The histogram shows the heights of the student In Mrs. Sanche's class. What precent of the student are taller than 55 inches. Round your answer to the nearest tenth in necessary.

The formula for the area of the quadrilateral with side lengths B C = b₁, A D = b₂, and A B = h can be given by the expression:

Area = ½ × (b₁ + b₂) × h

Let's consider the quadrilateral with side lengths B C = b₁, A D = b₂, and A B = h. We can divide this quadrilateral into two triangles by drawing a diagonal from B to D. The height of both triangles is equal to h, which is the perpendicular distance between the parallel sides B C and A D.

To find the area of each triangle, we use the formula: Area = ½ × base × height. In this case, the base of each triangle is b₁ and b₂, respectively, and the height is h.

Therefore, the area of each triangle is given by:

Area₁ = ½ × b₁ × h

Area₂ = ½ × b₂ × h

Since the quadrilateral is composed of these two triangles, the total area of the quadrilateral is the sum of the areas of the two triangles:

Area = Area₁ + Area₂

     = ½ × b₁ × h + ½ × b₂ × h

     = ½ × (b₁ + b₂) × h

Hence, the conjecture is that the formula for the area of the quadrilateral with side lengths B C = b₁, A D = b₂, and A B = h is given by the expression: Area = ½ × (b₁ + b₂) × h.

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x = 4 is the point of inflection on the curve.

The second derivative of f(x) = 1/2 x^4 - 4x^3 is f''(x) = 6x^2 - 24x.

To find the critical points, we set f''(x) = 0, which gives us the equation 6x(x - 4) = 0.

Solving for x, we find x = 0 and x = 4 as the critical points.

We evaluate the second derivative of f(x) at different intervals to determine the sign of the second derivative. Evaluating f''(-1), f''(1), f''(5), and f''(9), we find that the sign of the second derivative changes when x passes through 4.

Therefore, The point of inflection on the curve is x = 4.

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(a)  The slope coefficient can be positive.

(b) the slope coefficient is not equal to 1.

(c) the coefficient of intercept is not zero.

(d) The slope coefficient is not equal to 1.

(a) Testing of Slope Coefficient for Positivity:

Hypothesis:

H0: β1 ≤ 0 (null hypothesis)

H1: β1 > 0 (alternative hypothesis)

Using the t-test approach:

t = β1 / SE(β1), where β1 is the slope coefficient and SE(β1) is the standard error of the slope coefficient.

Calculating the t-value:

t = 0.73 / 0.10 = 7.30

With 108 degrees of freedom (n-k-1 = 110-2-1=107), at a 5% significance level, the critical value is 1.66.

Since the calculated value of t (7.30) is greater than the critical value (1.66), we can reject the null hypothesis.

Therefore, the slope coefficient can be positive.

(b) Testing Coefficient of Intercept and Slope:

Testing the Coefficient of Intercept at 1% significance level:

Hypothesis:

H0: β0 = 0 (null hypothesis)

H1: β0 ≠ 0 (alternative hypothesis)

Using the t-test approach:

t = β0 / SE(β0) = 19.6 / 7.2 = 2.72

At a 1% significance level, the critical value is 2.61.

Since the calculated value of t (2.72) is greater than the critical value (2.61), we can reject the null hypothesis.

Therefore, the coefficient of intercept is not zero.

Testing the Slope Coefficient at 5% significance level:

Hypothesis:

H0: β1 = 1 (null hypothesis)

H1: β1 ≠ 1 (alternative hypothesis)

Using the t-test approach:

t = (β1 - 1) / SE(β1) = (0.73 - 1) / 0.10 = -2.7

At a 5% significance level, the critical value is 1.98.

Since the calculated value of t (-2.7) is less than the critical value (1.98), we fail to reject the null hypothesis.

Therefore, the slope coefficient is not equal to 1.

(c) Testing Coefficient of Intercept by p-value approach:

The p-value is the probability of obtaining results as extreme or more extreme than the observed results in the sample data, assuming that the null hypothesis is true.

If the p-value ≤ α (level of significance), then we reject the null hypothesis. Otherwise, we fail to reject the null hypothesis.

