Solution :
Given weight of Kathy = 82 kg
Her speed before striking the water, [tex]$V_o $[/tex] = 5.50 m/s
Her speed after entering the water, [tex]$V_f$[/tex]= 1.1 m/s
Time = 1.65 s
Using equation of impulse,
[tex]$dP = F \times dT$[/tex]
Here, F = the force ,
dT = time interval over which the force is applied for
= 1.65 s
dP = change in momentum
dP = m x dV
[tex]$= m \times [V_f - V_o] $[/tex]
= 82 x (1.1 - 5.5)
= -360 kg
∴ the net force acting will be
[tex]$F=\frac{dP}{dT}$[/tex]
[tex]$F=\frac{-360}{1.65}$[/tex]
= 218 N
URGENT HELP
The electric motor in the car is powered by a battery.
To charge the battery, the car is plugged into the mains supply at 230 V
The power used to charge the battery is 6.9 kW
Calculate the current used to charge the battery.
Current = ?
Answer:
0.03 A
Explanation:
Answer:
30A
Explanation:
I (current)= p (power) / V (voltage)
I= 6.9*10^3 / 230
I= 30A
b. Velocity is both _speed __ and ___. Formula: ___
Answer: Velocity is both magnitude and direction. Formula: d(distance)/t(total time)
what element is chemically similar to Krypton?
Answer:
Nobel gases
Explanation:
Well since Krypton is in a group called the “Noble Gases”, then Krypton is similar to the others; Xenon, Helium, Neon, Argon, and Radon.
You must: (a) dim your high beams for oncoming vehicles by the time they are within _____ feet of your vehicle, and (b) dim your high beams when the vehicle you are following is within _____ feet.
Answer:
500,300
Explanation:
Safety measures on the road can be regarded as activities and precautions that should be taken in order to improve safety on the road which means to reduce risk.
Whenever one is driving with high-beam lights on, one of safety precautions that must taken into consideration is that ;
You must: (a) dim your high beams for oncoming vehicles by the time they are within 500 feet of your vehicle
(b) dim your high beams when the vehicle you are following is within 300 feet.
When you dim the beam, the oncoming vehicle won't be blind, he/she would be able to see clearly. As you are approaching a car with high-beams, look at the right edge of your own lane and use Conner of your eyes to watch the oncoming car to avoid been blind .
Read the question, and then use the drop-down menus to complete the paragraph.
What is Earth’s atmosphere made of?
The most abundant gas in Earth’s atmosphere is
, followed by
, which is needed to burn wood and fuel. The third-most abundant gas is
. The amount of
in the atmosphere is very small, making up just 0.033% of the atmosphere, but it is very important because plants use it to make simple sugars. Another important gas is water vapor, which condenses around
in the atmosphere to form clouds and then rain.
Answer:
The most abundant gas in Earth’s atmosphere is nitrogen, followed by oxygen, which is needed to burn wood and fuel. The third-most abundant gas is argon. The amount of carbon dioxide in the atmosphere is very small, making up just 0.33% of the atmosphere, but it is very important because plants use it to make simple sugars. Another important gas is water vapor, which condenses around small particles in the atmosphere to form clouds and then rain.
Explanation:
The atmospere of the earth is made up of different types of gases like Nitrogen, oxygen, Carbon di oxide etc.
What is atmosphere?Atmosphere is defined as the envelope of the gases covered the whole planet of earth and is responsible to save us from ultravoilet rays and entrape the radiation to maintain the ideal temperature on the surface of earth by green house effect.
The most abundant gas in Earth’s atmosphere is nitrogen, followed by oxygen, which is needed to burn wood and fuel. The third-most abundant gas is argon.
The amount of carbon dioxide in the atmosphere is very small, making up just 0.33% of the atmosphere, but it is very important because plants use it to make simple sugars.
Another important gas is water vapor, which condenses around small particles in the atmosphere to form clouds and then rain.
