Explanation:
Given that,
Mass of a soccer ball, m = 0.427 kg
Initial speed, u = 16 m/s
Final speed, v = -21.7 m/s (negative as it is in opposite direction)
(a) Impulse = change in momentum
J = 0.427 × (-21.7 -16)
J = -16.097 kg-m/s
(b) Impulse delivered to the ball by the player is in opposite direction.
(c) Time of contant, t = 0.0600 s
Average force,
J = force×time
[tex]F=\dfrac{J}{t}\\\\F=\dfrac{16.097}{0.0600 }\\\\=268.28\ N[/tex]
Hence, this is the required solution.
In a perfectly inelastic one-dimensional collision between two objects, what initial condition alone is necessary so that all of the original kinetic energy of the system is gone after the collision
Answer:
The objects must have moments with the same magnitude but opposite directions.
Explanation:
The condition alone that is necessary in order to make the final kinetic energy of the system to be zero after the collision is that the objects must have moments that are the same in magnitude but have opposite directions.
A wheel rolling on a horizontal surface with an angular speed of 2.5 rad/s gets on a ramp and rolls down the ramp with a constant angular acceleration of 2.0 rad/s2. If it takes 11.5 us to reach the bottom of the ramp, what is the final angular speed of the wheel at the bottom
Answer:
the final angular speed of the wheel at the bottom is 25.5 rad/s
Explanation:
The computation of the final angular speed of the wheel at the bottom is as follows:
As we know that
[tex]W_f = W_{in} + \alpha t\\\\= 2.5 + (2 \times 11.5)\\\\= 2.5 + 23\\\\= 25.5 rad/s[/tex]
Hence, the final angular speed of the wheel at the bottom is 25.5 rad/s
We simply applied the above formula so that the final angular speed could come
Jared is driving around a traffic circle. If he is traveling at a speed of 7.1 m/s, and it takes his 5.8 s to complete an entire loop around the traffic circle, what is the radius of the traffic circle?
A. 7.1 m
B. 6.6 m
C. 9.4 m
D. 5.6 m
Answer:
B. 6.6 m
Explanation:
Given;
speed of Jared , v = 7.1 m/s
time taken, T = 5.8 s
let the radius of the traffic circle = r
The speed of Jared is calculated as;
[tex]v = \frac{2\pi r}{T}[/tex]
Where;
v is speed of Jared
T is period of the motion
r is radius of the traffic circle
[tex]r = \frac{vT}{2\pi} \\\\r = \frac{7.1 \ \times \ 5.8}{2\pi} \\\\r = 6.55 \ m\\\\r = 6.6 \ m[/tex]
Therefore, the radius of the traffic circle is 6.6 m.
The picture shows a basic diagram of an electric motor. At top left a piece of magnet labeled N and at top right a piece labeled S. Between these a square coil of wire X sits attached to a metal rod, which runs between the 2 pieces of magnet. 2 semicircular pieces Z of metal surround the rod at its opposite end from the pieces of magnet. Wires connect to each semicircular piece at terminals Y to one pole of a battery. Blue arrows superimposed on the end of the coil away from the magnets point toward S and away from N. Which labels best complete the diagram? X: Brush Y: Armature Z: Commutator X: Commutator Y: Brush Z: Armature X: Armature Y: Commutator Z: Brush X: Armature Y: Brush Z: Commutator Mark this and return
Answer:
I know this isn't much help but its not B
Explanation:
Answer:
D
Explanation:
A 6 kg bowling ball is on top of a building. It has 2,352 J of potential energy. What is the height of
the building?
Hello!
[tex]\large\boxed{ h = 40m}[/tex]
Use the formula below to solve:
[tex]\text{ Potential energy} = mgh[/tex]
Where:
m = mass of object (kg)
g = acceleration due to gravity (9.8 m/s²)
h = height of the building (m)
We are given the potential energy, mass, and gravity, so plug in those values into the equation to solve for the height:
[tex]2352 = 6 * 9.8 * h\\\\2352 = 58.8h\\\\2352/58.8 = 58.8h / 58.8\\\\h = 40 m[/tex]
A car is stopped for a traffic signal. When the light turns green, the car accelerates, increasing its speed from 0 to 5.40 m/s in 0.792 s. What are:______
a. the magnitudes of the linear impulse
b. the average total force experienced by a 70.0-kg passenger in the car during the time the car accelerates?