For the coefficient of intercept:

P-value = P(t ≥ t0) = P(t ≥ 2.72) = 0.004

At a 1% significance level, the p-value is less than 0.01. Therefore, we reject the null hypothesis.

Therefore, the coefficient of intercept is not zero.

(d) Testing Slope Coefficient by p-value approach:

For the slope coefficient:

P-value = P(t ≥ t0) = P(t ≥ -2.7) = 0.007

At a 5% significance level, the p-value is less than 0.05. Therefore, we reject the null hypothesis.

Therefore, The slope coefficient is not one.

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The mean height of 10 women to the nearest whole number is 156.

In statistics, the mean is a measure of central tendency that represents the average value of a set of data points. It is calculated by summing up all the values in the dataset and dividing the sum by the total number of data points.

To determine the mean (average) height of the 10 women, you need to sum up all the heights and divide the total by the number of women. Let's calculate it:

Sum of heights = 168 + 160 + 168 + 154 + 158 + 152 + 152 + 150 + 152 + 150 = 1556

Number of women = 10

Mean height = Sum of heights / Number of women = 1556 / 10 = 155.6

Rounding the mean height to the nearest whole number, we get 156.

Therefore, the correct answer is D. 156.

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The midpoint of the segment with endpoints A(-8, -5) and B(1, 7) is found by taking the average of the x-coordinates and the average of the y-coordinates.

To find the midpoint of a segment with given endpoints, we take the average of the x-coordinates and the average of the y-coordinates of the endpoints.

For the given endpoints A(-8, -5) and B(1, 7), we can calculate the midpoint as follows:

Midpoint x-coordinate:

(x-coordinate of A + x-coordinate of B) / 2 = (-8 + 1) / 2

= -7/2

= -3.5

Midpoint y-coordinate:

(y-coordinate of A + y-coordinate of B) / 2 = (-5 + 7) / 2

= 2 / 2

= 1

Therefore, the coordinates of the midpoint of the segment with endpoints A(-8, -5) and B(1, 7) are (-3.5, 1). The x-coordinate is -3.5, and the y-coordinate is 1.

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(a) The given differential equation is non-linear.

(b) The given differential equation is not separable.

(a) A differential equation is linear if it can be expressed in the form a(x) dx/dt + b(x) = c(x), where a(x), b(x), and c(x) are functions of x only. In the given differential equation, dx/dt = x(1-x), we have a quadratic term x(1-x), which makes the equation non-linear.

(b) A differential equation is separable if it can be rearranged into the form f(x) dx = g(t) dt, where f(x) and g(t) are functions of x and t, respectively. In the given differential equation, dx/dt = x(1-x), we cannot separate the variables x and t to obtain such a form, indicating that the equation is not separable.

To draw a phase portrait for the given differential equation, we can analyze the behavior of the solutions. The equation dx/dt = x(1-x) represents a population dynamics model known as the logistic equation. It describes the growth or decay of a population with a carrying capacity of 1.

At x = 0 and x = 1, the derivative dx/dt is equal to 0. These are the critical points or equilibrium points of the system. For 0 < x < 1, the population grows, and for x < 0 or x > 1, the population decays. The behavior near the equilibrium points can be determined using stability analysis techniques.

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Answer:

Step-by-step explanation:

The side lengths need to satisfy the Pythagorean theorem, meaning the sum of the squares of the missing side lengths must equal [tex]20^2=400[/tex].

The test statistic is z = -1.60

To test the claim that the percentage of readers who own a personal computer is different from the reported percentage, we can use a hypothesis test. Let's define our null hypothesis (H0) and alternative hypothesis (H1) as follows:

H0: The percentage of readers who own a personal computer is equal to 34%.

H1: The percentage of readers who own a personal computer is different from 34%.

We can use the z-test statistic to evaluate this hypothesis. The formula for the z-test statistic is:

[tex]z = (p - P) / \sqrt_((P * (1 - P)) / n)_[/tex]

Where:

p is the sample proportion (30% or 0.30)

P is the hypothesized population proportion (34% or 0.34)

n is the sample size (360)

Let's plug in the values and calculate the test statistic:

[tex]z = (0.30 - 0.34) / \sqrt_((0.34 * (1 - 0.34)) / 360)_\\[/tex]

[tex]z = (-0.04) / \sqrt_((0.34 * 0.66) / 360)_\\[/tex]

[tex]z = -0.04 / \sqrt_(0.2244 / 360)_\\[/tex]

[tex]z= -0.04 / \sqrt_(0.0006233)_[/tex]

[tex]z = -0.04 / 0.02497\\z = -1.60[/tex]

Rounding the test statistic to two decimal places, the value is approximately -1.60.