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The density of sulfur is 2g/cm3. A large block of pure sulfur was broken into two smaller pieces. The density of each piece of sulfur is now 1 g/cm3.
True or false
Answer:
False
Explanation:
Density is an intensive property of a substance. Intensive properties are those properties that are characteristic of a substance. They do not depend on the amount of substance present.
Since density is an intensive property, each piece of sulphur still has a density of 2g/cm3.
1. The mass of an object on the Earth is 100. kg.
a. What is the weight of the object on the Earth?
b. What is the mass of the object on the moon?
Answer:
980N
100kg
Explanation:
Weight is Mass * Gravity.
For question a, the object with a mass of 100 kg will have a weight of
100 * 9.8 = 980N
For question b, the mass of the object will stay the same, even if it is on the moon. Therefore it is 100kg.
(a). The weight of the object on the Earth is 980 N.
(b). The mass of the object on the moon is 100 kg.
The weight of the object on the earth has been considered to be affected by the Gravitational force as it has been acting on the object.
(a) The weight of the object on Earth can be given by:
Weight = mass [tex]\times[/tex] Gravitational Force
Given, the mass of the object = 100 kg.
The gravitational force = 9.8N
Weight of the object = 100 [tex]\times[/tex] 9.8 N
Weight of the object = 980 N
(b) The mass of the object has been independent of the gravitational force that has been acting on the object.
Thus, the mass of the object on earth = the mass of object on the moon.
The mass of the object on the moon = 100 kg.
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Which system of equations and solution can be used to represent the radius if the mass of the cylinder is 11,000 grams
Explanation:
The mass of a cylinder made of barium with a height of 2 inches depends on the radius of the cylinder as defined by the
function m(r) = 7.18872.
which system of equations and solution can be used to represent the radius if the mass of the cylinder is 11,000 grams?
round to the nearest hundredth of an inch.
A student wants to build a simple circuit. Which material would be used to design a circuit with the last amount of resistance?
A. Long wires with a large diameter
B.Long wires with a thin diameter
C.Short wires with a large diameter
D.Short wires with a thin diameter
Answer:
C
Explanation:
The shorter a wire, the less it will be worn down from moving around, and the thicker the wire, the longer it will last.
Short wires with a wide diameter will be the material utilized to build a circuit with the minimum amount of resistance. Then, C is the right answer.
What is the circuit?Electrical devices such as resistance, transistors, capacitors, inductors, and diodes are connected via conductive wires or traces that allow the electric current to pass between them.
A closed-loop system in which electrons can move is called a circuit. Electricity is supplied to the circuit by an electricity source, such as a battery. No electrons will travel till the circuit is finished, that is, it goes full round back to the electricity source.
A student wants to build a simple circuit.
The material would be used to design a circuit with the least amount of resistance will be short wires with a large diameter. Then the correct option is C.
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Describe how the motion and arrangement of particles in a substance change as the substance freezes.
Answer:
As a substance freezes, its particles lose some of their freedom of motion and become more orderly.
Explanation:
Answer:
They get closer and slow down
Explanation:
How are the components of a heterogeneous mixture distributed?
Answer:
heterogeneous mixture has components that are not evenly distributed. This means that you can easily distinguish between the different components.
Seafloor spreading is a process that occurs along ___________1____________. At ___________2____________ boundary, two plates move away from each other resulting to spreading of seafloor, thereby creating new ___________3____________ crust. Near the mid-oceanic ridge _________4__________ rocks are found and far from it are older.
Answer:
where is the answer choices
Explanation:
B4-WWT03: OBJECT CHANGING VELOCITY-WORK
A 2-kg object accelerates as a net force acts on it.
During the 5 seconds this force acts, the object
changes its velocity from 3 m/s east to 7 m/s west.
A student states:
"The initial kinetic energy of the object was 9 Joules, and the final kinetic energy was 49 Joules. Thus the change in
kinetic energy of this object during these 5 seconds was 40 J, and thus the work done on this object by the net force
during this period was also 40 J.