Answer:
a) 378Ns
b) 477.27N
Explanation:
Impulse is the defined as the product of the applied force and time taken. This is expressed according to the formula
I = Ft = m(v-u)
m is the mass = 70kg
v is the final velocity = 5.4m/s
u is the initial velocity = 0m/s
Get the impulse
I = m(v-u)
I = 70(5.4-0)
I = 70(5.4)
I = 378Ns
b) Average total force is expressed as
F = ma (Newton's second law)
F = m(v-u)/t
F = 378/0.792
F = 477.27N
Hence the average total force experienced by a 70.0-kg passenger in the car during the time the car accelerates is 477.27N
Question 18 of 20
Which situation results in the least attraction between two magnets?
A. The south pole of one magnet is near the south pole of the other
magnet
B. The north pole of one magnet is near the south pole of the other
magnet
C. The north pole of one magnet is far away from the north pole of
the other magnet
D. The north pole of one magnet is far away from the south pole of
the other magnet.
Answer:D
Explanation:
Answer:
Explanation: the answer is D.
(a) What is lightning?
Problem 4: For a conservative force,esvoedca2beee49af123450c68a7237065a45ad885a4229cb932c3697d0b27c6328eaeovse 0N86-C1-52-40-A837-22820 If you push a wooden crate across rough ground with a force F over a distance d, what is the potential energy stored in the system due to this force
Answer:
PE = Fd
Explanation:
Potential energy is the energy possessed by a body by virtue of its position. It is expressed mathematically as:
PE = mgd
m is the mass
g is the acceleration due to gravity
d is the distance
Since Force F is expressed as the product of mass and acceleration due to gravity then, F = mg
Substitute into the formula above:
Recall that: PE = mgd
Since F = mg
PE = Fd
Hence the required expression is PE = Fd
An orange of mass m falls into a wagon. Assume the orange experiences upward acceleration magnitude a when it comes in contact with the wagon. What is the correct expression for the normal force magnitude F, exerted on the orange?
What is the correct expression for the normal force magnitude Fr exerted on the orange?
Consider upward as the positive direction.
Fn = m(a -g)
Fn = m(a +g)
Fn=a +g /m
Fn= m/a+g
Answer:
Explanation:
Fn = m(a + g)
A solenoid 30 cm long is wound with 250 turns of wire. The cross-sectional area of the coil is 3.5 cm^2. What is the self-inductance of the solenoid?
Answer:
The value is [tex]L = 9.164 *10^{-5} \ H[/tex]
Explanation:
From the question we are told that
The length of the solenoid is [tex]l = 30 \ cm = 0.3 \ m[/tex]
The number of turns is [tex]N = 250 \ turns[/tex]
The cross-sectional area is [tex]A = 3.5 \ cm^2 = 3.5 *10^{-4} \ m^2[/tex]
Generally the self inductance of the solenoid is
[tex]L = \frac{\mu_o * N^2 * A }{ l }[/tex]
Here [tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi *10^{-7} \ T \cdot m/A[/tex]
So
[tex]L = \frac{ 4 \pi*0^{-7} * 250^2 * 3.5 *10^{-4} }{ 0.3 }[/tex]
=> [tex]L = 9.164 *10^{-5} \ H[/tex]
From the gravitational law calculate the weight W (gravitational force with respect to the earth) of a 89-kg man in a spacecraft traveling in a circular orbit 261 km above the earth's surface. Express W in both (a) newtons and (b) pounds.