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Answer:

Step-by-step explanation:

There are 10 boys competing for 3 medals, so there are 10 choose 3 ways to award the medals to the boys. Similarly, there are 14 choose 3 ways to award the medals to the girls. Therefore, the total number of ways to award the six medals is:(10 choose 3) * (14 choose 3) = 120 * 364 = 43,680 So there are 43,680 different ways to award the six medals.

The values of ai in the given equation are not specified. More information is needed to determine the values of ai.

In the given equation, "d8 day +3 dn³ Find the values of ai," it is not clear what the specific values of ai are. The equation seems to involve derivatives (d) with respect to time (t), and the symbols day and dn represent different orders of differentiation.

However, without further information or context, it is not possible to determine the specific values of ai.

To provide a solution, we would need additional details or equations that define the relationship between the variables and derivatives involved. Without these details, it is not possible to solve the equation or find the values of ai.

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We have shown both directions of inclusion, we can conclude that Au (An B) = A.

Let's pick the first Absorption Law: Au (An B) = A. We will write a direct proof using the two-column method.

vbnet

Copy code

| Step | Reason                          |

|------|---------------------------------|

|  1   | Assume x ∈ (Au (An B))          |

|  2   | By definition of union, x ∈ A    |

|  3   | By definition of intersection, x ∈ An B |

|  4   | By definition of intersection, x ∈ B |

|  5   | By definition of union, x ∈ (Au B) |

|  6   | By definition of subset, (Au B) ⊆ A |

|  7   | Therefore, x ∈ A                |

|  8   | Conclusion: Au (An B) ⊆ A       |

Now, let's prove the other direction:

| Step | Reason                          |

|------|---------------------------------|

|  1   | Assume x ∈ A                    |

|  2   | By definition of union, x ∈ (Au B) |

|  3   | By definition of intersection, x ∈ An B |

|  4   | Therefore, x ∈ Au (An B)       |

|  5   | Conclusion: A ⊆ Au (An B)       |

Since we have shown both directions of inclusion, we can conclude that Au (An B) = A.

This completes the direct proof of the first Absorption Law.

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The composite functions for the given problems, which are as follows:f°g = 9x/5 - 5, domain is {x: x ≠ 0}.g°f = 5(x - 5)/9, domain is {x: x ≠ 5}.f°f = x - 5, domain is {x: x ≠ 5}.g°g = x, domain is {x: x ≠ 0}.

Given function f(x) = 9/x - 5 and g(x) = 5/x

We need to find the composite functions and state the domain of each.

a) Composite function f°g

We have, f(g(x)) = f(5/x) = 9/(5/x) - 5= 9x/5 - 5

The domain of f°g: {x : x ≠ 0}

Composite function g°f

We have, g(f(x)) = g(9/(x - 5)) = 5/(9/(x - 5))= 5(x - 5)/9

The domain of g°f: {x : x ≠ 5}

Composite function f°f

We have, f(f(x)) = f(9/(x - 5)) = 9/(9/(x - 5)) - 5= x - 5

The domain of f°f: {x : x ≠ 5}

Composite function g°g

We have, g(g(x)) = g(5/x) = 5/(5/x)= x

The domain of g°g: {x : x ≠ 0}

We have four composite functions in the given problem, which are as follows:f°g = 9x/5 - 5, domain is {x: x ≠ 0}.g°f = 5(x - 5)/9, domain is {x: x ≠ 5}.f°f = x - 5, domain is {x: x ≠ 5}.g°g = x, domain is {x: x ≠ 0}.

Composite functions are a way of expressing the relationship between two or more functions. They are used to describe how one function is dependent on another. The domain of a composite function is the set of all real numbers for which the composite function is defined. It is calculated by taking the intersection of the domains of the functions involved in the composite function. In this problem, we have calculated the domains of four composite functions, which are f°g, g°f, f°f, and g°g. The domains of each of the composite functions are different, and we have calculated them using the domains of the functions involved.

