km above the earth's surface. Express W in both (a) newtons and (b) pounds.

Answers

Answer:

[tex]W=\frac{773}{4.45}=173.76 l b f[/tex]

Explanation:

[tex]W=\frac{G \cdot m_{e} \cdot m}{(R+h)^{2}}[/tex]

The law of gravitation

[tex]G=6.673\left(10^{-11}\right) m^{3} /\left(k g \cdot s^{2}\right)[/tex]

Universal gravitational constant [S.I. units]

[tex]m_{e}=5.976\left(10^{24}\right) k g[/tex]

Mass of Earth [S.I. units]

[tex]m=89 kg[/tex]

Mass of a man in a spacecraft [S.I. units]

[tex]R=6371 \mathrm{~km}[/tex]

Earth radius [km]

Distance between man and the earth's surface

[tex]h=261 \mathrm{~km} \quad[\mathrm{~km}][/tex]

ESULT [tex]W=\frac{6.673\left(10^{-11}\right) \cdot 5.976\left(10^{24}\right) \cdot 89}{\left(6371 \cdot 10^{3}+261 \cdot 10^{3}\right)^{2}}=773.22 \mathrm{~N}[/tex]

[tex]W=\frac{773}{4.45}=173.76 l b f[/tex]

When gasoline is burned, it gives off 46,000 J/gram of heat energy. If an automobile uses 13.0 kg of gasoline per hour with an efficiency of 21%, what is the average horsepower output of the engine

Answers

Answer:

The correct output will be "46.76 h.p.".

Explanation:

The given values are:

Gasoline's energy content,

= 46000 J/g

= 4.6 x10⁷ J/kg

Fuel usage,

= 13 kg/h

= [tex]\frac{13}{3600} \ kg/s[/tex]

Fuel efficiency,

= 21%

= 0.21

Now,

The average output will be:

= [tex](Energy \ content \ of \ gasoline)\times (fuel \ usage)\times (fuel \ efficiency)[/tex]

On substituting the values, we get

= [tex]4.6\times 10^7\times (\frac{13}{3600} )\times 0.21\times (\frac{1}{746}) h.p.[/tex]

= [tex]46.76 \ h.p.[/tex]

Answer:

the  average horsepower output of the engine is 46.76 hp

Explanation:

The computation of the  average horsepower output of the engine is shown below

The output of the engine is

= (Energy content of gasoline) × (usage of the fuel ) ×  (Fuel efficiency)

As we know that

1 hp = 746 W

where,

Energy content of gasoline = 46000 J / g = 4.6  × 107 J/kg

Usage of the fuel = 13 kg / h = 13 ÷ 3600 kg/s

Fuel efficiency = 21% = 0.21

Therefore, the output of the engine is

= 4.6 ×  107 × (13 ÷ 3600) × 0.21 × (1 ÷ 746) h.p.

= 46.76 h.p.

hence, the  average horsepower output of the engine is 46.76 hp

Which of the following is an instantaneous speed?

A: All of the above
B: 80 ft/s
C. 80 yds./min
D. 80 km/hr​

Answers

Answer:

A: All of the above

Explanation:

The instantaneous speed of an object is simply the current seed of the object at any given time. The SI unit is m/S and it is a vector quantity.

Therefore, according to the given options, they all have SI units that are consistent with distance and time which makes them all an example of instantaneous speed.

How does heat from the sun affect Earth's spheres?

Answers

Answer:

1)The heat from the sun is one of the causes of rainfall.

2) It also causes thermal equilibrium on the earth's surface.

Explanation:

1) Heat from the sun heard of the water bodies, covers some to vapor which is taking up too form rains and snow.

2) Without the heat of the sun the only source of heart for the earth would be the geothermal heat (ie. the heat from within the earth). This type of heart wouldn't be enough to keep us warm because of the presence of the glaziers

Only four forces act on an object. They all have the same magnitude. Their directions are north, south, northwest, and northeast. In which direction does the object accelerate? (A) north (B) south (C) northwest (D) northeast (E) The object does not accelerate because the four forces cancel.

Answers

Answer:

the correct answer is A,   North

Explanation:

The forces are vectors so they must be added vectorially.

The magnitude of the forces is the same, but not their direction, which is why they are different.

Analyze the situation presented

We have a force towards the North and another towards the South with the same magnitude, therefore these cancel each other out

We have a force towards the Northeast and another towards the Northwest, these can be decomposed into parts, one towards the North and another on the East-West axis, this last component is canceled, but the component towards the North is added.

In summary we see that the body accelerates towards the North

the correct answer is A

A solenoid 30 cm long is wound with 250 turns of wire. The cross-sectional area of the coil is 3.5 cm^2. What is the self-inductance of the solenoid?

Answers

Answer:

The value is  [tex]L = 9.164 *10^{-5} \ H[/tex]

Explanation:

From the question we are told that

    The length of the solenoid is [tex]l = 30 \ cm = 0.3 \ m[/tex]

     The number of turns is  [tex]N = 250 \ turns[/tex]

    The cross-sectional  area is  [tex]A = 3.5 \ cm^2 = 3.5 *10^{-4} \ m^2[/tex]

Generally the self  inductance of the solenoid is  

       [tex]L = \frac{\mu_o * N^2 * A }{ l }[/tex]

Here  [tex]\mu_o[/tex] is the permeability of free space with value  [tex]\mu_o = 4\pi *10^{-7} \ T \cdot m/A[/tex]

So

       [tex]L = \frac{ 4 \pi*0^{-7} * 250^2 * 3.5 *10^{-4} }{ 0.3 }[/tex]

=>     [tex]L = 9.164 *10^{-5} \ H[/tex]

The is the sac-like structure that holds the testes.