What if anything, is wrong with this statement? If something is wrong, identify it and explain how to correct
it. If this statement is correct, explain why.
Answer:
Part A;
he mass of the object, m = 2 kg
The initial speed of the object, u = 3 m/s east
The final speed of the object, v = 7 m/s west
The initial kinetic energy of the object = 1/2 × m × u² = 1/2 × 2 × 3² = 9 Joules
The final kinetic energy of the object = 1/2 × m × v² = 1/2 × 2 × 7² = 49 Joules
Based on the change in the momentum produced by the force which changes the direction of the object, we add the two energy quantities to get the total change in energy as follows;
The change in kinetic energy = 9 J + 49 J = 58 J
The statement is wrong because the change in momentum brought about by the force should be included when finding the the total change in kinetic energy of the object during the 5 seconds period
Part B;
The kinetic energy, K. E. = 1/2 × m × v²
The kinetic energy of the car A = 1/2 × 1000 × 6² = 18,000 J
The kinetic energy of the car B = 1/2 × 1600 × 8² = 51,200 J
The kinetic energy of the car C = 1/2 × 1200 × 8² = 38,400 J
The kinetic energy of the car D = 1/2 × 1600 × 4² = 12,800 J
Given that work required = Force × Distance, and the distance, is constant, we have;
The force required is directly proportional to the energy kinetic energy of the car that is to be stopped
Therefore, we have;
B = 1, C = 2, A = 3, and D = 4
The work needed to stop the car, W = The strength of the applied force, F × The given constant distance to stop, d
∴ W ∝ F.
Explanation:
Part A;
The mass of the object, m = 2 kg
The initial velocity of the object, u = 3 m/s east
The final velocity of the object, v = 7 m/s west
The initial kinetic energy of the object = [tex]1/2 * m * u^2 = 1/2 * 2 *3^2 = 9 \text{ Joules}[/tex]
The final kinetic energy of the object = [tex]1/2 * m * v^2 = 1/2 * 2 * 7^2 = 49 \text{ Joules}[/tex]
Based on the change in the momentum produced by the force which changes the direction of the object, we add the two energy quantities to get the total change in energy as follows;
The change in kinetic energy = [tex]9 J + 49 J = 58 J[/tex]
The statement is wrong because the change in momentum brought about by the force should be included when finding the the total change in kinetic energy of the object during the 5 seconds period.
Part B;
The kinetic energy, K. E. = 1/2 × m × v²
The kinetic energy of the car A = [tex]1/2 * 1000 *6^2 = 18,000 J[/tex]
The kinetic energy of the car B = [tex]1/2 * 1600 * 8^2 = 51,200 J[/tex]
The kinetic energy of the car C = [tex]1/2 * 1200 * 8^2 = 38,400 J[/tex]
The kinetic energy of the car D =[tex]1/2 * 1600 * 4^2 = 12,800 J[/tex]
Given that work required = Force × Distance, and the distance, is constant, we have;
The force required is directly proportional to the energy kinetic energy of the car that is to be stopped
Therefore, we have;
B = 1, C = 2, A = 3, and D = 4
The work needed to stop the car, W = The strength of the applied force, F × The given constant distance to stop, d.
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Dos personas aplican sendas fuerzas de 50N sobre una mesa, en direcciones horizontales perpendiculares entre sí. ¿Cuanto vale el módulo e la resultante de estas dos fuerzas? Ilustra tu respuesta con un dibujo.
Answer:
|Fr| = 50*√2 [N]
Explanation: (See Annex )
En el diagrama de cuerpo libre ( mostrado en el anexo) se ve que, al ser las dos fuerzas iguales (50 N) el paralelogramo formado para encontrar la resultante de las fuerzas (Fr) es un cuadrado, y la diagonal de ese cuadrado ( que es al mismo tiempo la hipotenusa del triangulo recto OPA ) es igual a:
Hipotenusa = |Fr| = √ (50)² + (50)²
|Fr| = √2* (50)²
|Fr| = 50*√2 [N]
Please help me out
please show solvings
Answer:
5) The approximate height is about 80 m. Choice (c)
6) The stone takes about 3 seconds to rise to its maximum height
Explanation:
Free Fall Motion
A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall.