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Scenario 1A:

Coinsurance amount is $90

Medicare payment is $360

Provider write-off is $290

Scenario 1B:

Remaining amount for Insurance and patient to pay is $350

Coinsurance amount is $70

Total paid by patient is $170

Medicare payment is $280

Provider write-off is $370

Scenario 1A:

Submitted charge: $650

Medicare participating physician fee schedule (PFS): $450

Coinsurance amount (20% paid by patient): $

Medicare payment (80% of the PFS): $

Provider write-off: $

To calculate the missing amounts, we can use the provided information:

Coinsurance amount (20% paid by patient):

Coinsurance amount = 20% of the Medicare participating physician fee schedule (PFS)

Coinsurance amount = 0.2 * $450 = $90

Medicare payment (80% of the PFS):

Medicare payment = 80% of the Medicare participating physician fee schedule (PFS)

Medicare payment = 0.8 * $450 = $360

Provider write-off:

Provider write-off = Submitted charge - Medicare payment

Provider write-off = $650 - $360 = $290

Scenario 1B:

Submitted charge: $650

Medicare participating physician fee schedule (PFS): $450

Patient pays $100 remaining on their deductible

Remaining amount for Insurance and patient to pay: $

Coinsurance amount (20% of remaining amount): $

Total paid by patient (deductible & 20% of remaining): $

Medicare payment (80% of the remaining amount): $

Provider write-off: $

To calculate the missing amounts, we can use the provided information:

Remaining amount for Insurance and patient to pay:

Remaining amount for Insurance and patient to pay = PFS - remaining deductible

Remaining amount for Insurance and patient to pay = $450 - $100 = $350

Coinsurance amount (20% of remaining amount):

Coinsurance amount = 20% of the remaining amount

Coinsurance amount = 0.2 * $350 = $70

Total paid by patient (deductible & 20% of remaining):

Total paid by patient = remaining deductible + coinsurance amount

Total paid by patient = $100 + $70 = $170

Medicare payment (80% of the remaining amount):

Medicare payment = 80% of the remaining amount

Medicare payment = 0.8 * $350 = $280

Provider write-off:

Provider write-off = Submitted charge - Medicare payment

Provider write-off = $650 - $280 = $370

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The percent decrease in Val's fund from last quarter to this quarter is 14.4%

To calculate the percent decrease in Val's mutual fund from last quarter to this quarter, we can use the following formula:

Percent Decrease = (Change in Value / Initial Value) * 100

Given that last quarter her fund was worth $37,500 and this quarter it is worth $32,100, we can calculate the change in value:

Change in Value = Initial Value - Final Value

= $37,500 - $32,100

= $5,400

Now we can plug these values into the formula for percent decrease:

Percent Decrease = (5,400 / 37,500) * 100

= 0.144 * 100

= 14.4%

Therefore, the percent decrease in Val's fund from last quarter to this quarter is 14.4%.

This means that the value of Val's mutual fund decreased by 14.4% over the given time period. It is important to note that this calculation assumes a simple percentage decrease based on the initial and final values and does not take into account any additional factors such as fees or dividends.

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The value for s is 7.

Equations are mathematical statements containing two algebraic expressions on both sides of an 'equal to (=)' sign. It shows the relationship of equality between the expression written on the left side with the expression written on the right side.

Given:

Rearrange unknown terms to the left side of the equation:

[tex]\sf 5s-3s=9+5[/tex]

Combine like terms:

[tex]\sf 2s=9+5[/tex]

Calculate the sum or difference:

[tex]\sf 2s=14[/tex]

Divide both sides of the equation by the coefficient of variable:

[tex]\sf s=\dfrac{14}{2}[/tex]

[tex]\rightarrow \bold{s=7}[/tex]

Hence, the value for s is 7.

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66 € A is true as 66 is a multiple of 3, which is a member of A. Therefore, 66 € A is True. 0 € C (FALSE). The set C is not given. Therefore, it is not possible to say whether 0 belongs to C or not. Hence, 0 € C is false.