Answer:
[tex]W=\frac{773}{4.45}=173.76 l b f[/tex]
Explanation:
[tex]W=\frac{G \cdot m_{e} \cdot m}{(R+h)^{2}}[/tex]
The law of gravitation
[tex]G=6.673\left(10^{-11}\right) m^{3} /\left(k g \cdot s^{2}\right)[/tex]
Universal gravitational constant [S.I. units]
[tex]m_{e}=5.976\left(10^{24}\right) k g[/tex]
Mass of Earth [S.I. units]
[tex]m=89 kg[/tex]
Mass of a man in a spacecraft [S.I. units]
[tex]R=6371 \mathrm{~km}[/tex]
Earth radius [km]
Distance between man and the earth's surface
[tex]h=261 \mathrm{~km} \quad[\mathrm{~km}][/tex]
ESULT [tex]W=\frac{6.673\left(10^{-11}\right) \cdot 5.976\left(10^{24}\right) \cdot 89}{\left(6371 \cdot 10^{3}+261 \cdot 10^{3}\right)^{2}}=773.22 \mathrm{~N}[/tex]
[tex]W=\frac{773}{4.45}=173.76 l b f[/tex]
Which of the following is an instantaneous speed?
A: All of the above
B: 80 ft/s
C. 80 yds./min
D. 80 km/hr
Answer:
A: All of the above
Explanation:
The instantaneous speed of an object is simply the current seed of the object at any given time. The SI unit is m/S and it is a vector quantity.
Therefore, according to the given options, they all have SI units that are consistent with distance and time which makes them all an example of instantaneous speed.
What is the main organ of the circulatory system?
veins
arteries
heart
capillaries
It is the heart
if not im sorry
which of the following is not a risk associated with using legal drugs without medical supervision
Answer:
paying too much on the black market instead of getting a prescription
Explanation:
i just took the quiz
Answer:
Paying too much on the black market instead of getting a prescription
Explanation:
The rest of the options are risks associated with using legal drugs without medical supervision.
An object is moving with constant speed in a
circular path. The object's centripetal
acceleration remains constant in
(1) magnitude, only
(2) direction, only
(3) both magnitude and direction
(4) neither magnitude nor direction
Answer:
both magnitude and direction
Explanation:
When an object moves in a circular path, its motion is called uniform circular motion. In this motion, the force acting on it is centripetal force and it is moving under centripetal acceleration. This type of force acts towards the centre of the circle.
In this type of motion, the speed remains constant while the velocity keeps on changing. The object's centripetal acceleration remains constant in magnitude as well as direction.
Hence, the correct option is (3).
If an object is moving with constant speed in the circular path the object's centripetal acceleration remains constant in both magnitude and direction
The formula for calculating the centripetal acceleration of an object is expressed as:
[tex]a =\frac{v^2}{r}[/tex]
v is the speed of the objectr is the radius of the circular pathIf the speed of the object is constant, the acceleration is of the body is also constant.Hence if an object is moving with constant speed in the circular path the object's centripetal acceleration remains constant in both magnitude and direction
Learn more on centripetal acceleration here: https://brainly.com/question/79801
Only four forces act on an object. They all have the same magnitude. Their directions are north, south, northwest, and northeast. In which direction does the object accelerate? (A) north (B) south (C) northwest (D) northeast (E) The object does not accelerate because the four forces cancel.
Answer:
the correct answer is A, North
Explanation:
The forces are vectors so they must be added vectorially.
The magnitude of the forces is the same, but not their direction, which is why they are different.
Analyze the situation presented
We have a force towards the North and another towards the South with the same magnitude, therefore these cancel each other out
We have a force towards the Northeast and another towards the Northwest, these can be decomposed into parts, one towards the North and another on the East-West axis, this last component is canceled, but the component towards the North is added.
In summary we see that the body accelerates towards the North
the correct answer is A
Compare and contrast Infra-red, visible light and UV.
Answer:
The EM radiation most immediately lower-frequency than visible light is called infrared, and the EM radiation most immediately higher-frequency is called ultraviolet.
An investigation has been completed similar to the one on latent heat of fusion, where steam is bubbled through a container of water. Steam condenses and the lost energy heats the water and container. Use the following data to answer the question below:
Mass of the aluminum container 50 g
Mass of the container and water 250 g
Mass of the water 200 g
Initial temperature of the container and water 20°C
Temperature of the steam 100°C
Final temperature of the container, water, and condensed steam 50°C
Mass of the container, water, and condensed steam 261 g
Mass of the steam 11 g Specific heat of aluminum 0.22 cal/g°C
Given the data above, determine the total heat energy gained by the container and water.