If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the gravitational acceleration, which value is [tex]g = 9.8 m/s^2[/tex].
The distance traveled by a dropped object is:
[tex]\displaystyle y=\frac{gt^2}{2}[/tex]
Question 5
Given the stone reaches the ground in t=4 seconds, the height of the tower is:
[tex]\displaystyle y=\frac{9.8*4^2}{2}=78.4\ m[/tex]
The approximate height is about 80 m. Choice (c)
Question 6
Vertical Motion
The vertical motion of an object is controlled by the force of gravity. This means that there is a non-zero net force acting on the object that makes it accelerate downwards.
If the object is thrown upwards at speed vo, its speed at time t is:
[tex]v_f=v_o-g.t[/tex]
The stone reaches its maximum height when the final speed is zero, thus:
[tex]v_o-g.t=0[/tex]
Solving for t:
[tex]\displaystyle t=\frac{v_o}{g}[/tex]
The stone is thrown vertically upwards with vo=30 m/s, thus:
[tex]\displaystyle t=\frac{30}{9.8}[/tex]
[tex]t=3.06\ s[/tex]
[tex]t\approx 3\ s[/tex]
The stone takes about 3 seconds to rise to its maximum height
A car accident my rolls off a cliff as it leaves the cliff it has a horizontal velocity of 13 ms it hiys the ground 60 m from the shoreline calculate the height of the cliff
Answer:
104.59 m
Explanation:
The following data were obtained from the question:
Horizontal velocity (u) = 13 ms¯¹
Horizontal distance (s) = 60 m
Height (h) =?
Next, we shall determine the time taken for the car to get to the ground. This can be obtained as follow:
Horizontal velocity (u) = 13 ms¯¹
Horizontal distance (s) = 60 m
Time (t) =?
s = ut
60 = 13 × t
Divide both side by 13
t = 60 / 13
t = 4.62 s
Finally, we shall determine the height cliff. This can be obtained as follow:
Time (t) = 4.62 s
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) =?
h = ½gt²
h = ½ × 9.8 × 4.62²
h = 4.9 × 21.3444
h = 104.59 m
Thus, the height of the cliff is 104.59 m
HELP PLEASE!!!!!!!!!!!
Explanation:
Total horizontal force50cos16.25°N + 60N - 10N =98NTotal workdone force × distance
98×100= 9800J = 9.8kJ
why is gamma radiation difficult to detect
Answer:
2 reasons because there are not many of them and they have so much energy that it is hard to capture one at all
Answer:
they have a lot of energy that can prove difficult to capture
Explanation:
You wish to cool a 1.83 kg block of tin initially at 88.0°C to a temperature of 57.0°C by placing it in a container of kerosene initially at 24.0°C. Determine the volume (in L) of the liquid needed in order to accomplish this task without boiling. The density and specific heat of kerosene are respectively 820 kg/m3 and 2,010 J/(kg · °C), and the specific heat of tin is 218 J/(kg · °C).
Answer:
0.273 liters are needed to accomplish this task without boiling.
Explanation:
The minimum boiling point of kerosene is [tex]150\,^{\circ}C[/tex]. According to this question, we need to determine the minimum volume of liquid such that heat received is entirely sensible, that is, with no phase change.
If we consider a steady state process and that energy interactions with surrounding are negligible, then we get the following formula by the Principle of Energy Conservation:
[tex]\rho_{k}\cdot V_{k}\cdot c_{k}\cdot (T-T_{k,o}) = m_{t}\cdot c_{t}\cdot (T_{t,o}-T)[/tex] (1)
Where:
[tex]\rho_{k}[/tex] - Density of kerosene, measured in kilograms per cubic meter.
[tex]V_{k}[/tex] - Volume of kerosene, measured in cubic meters.