A. A = {0.313, 0.626, 0.939} B. B = {-1}
A set in mathematics is a collection of distinct objects called elements of the set. These elements could be numbers, letters, or any other kind of object. Here, we are going to use the roster method to represent the sets in list form.
The roster method is the method of representing a set by listing its elements within braces {}. A. Set A comprises all the natural numbers (x) that appear in the decimal expansion of 313/999. Now, let's solve the problem using the roster method: A = {0.313, 0.626, 0.939}. Set A comprises all the natural numbers (x) that appear in the decimal expansion of 313/999.
The roster method is the method of representing a set by listing its elements within braces {}. The set A can be represented in list form as A = {0.313, 0.626, 0.939}. B. The set B comprises all odd integers smaller than 1. The set B comprises all odd integers smaller than 1. The roster method is the method of representing a set by listing its elements within braces {}. The set B can be represented in list form as B = {-1}.2.
a) {1,1/4,1/16,1/64,...}
Notice that each term is of the form 1/4ⁿ. The next element in the set is 1/256.2.b) {3,3,6,9,15,24,...}
Notice that the differences between consecutive terms in the sequence are 0, 3, 3, 6, 9,.... The next term would be obtained by adding 12 to 24. Therefore, the next term is 36.3. a) 66 € A (TRUE) as 66 is a multiple of 3, which is a member of A. Therefore, 66 € A is True.
3. b) 0 € C (FALSE). The set C is not given. Therefore, it is not possible to say whether 0 belongs to C or not. Hence, 0 € C is False.
3. c) {4} € B (FALSE)The set B has only odd integers, and 4 is an even integer. Therefore, {4} € B is False. 3. d) C C A (FALSE)Since 0 € C is False, C € A is False.

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The length of each helix in the DNA molecule is approximately 7.68 centimeters.

To calculate the length of each helix, we need to multiply the rise per turn by the number of turns and convert the result to centimeters. Given that each helix rises about 32 Å (angstroms) during each complete turn and there are about 2.5 x 10^8 complete turns, we can calculate the length as follows:

Length of each helix = Rise per turn × Number of turns

                   = 32 Å × 2.5 x 10^8 turns

To convert the length from angstroms to centimeters, we can use the conversion factor: 1 Å = 10^(-8) cm.

Length of each helix = 32 Å × 2.5 x 10^8 turns × (10^(-8) cm/Å)

Simplifying the equation:

Length of each helix = 32 × 2.5 × 10^8 × 10^(-8) cm

                   = 8 × 10^(-6) cm

                   = 7.68 cm (rounded to two decimal places)

Therefore, the length of each helix in the DNA molecule is approximately 7.68 centimeters.

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The given vector as a linear combination are

To express the vector (17, 9, 17) as a linear combination of u, v, and w, we need to find the coefficients (i, j, k) such that:

(i)u + (j)v + (k)w = (17, 9, 17)

Substituting the given values for u, v, and w:

(i)(4, 1, 6) + (j)(1, -1, 5) + (k)(4, 2, 8) = (17, 9, 17)

Expanding the equation component-wise:

(4i + j + 4k, i - j + 2k, 6i + 5j + 8k) = (17, 9, 17)

By equating the corresponding components, we can solve for i, j, and k:

4i + j + 4k = 17 (Equation 1)

i - j + 2k = 9 (Equation 2)

6i + 5j + 8k = 17 (Equation 3)

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He probability that the sample contains one or more rotten oranges is approximately 0.533

To find the probability of selecting a sample with one or more rotten oranges, we need to calculate the probability of selecting at least one rotten orange.

Let's denote the event "selecting a rotten orange" as A, and the event "selecting a non-rotten orange" as B.

The probability of selecting a rotten orange in the first pick is 3/10 (since there are 3 rotten oranges out of a total of 10 oranges).

The probability of not selecting a rotten orange in the first pick is 7/10 (since there are 7 non-rotten oranges out of a total of 10 oranges).

To calculate the probability of selecting at least one rotten orange, we can use the complement rule. The complement of selecting at least one rotten orange is selecting zero rotten oranges.