Answer:
[tex]Q_a=330 cal[/tex]
[tex]Q_w=6000cal[/tex]
Explanation:
From the question we are told that
Mass of the aluminum container 50 g
Mass of the container and water 250 g
Mass of the water 200 g
Initial temperature of the container and water 20°C
Temperature of the steam 100°C
Final temperature of the container, water, and condensed steam 50°C
Mass of the container, water, and condensed steam 261 g
Mass of the steam 11 g Specific heat of aluminum 0.22 cal/g°C
a) Heat energy on container
Generally the formula for mathematically solving heat gain
[tex]Q_c=M_c *C_c*( \triangle T)[/tex]
Therefore imputing variables we have
[tex]Q_a=50g *0.22*50-20[/tex]
[tex]Q_a=330 cal[/tex]
b) Heat energy on water
Generally the formula for mathematically solving heat gain
[tex]Q_w=M_w *C_w*( \triangle T)[/tex]
Therefore imputing variables we have
[tex]Q_w=200 *1* 50-204[/tex]
[tex]Q_w=6000cal[/tex]
in how many days the life cycle of honeybee complete
Three wheels each of radius 1 have their centers at respective verticies of an equilateral triangle of side length 4. A belt is wrapped continuously around the wheels. Find the length of the belt.
Answer:
L = 6 * ( π + 1 )
Explanation:
The side of the equilateral triangle is 4, and each one of the circles is of radius 1. Then
Triangle vertex A B and C
Trajectory of the belt, beginning in vertex A
1.-First circle A one turn
L₁ = 2*π*1 = 2*π
2.-Length between the circle A and B
L₂ = 2
3.- To wrap this circle we need to wrap the circle and to run the belt through the radius twice. The firs over the side AB and the second over the side BC, therefore
L₃ = 2*π*1 + 2*(1)
L₃ = 2*π + 2
4.-Length between two nearest points of circles B and C is 2 and length of the circle in C is 2*π*1. Then
L₄ = 2 + 2*π
Total length of the belt is:
L = L₁ + L₂ + L₃ + L₄
L = 2*π + 2 + (2*π + 2 ) + ( 2 + 2*π )
L = 6*π + 6
L = 6 * ( π + 1 )
why is heat called a form of energy?
Answer:
Because heat can be converted from one form to another.
Heat is also does work, for example it sets water molecules into motion when boiling ( convection currency ).
since energy is the ability to do work, heat does work.
When gasoline is burned, it gives off 46,000 J/gram of heat energy. If an automobile uses 13.0 kg of gasoline per hour with an efficiency of 21%, what is the average horsepower output of the engine
Answer:
The correct output will be "46.76 h.p.".
Explanation:
The given values are:
Gasoline's energy content,
= 46000 J/g
= 4.6 x10⁷ J/kg
Fuel usage,
= 13 kg/h
= [tex]\frac{13}{3600} \ kg/s[/tex]
Fuel efficiency,
= 21%
= 0.21
Now,
The average output will be:
= [tex](Energy \ content \ of \ gasoline)\times (fuel \ usage)\times (fuel \ efficiency)[/tex]
On substituting the values, we get
= [tex]4.6\times 10^7\times (\frac{13}{3600} )\times 0.21\times (\frac{1}{746}) h.p.[/tex]
= [tex]46.76 \ h.p.[/tex]
Answer:
the average horsepower output of the engine is 46.76 hp
Explanation:
The computation of the average horsepower output of the engine is shown below
The output of the engine is
= (Energy content of gasoline) × (usage of the fuel ) × (Fuel efficiency)
As we know that
1 hp = 746 W
where,
Energy content of gasoline = 46000 J / g = 4.6 × 107 J/kg
Usage of the fuel = 13 kg / h = 13 ÷ 3600 kg/s
Fuel efficiency = 21% = 0.21
Therefore, the output of the engine is
= 4.6 × 107 × (13 ÷ 3600) × 0.21 × (1 ÷ 746) h.p.