[tex]c_{k}[/tex], [tex]c_{t}[/tex] - Specific heats of the kerosene and tin, measured in joule per kilogram-Celsius.
[tex]T_{k,o}[/tex], [tex]T_{t,o}[/tex] - Initial temperatures of kerosene and tin, measured in degrees Celsius.
[tex]T[/tex] - Final temperatures of the kerosene-tin system, measured in degrees Celsius.
Please notice that the block of tin is cooled at the expense of the temperature of the kerosene until thermal equilibrium is reached.
From (1), we clear the volume of kerosene:
[tex]V_{k} = \frac{m_{t}\cdot c_{t}\cdot (T_{t,o}-T)}{\rho_{k}\cdot c_{k}\cdot (T-T_{k,o})}[/tex]
If we know that [tex]m_{t} = 1.83\,kg[/tex], [tex]c_{t} = 218\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]T_{t,o} = 88\,^{\circ}C[/tex], [tex]T_{k,o} = 24.0\,^{\circ}C[/tex], [tex]T = 57\,^{\circ}C[/tex], [tex]c_{k} = 2010\,\frac{J}{kg\cdot ^{\circ}C}[/tex] and [tex]\rho_{k} = 820\,\frac{kg}{m^{3}}[/tex], then the volume of the liquid needed to accomplish this task without boiling is:
[tex]V_{k} = \frac{(1.83\,kg)\cdot \left(218\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (88\,^{\circ}C-57\,^{\circ}C)}{\left(820\,\frac{kg}{m^{3}} \right)\cdot \left(2010\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (57\,^{\circ}C-24\,^{\circ}C)}[/tex]
[tex]V_{k} = 2.273\times 10^{-4}\,m^{3}[/tex]
[tex]V_{k} = 0.273\,L[/tex]
0.273 liters are needed to accomplish this task without boiling.
The water-balloon weighs 4.9 N. gravitational field strength = 9.8 N/kg Calculate the mass of the water-balloon
Answer:
0.5kg
Explanation:
Mass = Weight / Gravitational field strength
Mass = 4.9 / 9.8
Mass = 0.5
The momentum of an object can change. True or false?
Answer:
True
Explanation:
The momentum of the object won't change if it is left alone. However, if it is moved, the momentum will change. It depends on what you are talking about.
How would the cost of operating a 30 watt bulb relate to the cost of operating a 60 watt bulb for a given amount of time?
Explain what happens as an object moves through each phase of matter.
ASAP PLEASE ????????
Explanation:
gas vibrate and moves freely at high speeds, liquid vibrate, move about, and slide past each other. solid vibrate (jiggle) but generally do not move from place to place
hope it helps you
box
Complete the concept map on ATP production. Choose your answer from the
Key Words
Electron Transport Chain
Krebs Cycle
Pyruvate
Glycolysis
Glucose
ADP
C
ATP
Acetyl COA
ADP
IC
ATP
CO2
High energy electrons and H*
ADP
IC
ATP
02
H2O
Answer:
Glycolysis
Pyruvate
Krebs Cycle
Electron Transport Chain
Explanation:
The concept map on ATP production shows the process of cellular respiration in living organisms.
Cellular respiration begins with glucose which is broken down in the process of glycolysis that occur in cytoplasm and gives 2 ATP. Glycolysis gives pyruvate as end product that enter in the process of Krebs Cycle or citric acid cycle as a aerobic process, that occur in mitochondria and produces 2 ATP. This energy is then used in Electron Transport Chain to pump high energy electrons and H+ that produces 36 ATP.
how to draw a
electronics configuration
Answer:do you know how to draw a electronics configuration
Explanation:
Which statement best describes the adiabatic process?
Answer:
diaetes
Explanation:
Answer:
A: In an adiabatic process, no heat enters or leaves the system
What is the specific heat of a substance that absorbs 2500 joules of heat when a sample of 1.200 kg of the substance increases in temperature from 10.0°C to 70.0°C?