The probability of selecting zero rotten oranges in a sample of two oranges can be calculated as follows:

P(selecting zero rotten oranges) = P(not selecting a rotten orange in the first pick) × P(not selecting a rotten orange in the second pick)

P(selecting zero rotten oranges) = (7/10) × (6/9) = 42/90

To find the probability of selecting one or more rotten oranges, we subtract the probability of selecting zero rotten oranges from 1:

P(selecting one or more rotten oranges) = 1 - P(selecting zero rotten oranges)

P(selecting one or more rotten oranges) = 1 - (42/90)

P(selecting one or more rotten oranges) = 1 - 0.4667

P(selecting one or more rotten oranges) ≈ 0.533

Therefore, the probability that the sample contains one or more rotten oranges is approximately 0.533 (rounded to three decimal places).

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The lab technician should mix 24 mL of the 15% acid solution with 56 mL of the 25% acid solution to obtain an 80 mL mixture with a 22% acid concentration.

Let's denote the volume of the 15% acid solution as "x" mL and the volume of the 25% acid solution as "y" mL.

We have the following information:

Volume of the resultant mixture: x + y = 80 mL (equation 1)

Percentage of acid in the resultant mixture: (0.15x + 0.25y)/(x + y) = 0.22 (equation 2)

We can now solve this system of equations to find the values of x and y.

From equation 1, we can express x in terms of y:

x = 80 - y

Substituting this value of x into equation 2, we have:

(0.15(80 - y) + 0.25y)/80 = 0.22

Simplifying the equation:

(12 - 0.15y + 0.25y)/80 = 0.22

12 + 0.10y = 0.22 * 80

12 + 0.10y = 17.6

0.10y = 17.6 - 12

0.10y = 5.6

y = 5.6 / 0.10

y = 56 mL

Now, substituting the value of y back into equation 1, we can find x:

x = 80 - 56

x = 24 mL

Therefore, the lab technician should mix 24 mL of the 15% acid solution with 56 mL of the 25% acid solution to obtain an 80 mL mixture with a 22% acid concentration.

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Answer:

Domain: [tex][-1,3)[/tex]

Range: [tex](-5,4][/tex]

Step-by-step explanation:

Domain is all the x-values, so starting with x=-1 which is included, we keep going to the left until we hit x=3 where it is not included, so we get [-1,3) as our domain.

Range is all the y-values, so starting with y=-5 which is not included, we keep going up until we hit y=4 where it is included, so we get (-5,4] as our range.

Let's denote the number of child tickets sold as 'c' and the number of adult tickets sold as 'a'.  Therefore, 60 child tickets were sold on Wednesday at the movie theatre.

Let's denote the number of child tickets sold as 'c' and the number of adult tickets sold as 'a'. We know that the price of a child ticket is $5.70 and the price of an adult ticket is $9.10. The total sales from 136 tickets sold is $1033.60.

We can set up the following system of equations:

c + a = 136 (equation 1, representing the total number of tickets sold)

5.70c + 9.10a = 1033.60 (equation 2, representing the total sales)

From equation 1, we can rewrite it as a = 136 - c and substitute it into equation 2:

5.70c + 9.10(136 - c) = 1033.60

Simplifying the equation, we have:

5.70c + 1237.60 - 9.10c = 1033.60

Combining like terms, we get:

-3.40c + 1237.60 = 1033.60

Subtracting 1237.60 from both sides, we have:

-3.40c = -204

Dividing both sides by -3.40, we find:

c = 60

Therefore, 60 child tickets were sold on Wednesday at the movie theatre.

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The expressions for the length, width, and height of the open box are L- 2x, W- 2x, x respectively.The diagram shows that the metalworker cuts equal squares from each corner of the sheet of metal.

To find the expressions for the length, width, and height of the open box, we need to understand how the sheet of metal is being cut to form the box.

When the metalworker cuts equal squares from each corner of the sheet, the resulting shape will be an open box. Let's assume the length and width of the sheet of metal are denoted by L and W, respectively.

1. Length of the open box:

To find the length, we need to consider the remaining sides of the sheet after cutting the squares from each corner. Since squares are cut from each corner,

the length of the open box will be equal to the original length of the sheet minus twice the length of one side of the square that was cut.

Therefore, the expression for the length of the open box is:

Length = L - 2x, where x represents the length of one side of the square cut from each corner.