= 46.76 h.p.
hence, the average horsepower output of the engine is 46.76 hp
If the interest of sum of money is 6 yrs in 3/8 of the principal . what is the rate of interest?
Answer:
=6.25%
Explanation:
Simple interest can be calculated using the below formula
I=prt/100
=Interest
P=Principal
R=Rate
T=Time
T=6 yrs
R=3/8
Making R subject of the formula
R=(I ×100)/PT
Substitute the values
=(3/2 P×100)/P×6
The "P" in the numerator cancelled out the "P" in denominator then we have
=(3/2×100)/6
=6.25%
Hence the rate is 6.25%
After a collision between two different massed objects; the larger objects accelerate at a faster rate than the smaller object? If false please explain
why
Answer: Things continue doing what they are doing unless a force is applied to it. Objects have a natural tendency to resist change. This is INERTIA. Heavier objects (objects with more mass) are more difficult to move and stop. Heavier objects (greater mass) resist change more than lighter objects, so true
Explanation:
Pushing a bicycle or a Cadillac, or stopping them once moving. The more massive the object (more inertia) the harder it is to start or stop. The Cadillac has more of a tendency to stay stationary (or continue moving), and resist a change in motion than a bicycle.
SOMEBODY ONCE TOLD ME THE WORLD WAS GONNA ROLL ME
I AIN'T THE SHARPEST TOOL IN THE SHED~
SHE WAS LOOKING KINDA DUM WITH HER FINGER AND HER THUMB
IN THE SHAPE OF AN "L" ON HER FOREHEAD~
WELL THE YEARS START COMING AND THEY DON'T STOP COMING
FED TO THE RULES AND I HIT THE GROUND RUNNING
DIDN'T MAKE SENSE NOT TO LIVE FOR FUN
YOUR BRAIN GETS SMART BUT YOUR HEAD GETS DUM
SO MUCH TO DO, SO MUCH TO SEE--
SO WHATS WRONG WITH TAKING THE BACKSTREETS?
YOU'LL NEVER KNOW IF YOU DON'T GO
YOU'LL NEVER SHINE IF YOU DON'T GLOW.
Answer:
shrek
Explanation:
allstar
What us the difference in the ways objects move at a speed of a car and an object mkvinf close to the speed of light?
Answer:
The difference is in who or what is observing the speed.
Explanation:
Giving that speed is relative between the objects and the reference point from which it is being observed.
It is concluded that speed alone has no direct effect on a moving object, hence it is just a determining unit for the difference in distance between two objects.
Therefore, in this case, the difference is in who or what is observing the speed.
How does heat from the sun affect Earth's spheres?
Answer:
1)The heat from the sun is one of the causes of rainfall.
2) It also causes thermal equilibrium on the earth's surface.
Explanation:
1) Heat from the sun heard of the water bodies, covers some to vapor which is taking up too form rains and snow.
2) Without the heat of the sun the only source of heart for the earth would be the geothermal heat (ie. the heat from within the earth). This type of heart wouldn't be enough to keep us warm because of the presence of the glaziers
A tennis ball (m=0.060 kg) is moving horizontally at 20 m/s toward a tennis player who hits it straight back at 26 m/s. What is the change in momentum (in kg m/s) delivered to the tennis ball? 20 m/s 26 m/s
A. 0.36
B. 12.2
C. 1.84
D. 2.76
Answer:
0.36 kg-m/s
Explanation:
Given that,
Mass of a ball, m = 0.06 kg
Initial velocity of the ball, u = 20 m/s
Final velocity of the ball, v = 26 m/s
We need to find the change in momentum of the tennis ball. It is equal to the final momentum minus initial momentum
[tex]\Delta p=m(v-u)\\\\=0.06\times (26-20)\\\\=0.36\ kg-m/s[/tex]
So, the change in momentum of the ball is 0.36 kg-m/s.
The is the sac-like structure that holds the testes.
Answer:
Scrotum
Explanation:
Answer: Scrotum
Explanation: edge