Test One: If I breed a short fur, FF female with a short fur, Ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.
Since all these offspring only have one trait for long fur, this trait stays hidden in their DNA and is not expressed in their phenotype. All the offspring will have short fur.
Test Two: If I breed a short fur, Ff female with a short fur, Ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.
Test Three: If I breed a long fur, ff female with a long fur, ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.
Answers
Answer:
test two:
some short fur and some long fur will be seen.
this is because in some cases, the offsprings have only have the trait for short fur or just one trait for long fur and so short fur is expressed in the phenotype. in other cases, the offsprings have only the trait for long fur and so long fur is expressed phenotypically.
test three:
all long fur is seen.
since all the offsprings only have the trait for long fur and no trait for short fur, long fur is expressed in the phenotype.
Assuming a diallelic gene coding for the trait and expressing complete dominance, 1) all short fur. 2)some short and some long fur. 3) all long fur.
According to the information that was provided, we can assume that the trait fur length is coded by a single diallelic gene
• dominant allele F codes for short fur
• recessive allele f codes for long fur
We can also assume that the gene expresses complete dominance.
What is complete dominance?It is the inheritance pattern in which the dominant allele completely masks the recessive allele.
This is the case of individuals that are heter0zyg0us for a particular gene and express the dominant phenotype. The dominant allele is hiding the expression of the recessive allele.
Many genes show complete dominance.
Cross 1:
Parentals) FF x Ff
F1) 100% short fur
All short fur
Cross 2:
Parentals) Ff x Ff
F1) 1/4 FF + 1/2 Ff / 1/4 ff
75% short fur + 25% long fur
Some short fur, and some long fur
Cross 3:
Parentals) ff x ff
F1) 100% long fur
All long fur
Note: Due to technical problems, you will find the complete explanation in the attached files.
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