Answer:
0.035 J/g°C
Explanation:
From the question given above, the following data were obtained:
Heat (Q) absorbed = 2500 J
Mass (M) = 1.2 Kg
Initial Temperature (T₁) = 10 °C
Final Temperature (T₂) = 70 °C
Specific heat capacity (C) =?
Next, we shall determine the change in temperature. This can be obtained as follow:
Initial Temperature (T₁) = 10 °C
Final Temperature (T₂) = 70 °C
Change in temperature (ΔT) =
ΔT = T₂ – T₁
ΔT = 70 – 10
ΔT = 60 °C
Thus, the change in the temperature of the substance is 60 °C
Next, we shall convert 1.2 Kg to grams (g). This can be obtained as follow:
1 Kg = 1000 g
Therefore,
1.2 Kg = 1.2 Kg × 1000 g / 1 Kg
1.2 Kg = 1200 g
Thus, 1.2 Kg is equivalent to 1200 g.
Finally, we shall determine the specific heat capacity of substance. This can be obtained as follow:
Heat (Q) absorbed = 2500 J
Mass (M) = 1200 g
Change in temperature (ΔT) = 60 °C
Specific heat capacity (C) =?
Q = MCΔT
2500 = 1200 × C × 60
2500 = 72000 × C
Divide both side by 72000
C = 2500 / 72000
C = 0.035 J/g°C
Therefore, the specific heat capacity of the substance is 0.035 J/g°C
A person investing p at a certain rate of simpl interest after 1 2 and3 years it amounted to 1.5 p 2.5 p respectively what will it amount to at the end of 20 years
Answer: It will amount to 11p after 20 years.
Explanation:
Formula :
Simple interest = Principal x rate x Time (i)
Amount = Principal + Interest
Amount = Principal + Principal x rate x Time
Amount = Principal (1+ rate x Time) (ii)
Given: Principal = p
After 1 year , amount = 1.5p
After 3 years , amount = 2.5p
From (ii)
[tex]1.5p = p (1+r)\\\\\Rightarrow\ 1.5=1+r\\\\\Rightarrow\ 0.5= r\\\\\Rightarrow r= 0.5[/tex]
Amount after 20 years = p(1+ 0.5 x 20) = p(1+10)=11p
It will amount to 11p after 20 years.
What is the efficiency of a machine that lifts a load of 12.0 kg a vertical distance of 5.00
m in 30.0 s after being supplied with 70.0 W of power? Explain the steps you take to get the answer.
Answer:
Efficency = 28%
Explanation:
We have the load has a weight of:
[tex]w =m*g\\w =12*9.81\\w = 117.72 [N][/tex]
Work in physics is defined as the product of force (weight) by distance.
[tex]W=w*d[/tex]
where:
W = work [J]
w = weight = 117.72[N]
d = distance = 5 [m]
[tex]W=117.72*5\\W=588.6[J][/tex]
Now power is defined as the relationship of work at a certain time.
[tex]P=W/t\\[/tex]
where:
P = power [W]
W = work = 588.6[J]
t = time = 30[s]
[tex]P=588.6/30\\P=19.62[W][/tex]
Now the efficiency of a machine is defined as the power output over the power input to the machine. The power input should always be greater than the power output.
[tex]efficency = \frac{Power_{out}}{Power_{in}}\\Efficeny = \frac{19.62}{70} \\Efficency = 0.28\\Efficency = 28%[/tex]
All three springs show the same relationship between the weight and extension what is relationship tick one box
Answer:
The extension is directly proportional to the force exerted by the weight on the spring.
Explanation:
When the weight is suspended to a spring , the spring is extended through a length say x cm . This displacement is directly proportional to the force exerted on the spring equal to its weight.
Mathematically
F ∝ -x
F= -kx
where x is the displacement of the spring and k is the spring's constant whose value depends on the stiffness of the spring. F is the force exerted by the weight on the spring.
If more weight is added the extension will be greater . If less weight / force is applied the extension in the spring will be less.