classify the simple machine knife​

Answer:

10 kg

Explanation:

The mass of an object does not change even if the amount of gravtiy changes.

Answer:

25000N

Explanation:

distance travelled(d)=500m

force(f)=20N

Power=0.4KW=0.4×1000Watt=400watt

Then,Time(T)=?

Now,

Power(P)=W/T

400=F×D/T.(w=f×d)

or, 400=20×500/T

or, 400=10000/T

or, T=10000/400

or,T=25 sec

Therefore,time taken=25 sec

Answer:

Just 3

Explanation:

I believe the other two are incorrect

Answer: e: none of the above.

Explanation:

For any object in the air, the gravitational acceleration will be always -9.8m/s^2, where the negative sign is because gravity pulls the object down.

The instantaneous velocity, as a function of time, for the case of the ball, is

V(t) = (-9.8m/s^2)*t + v0

Where v0 is the velocity at which the ball is thrown up.

The velocity will be zero when the ball is at the top of its flight pat, in that point the sign of the velocity changes, it stops being positive (so the ball stops going up) and becomes negative (so the ball starts to fall down).

Now, while the instantaneous velocity can be zero during the flight, the acceleration does not, it only will be zero when the object hits the ground. Then the only correct option will be e: none of the above.

Correct question is;

A tiny water droplet of radius 0.010 cm descends through air from a high building .Calculate its terminal velocity . Given that η of air = 19 × 10^(-6) kg/m.s and density of water ρ = 1000kg/ms

Answer:

1.146 m/s

Explanation:

We are given;

Radius; r = 0.010 cm = 0.01 × 10^(-2) m

η = 19 × 10^(-6) kg/m.s

ρ = 1000 kg/ms

The formula for the terminal velocity is given by;

V_t = 2r²ρg/9η

g is acceleration due to gravity = 9.8 m/s²

Thus;

V_t = (2 × (0.01 × 10^(-2))² × 1000 × 9.8)/(9 × 19 × 10^(-6))

V_t = 1.146 m/s

Answer:

There are at least two ways contemporary music in America has made use of nature by directly making use of the sounds of nature as musical material, or else in works that desire to imitate nature "in its manner of operation." That is, they are constructed the way nature is, they work the way nature works, rather than sounding the way nature sounds.

Explanation:

Answer:

The answer would be a

Explanation:

Answer:

The two criteria that are most essential are options C and D

Explanation:

In trying to develop a new process/procedure for the commercial/industrial production of a particular substance (in this case phosphorus pentachloride), it is important that the workers that would operate the equipment required for this new procedure are able to operate it safely, i.e without fear of injury or losing one's life. If this fear is present or any adverse effect occurs, it would not only be counterproductive but would also make workers avoid using this procedure and may be forced to revert to previous safe procedure.

It is also essential for the new procedure to be able to get the most desired product out of the reactant, meaning the rate and amount of desired product (phosphorus pentachloride) that would be obtained from a given amount of reactant must be very high (a better upgrade when compared to the previous procedure). This is going to cause for a better amount of phosphorus pentachloride produced as against the previous amounts produced from previous procedure.

From the above, it can be deduced that options C and D are two criteria that are most essential when trying to develop a novel process to produce phosphorus pentachloride.

Answer: the guy above me is correct

Explanation:

Mesas form by weathering and erosion of horizontally layered rocks that have been uplifted by tectonic activity. Variations in the ability of different types of rock to resist weathering and erosion cause the weaker types of rocks to be eroded away, leaving the more resistant types of rocks topographically higher than their surroundings. This process is called differential erosion. 

Hope it helps!

Answer:

(1) the potential difference that stopped the proton is 1878.75 V

(2) the initial kinetic energy of the proton is 1878.75 eV

Explanation:

Given;

initial speed of the proton, v = 600,000 m/s

mass of proton, m = 1.67 x 10⁻²⁷ kg

(1) The work done in bringing the proton to rest is given as;

[tex]W = eV[/tex]

Apply work energy theorem;

[tex]K.E =W\\\\ \frac{1}{2} mv^2 = eV\\\\V = \frac{mv^2}{2e}[/tex]

where;

V is the potential difference

[tex]V = \frac{1.67\times 10^{-27} \times\ 600,000^2}{2 \ \times \ 1.6 \times 10^{-19}} \\\\V = 1878.75 \ V[/tex]

(2) the initial kinetic energy of the proton, in electron volts;

[tex]K.E = \frac{1}{2} mv^2\\\\K.E = \frac{1}{2} \times \ 1.67\times 10^{-27} \times 600,000^2 = 3.006 \times 10^{-16} \ J\\\\K.E = \frac{3.006 \times 10^{-16} \ J \ \ eV}{1.6 \times 10^{-19} \ J} = 1878.75 \ eV[/tex]

Answer:

As the height increases the pressure must increase.