2. Width of the open box:

Similar to the length, the width of the open box can be calculated by subtracting twice the length of one side of the square cut from each corner from the original width of the sheet.

The expression for the width of the open box is:

Width = W - 2x, where x represents the length of one side of the square cut from each corner.

3. Height of the open box:

The height of the open box is determined by the length of the square cut from each corner. When the metalworker folds the remaining sides to form the box, the height will be equal to the length of one side of the square.

Therefore, the expression for the height of the open box is:

Height = x, where x represents the length of one side of the square cut from each corner.

In summary:

- Length of the open box = L - 2x

- Width of the open box = W - 2x

- Height of the open box = x

Remember, these expressions are based on the assumption that equal squares are cut from each corner of the sheet.

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The graph of the inequality y > x² - 9 is given by the image presented at the end of the answer.

The inequality for this problem is given as follows:

y > x² - 9.

For the curve y = x² - 9, we have that:

Due to the > sign, the values greater than the inequality, that is, above the inequality, are shaded.

As the inequality does not have an equal sign, the parabola is dashed.

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To find the diameter of the hollow rubber ball, we need to determine its radius first.

We know that the surface area of the ball is 50 square feet. Using the formula for the surface area of a sphere, which is A = 4πr^2, we can substitute the given surface area and solve for the radius:

50 = 4πr^2

Dividing both sides of the equation by 4π, we get:

r^2 = 50 / (4π)

r^2 ≈ 3.98

Taking the square root of both sides, we find:

r ≈ √3.98

Now that we have the radius, we can calculate the diameter by multiplying the radius by 2:

diameter ≈ 2 * √3.98

Therefore, the approximate diameter of the hollow rubber ball is approximately 3.16 feet.

The Cartesian coordinates (x, y, z) are approximately (3.464, 2, -5) in decimals.

To convert the point (r, 0, z) = (4, π/6, -5) to Cartesian coordinates (x, y, z), we can use the formulas:

x = r * cos(θ)
y = r * sin(θ)
z = z

First, let's calculate x:

x = 4 * cos(π/6)
x = 4 * √3/2
x = 2√3

Now, let's calculate y:

y = 4 * sin(π/6)
y = 4 * 1/2
y = 2

Finally, z remains the same:

z = -5

So, the Cartesian coordinates for the point (r, 0, z) = (4, π/6, -5) are (x, y, z) = (2√3, 2, -5).

The values of x, y, and z are expressed as a combination of integers and square roots (√3) and cannot be simplified further. If you need the decimal values, you can approximate them using a calculator:

x ≈ 3.464
y = 2
z = -5

Therefore, the Cartesian coordinates (x, y, z) are approximately (3.464, 2, -5) in decimals.

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If we find the square of a negative number, say -x, where x > 0, then (-x) × (-x) = x 2. Here, x 2 > 0. Therefore, the square of a negative number is always positive.

The answer is:

below

Work/explanation:

The square of a negative number is always a positive number :

[tex]\sf{(-a)^2 = b}[/tex]

where b = the square of -a

The thing is, the square of a positive number is equal to the square of the same negative number :

[tex]\rhd\phantom{333} \sf{a^2 = (-a)^2}[/tex]

So if we take the square root of a number, let's say the number is 49 - we will end up with two solutions :

7, and -7

This was it.

The smaller number is 1 and the larger number is 15.

Let me explain the solution in more detail.

We are given two pieces of information:

1) One number is 15 times greater than another number: This can be represented as y = 15x, where y represents the larger number and x represents the smaller number.

2) 5 times the larger number minus twice the smaller number is 73: This can be represented as 5y - 2x = 73.

To solve the system of equations, we use the substitution method. We solve one equation for one variable and substitute it into the other equation.

In this case, we solve equation (1) for y by expressing y in terms of x: y = 15x.

Then we substitute this expression for y in equation (2):

5(15x) - 2x = 73

Multiplying 5 by 15x gives us 75x:

75x - 2x = 73

Simplifying the equation, we combine like terms:

73x = 73

Dividing both sides of the equation by 73, we get:

x = 1

Now that we have the value of x, we substitute it back into equation (1) to find the value of y:

y = 15(1)

y = 15

Therefore, the smaller number is 1 and the larger number is 15, satisfying both conditions given in the problem.

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