A SOUND WAVE WITH ITS CHARACTERISTIC PATTERN OF COMPRESSIONS AND
RAREFACTIONS IS SHOWN BELOW. A CENTIMETER RULER IS INCLUDED BELOW THE
PATTERN THE WAVELENGTH OF THIS SOUND WAVE IS HOW MANY cm?
A 2 cm
B 3 cm
C 35 cm
D. 85 cm
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Answers

Answer 1

Answer:

The wavelength is 1.7cm

Explanation:

Given

See attachment for wave pattern

Required

What is the wavelength

To do this, we simply calculate the distance between successive waves (see attachment 2 for point A and B)

Using the ruler, points A and B are at:

[tex]A = 0.6cm[/tex]

[tex]B = 2.3cm[/tex]

So, the wavelength is:

[tex]\lambda = B - A[/tex]

[tex]\lambda = 2.3cm - 0.6cm[/tex]

[tex]\lambda = 1.7cm[/tex]

If approximated, the wavelength is:

[tex]\lambda \approx 2cm[/tex]

A SOUND WAVE WITH ITS CHARACTERISTIC PATTERN OF COMPRESSIONS ANDRAREFACTIONS IS SHOWN BELOW. A CENTIMETER
A SOUND WAVE WITH ITS CHARACTERISTIC PATTERN OF COMPRESSIONS ANDRAREFACTIONS IS SHOWN BELOW. A CENTIMETER

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Which factors below will increase the momentum of a rolling ball of constant mass m? (Select only the answers that will increase the momentum of the ball.) Moving from a flat surface to moving downhill. Colliding with a ball of much lower mass moving in the opposite direction of the ball. A moving object traveling in the same direction as the ball colliding with it. Rolling uphill onto an inclined surface. Rolling onto a surface with high amounts of friction with the ball.​

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Answer:

Explanation:

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Answer:

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Answer:

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Answers

Answer:

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Answers

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Answers

For harmer:-

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Answers

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Answers

Answer:

Let y equal lambda the wavelength of the light

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helppppppppppppppppppppppp

Answers

Explanation:

v²= u² + 2as

v= final velocity.

u= initial velocity.

a= acceleration.

s= distance.

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