Answers

Answer:

Scrotum

Explanation:

Answer: Scrotum

Explanation: edge

The picture shows a basic diagram of an electric motor. At top left a piece of magnet labeled N and at top right a piece labeled S. Between these a square coil of wire X sits attached to a metal rod, which runs between the 2 pieces of magnet. 2 semicircular pieces Z of metal surround the rod at its opposite end from the pieces of magnet. Wires connect to each semicircular piece at terminals Y to one pole of a battery. Blue arrows superimposed on the end of the coil away from the magnets point toward S and away from N. Which labels best complete the diagram? X: Brush Y: Armature Z: Commutator X: Commutator Y: Brush Z: Armature X: Armature Y: Commutator Z: Brush X: Armature Y: Brush Z: Commutator Mark this and return

Answers

Answer:

I know this isn't much help but its not B

Explanation:

Answer:

D

Explanation:

How could girls improve their communication skills

Answers

Answer:

////??????????????/

Explanation:

Answer:

As you go talk to her or even before you go talk to her. If that's the case however, start talking to everyone you meet both boys and girls. See, improving your communication with women is easy. Just get a few books on social skills and then go over to talk to all the ladies you see without any hidden agenda.

Explanation:

I really hope this helps your question  ^_^

Do scientific theories have math in them?

Answers

Answer:

Yes of course science has maths

An orange of mass m falls into a wagon. Assume the orange experiences upward acceleration magnitude a when it comes in contact with the wagon. What is the correct expression for the normal force magnitude F, exerted on the orange?
What is the correct expression for the normal force magnitude Fr exerted on the orange?
Consider upward as the positive direction.
Fn = m(a -g)
Fn = m(a +g)
Fn=a +g /m
Fn= m/a+g

Answers

Answer:

Explanation:

Fn = m(a + g)

An object is moving with constant speed in a
circular path. The object's centripetal
acceleration remains constant in
(1) magnitude, only
(2) direction, only
(3) both magnitude and direction
(4) neither magnitude nor direction

Answers

Answer:

both magnitude and direction

Explanation:

When an object moves in a circular path, its motion is called uniform circular motion. In this motion, the force acting on it is centripetal force and it is moving under centripetal acceleration. This type of force acts towards the centre of the circle.

In this type of motion, the speed remains constant while the velocity keeps on changing. The object's centripetal  acceleration remains constant in magnitude as well as direction.

Hence, the correct option is (3).

If an object is moving with constant speed in the circular path the object's centripetal  acceleration remains constant in both magnitude and direction

The formula for calculating the centripetal acceleration of an object is expressed as:

[tex]a =\frac{v^2}{r}[/tex]

v is the speed of the objectr is the radius of the circular path

If the speed of the object is constant, the acceleration is of the body is also constant.

Hence if an object is moving with constant speed in the circular path the object's centripetal  acceleration remains constant in both magnitude and direction

Learn more on centripetal acceleration here: https://brainly.com/question/79801

A car is stopped for a traffic signal. When the light turns green, the car accelerates, increasing its speed from 0 to 5.40 m/s in 0.792 s. What are:______

a. the magnitudes of the linear impulse
b. the average total force experienced by a 70.0-kg passenger in the car during the time the car accelerates?

Answers

Answer:

a) 378Ns

b) 477.27N

Explanation:

Impulse is the defined as the product of the applied force and time taken. This is expressed according to the formula

I = Ft = m(v-u)

m is the mass = 70kg

v is the final velocity = 5.4m/s

u is the initial velocity = 0m/s

Get the impulse

I = m(v-u)

I = 70(5.4-0)

I = 70(5.4)

I = 378Ns

b) Average total force is expressed as

F = ma (Newton's second law)

F = m(v-u)/t

F = 378/0.792

F = 477.27N

Hence the average total force experienced by a 70.0-kg passenger in the car during the time the car accelerates is 477.27N

SOMEBODY ONCE TOLD ME THE WORLD WAS GONNA ROLL ME
I AIN'T THE SHARPEST TOOL IN THE SHED~
SHE WAS LOOKING KINDA DUM WITH HER FINGER AND HER THUMB
IN THE SHAPE OF AN "L" ON HER FOREHEAD~
WELL THE YEARS START COMING AND THEY DON'T STOP COMING
FED TO THE RULES AND I HIT THE GROUND RUNNING
DIDN'T MAKE SENSE NOT TO LIVE FOR FUN
YOUR BRAIN GETS SMART BUT YOUR HEAD GETS DUM
SO MUCH TO DO, SO MUCH TO SEE--
SO WHATS WRONG WITH TAKING THE BACKSTREETS?
YOU'LL NEVER KNOW IF YOU DON'T GO
YOU'LL NEVER SHINE IF YOU DON'T GLOW.

Answers

Answer:

shrek

Explanation:

allstar

Problem 4: For a conservative force,esvoedca2beee49af123450c68a7237065a45ad885a4229cb932c3697d0b27c6328eaeovse 0N86-C1-52-40-A837-22820 If you push a wooden crate across rough ground with a force F over a distance d, what is the potential energy stored in the system due to this force

Answers

Answer:

PE = Fd

Explanation:

Potential energy is the energy possessed by a body by virtue of its position. It is expressed mathematically as:

PE = mgd

m is the mass

g is the acceleration due to gravity

d is the distance

Since Force F is expressed as the product of mass and acceleration due to gravity then, F = mg

Substitute into the formula above:

Recall that: PE = mgd

Since F = mg

PE = Fd

Hence the required expression is PE = Fd

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