Explanation:

When we add masses to the fluid, the amount of fluid in the tank increases, therefore its height increases and the pressure is described by the expression

           P = ρ g h

where rho is constant for a given fluid and h is the height measured from the surface of the fluid.

As the height increases the pressure must increase.

Answer:

323.4 N

Explanation:

Given that,

The coefficient of static friction, [tex]\mu_s=0.63[/tex]

The coefficient of kinetic friction, [tex]\mu_k=0.49[/tex]

We need to find the frictional force acting on the player. As the baseball player is sliding into home base, we will use the coefficient of kinetic friction to find the frictional force.

[tex]F=\mu _kN\\\\=0.49\times 660\\\\=323.4\ N[/tex]

So, the frictional force acting on the player is 323.4 N.

Answer:

Because as we climb higher the amount of oxygen in the air decreases and this makes the air thinner and dryer. And at higher altitudes the blood pressure inside of our body is more than the atmospheric pressure which forces the blood to come out from openings like the nose.

Explanation:

Answer:

bowling was one of the first racially integrated sports because bowling alleys were primarily located in urban areas. Racial integration was inevitable since it was promoted by US Armed Forces during 1940s and its image as sport for the common man made it a choice of activity for Americans!!

Explanation:

Answer:

The answer is below

Explanation:

Equation of motion is a term in physics that is used in explaining the characteristics of a physical system concerning its motion while considering the period.

The First Equation of Motion is given as v = u + at

Here, a = acceleration, v = final velocity, u = initial velocity, and t = time

To deduce it algebraically, it is written as

a = (v - u) ÷ t

Therefore, it can be repositioned to => v = u + a * t

Answer:

a. increases

Explanation:

Outdoor pipe organ is a musical instrument that is used to play music. It produces some soothing notes and is very peaceful to the ears. The organ pipe is the source of sound for the outdoor organ. And the length of the pipe determines the wavelength of the sound. When the air temperature of the surrounding is increased, the fundamental frequency of one of the organ pipes will be increased as the speed of the sound will increased.

Explanation:

Given that,

Mass of a body, m = 1 kg

Force constant, k = 16 N/m

We need to find the angular frequency and the frequency of oscillation.

(a) The angular frequency of a body is given by :

[tex]\omega=\sqrt{\dfrac{k}{m}} \\\\=\omega=\sqrt{\dfrac{16}{1}} \\\\=4\ rad/s[/tex]

(b) The frequency of oscillation is given by :

[tex]f=\dfrac{\omega}{2\pi}\\\\f=\dfrac{4}{2\pi}\\\\=\dfrac{2}{\pi}\ Hz[/tex]

Hence, this is the required solution.

Answer:

Conductors- copper, aluminum, gold, and silver.

Insulators- glass, air, plastic, rubber, and wood.

Explanation:

Answer: 5 conductors are copper, aluminum, gold, iron, and silver and 5 insulators are glass, air, plastic, rubber, and wood.

Answer:

1.4 m/s

Explanation:

Assuming that the system is an isolated one, then we will conserve the linear momentum of the system so as to be able to solve the system for required quantities:

Using the conservation of momentum, we have,

initial momentum = final momentum

P(i) = P(f)

And from the question, we see that the system has no initial momentum

After throwing the first brick we have

(40 + 10 + 5)v2 + 5 * -7 = 0

55v2 - 35 = 0

55v2 = 35

v2 = 35/55

v2 = 0.63 m/s

Now, considering that she conserves momentum when she throws the second brick again, we then say

(40 + 10 + 5) * 0.63 = (40 + 10)v(f) + 5 * -7

55 * 0.63 = 50v(f) - 35

35 = 50v(f) - 35

50v(f) = 35 + 35

50v(f) = 70

v(f) = 70/50

v(f) = 1.4 m/s

Answer:

Fr = 55 [N]

Explanation:

We must perform a free body diagram to understand the forces acting on the couch. In the attached image we see the force that Jack exerts just like that of Rob acting in the same direction.

We must perform a summation of force on the X-axis, to determine the resulting force.

∑Fx = Fr

Fr = 30 + 25

Fr = 55 [N]

Given the workdone and the quantity of the charge, the potential difference between points A and points B is 5 Volts.

