In ΔOPQ, \overline{OQ} OQ ​ is extended through point Q to point R, \text{m}\angle PQR = (4x-10)^{\circ}m∠PQR=(4x−10) ∘ , \text{m}\angle OPQ = (x+9)^{\circ}m∠OPQ=(x+9) ∘ , and \text{m}\angle QOP = (x-5)^{\circ}m∠QOP=(x−5) ∘ . Find \text{m}\angle PQR.m∠PQR.

In OPQ, \overline{OQ} OQ Is Extended Through Point Q To Point R, \text{m}\angle PQR = (4x-10)^{\circ}mPQR=(4x10)

Answers

Answer 1

Answer:

In

In to point R, \text{m}\angle PQR = (7x-19)^{\circ}m∠PQR=(7x−19) ∘ , \text{m}\a

Step-by-step explanation:

Answer 2

The sum of two interior angles other than the adjacent angle of extended length will be equal to the external angle of extended length thus m∠PQR will be 18°.

What is an angle?

An angle is a geometry in plane geometry that is created by 2 rays or lines that have an identical terminus.

The identical endpoint of the two rays—known as the vertex—is referenced as an angle's sides.

In any triangle,The sum of two interior angles other than the adjacent angle of extended length will be equal to the external angle of extended length.

In the given triangle below image,

m∠PQR = m∠OPQ + m∠POQ

4x - 10 = x + 9 + x - 5

4x - 10 = 2x + 4

2x = 14

x = 7

So,

m∠PQR = 4(7) - 10 = 18°

Hence "The measure of m∠PQR will be 18° for the given triangle".

For more about the angle,

brainly.com/question/13954458

#SPJ2

In OPQ, \overline{OQ} OQ Is Extended Through Point Q To Point R, \text{m}\angle PQR = (4x-10)^{\circ}mPQR=(4x10)

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If the m∠A is 29°, what are the m∠B and m∠C?)

A. m∠B= 119°, m∠C = 151°
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Answers

Step-by-step explanation:

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therefore the answer is D. mB = 61°, mC = 119°

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