Potential difference is simply referred to as work done required to move a charge from point A to point B per unit charge.

It is expressed as;

V = W / q

Given the data in the question;

We substitute our values into the exression above.

V = W / q

V = 10J / 2C

V = 5V

Therefore, given the workdone and the quantity of the charge, the potential difference between points A and points B is 5 Volts.

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Answer:

The maximum value of the magnetic field in the given wave is 6.67 nT.

Explanation:

Given;

maximum value of the electric field, E₀ = 2.0 V/m

The maximum value of the magnetic field in the given wave is calculated as;

[tex]B_o = \frac{E_o}{c}[/tex]

where;

c is the speed of light = 3 x 10⁸ m/s

[tex]B_o = \frac{E_o}{c} \\\\B_o = \frac{2}{3 \ \times \ 10^8} \\\\B_o = 6.67 \ \times \ 10^{-9} \ T\\\\B_o = 6.67 \ nT[/tex]

Therefore, the maximum value of the magnetic field in the given wave is 6.67 nT.

Answer:

negative plus positive with energy = battery

Explanation:

Explanation:

The tangential speed of Andrea is given by :

[tex]v=r\omega[/tex]

Where

r is radius of the circular path

ω is angular speed

The merry-go-round is rotating at a constant angular speed. Let the new distance from the center of the circular platform is r'

r' = 2r

New angular speed,

[tex]v'=r'\omega'\\\\v'=(2r)\omega\\\\v'=2r\omega\\\\v'=2v[/tex]

New angular speed is twice that of the Chuck's speed.

Answer:

The answer is "effective stress at point B is 7382 ksi "

Explanation:

Calculating the value of Compressive Axial Stress:

[tex]\to \sigma y =\frac{F}{A} = \frac{4 F}{( p d ^2 )} = \frac{(4 x ( - 40000 \ lbf))}{[ p \times (1 \ in)^2 ]} = - 50.9 \ ksi \\[/tex]

Calculating Shear Transverse:

[tex]\to \frac{4v}{ 3 A} = \frac{4 (75 \ lbf + 25 \ lbf)}{ \frac{3 ( lni)^2}{4}}[/tex]

        [tex]= \frac{4 (100 \ lbf)}{ \frac{3 ( lni)^2}{4}} \\\\ = \frac{400 \ lbf)}{ \frac{3 ( lni)^2}{4}} \\\\= 0.17 \ ksi[/tex]

[tex]= R \times 200 \ in - P \times 100 \ in = 12500 \ lbf \times\ in[/tex]

[tex]\to \sigma' =[ s y^2 +3( t \times y^2 + t yz^2 )] \times \frac{1}{2}\\\\[/tex]

       [tex]= [ (-50.9)^2 +3((63.7)^2 +(0.17)^2 )] \times \frac{1}{2}\\\\=[2590.81+ 3(4057.69)+0.0289]\times \frac{1}{2}\\\\=[2590.81+12,173.07+0.0289] \times \frac{1}{2}\\\\=14763.9089\times \frac{1}{2}\\\\ = 7381.95445 \ ksi\\\\ = 7382 \ ksi[/tex]

Answer:

The number of vibrations per second an object is making

Explanation:

We need to find the correct option for a sound wave’s frequency.

Frequency is the number of vibrations per second an object is making. It can be calculated as total no. of vibrations divided by time taken.

Its SI unit is Hertz and it is denoted by Hz.

Hence, the correct option is (a).

Answer: 54.8

Explanation:

The centripetal force on the rock moving along the string is 104.66 N.

The given parameters;

The centripetal acceleration of the rock is calculated as follows;

[tex]\omega _f^2 = \omega _i^2 + 2\alpha (\theta)\\\\(100 \ \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1 \min}{60 \ s} )^2 = 0 + 2\alpha (30 ^0 \times \frac{\pi \ rad}{180^0} )\\\\109.69 = 1.048\alpha \\\\\alpha = \frac{109.69}{1.048} \\\\\alpha =104.66 \ rad/s^2[/tex]

[tex]a_c = \alpha \times r\\\\a_c = 104.66 \times 1 = 104.66 \ m/s^2[/tex]

The centripetal force on the rock is calculated as follows;

[tex]F_c = ma_c[/tex]

[tex]F_c = 104.66 \times 1\\\\F_c = 104.66 \ N[/tex]

Thus, the centripetal force on the rock moving along the string is 104.66 N.

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