Answer: C) 48 N forward
===================================================
Explanation:
Subtract the two forces, since they are working opposite one another.
79-31 = 48
The net force is 48 newtons forward. The truck is moving forward since the engine's force (79 N) is larger than the force of friction (31 N).
The force of friction cannot exceed the engine's force because friction only slows down an object, and does not push the object backward. In other words, if the object was stationary, then the ground isn't pushing the object backwards assuming you're on a level flat ground.
1. A series circuit has three resistors, each on different paths and connected to a 120 V battery. Resistor 1 has a resistance of 5.0 Ω, Resistor 2 has a resistance of 7.5 Ω, and Resistor 3 has a resistance of 9.5 Ω. Create the circuit using the PhET simulator, and then draw a picture of the circuit you made. Then, fill in the table below for this circuit. Show your work completed. Measurements and the corresponding units Resistor 1 Resistor 2 Resistor 3 Total V (volts) 120 V I (A – amperes) R (Ω – ohms) 5.0 Ω 7.5 Ω 9.5 Ω P (W – work) Show your work: I=Vtotal/Rtotal. This gives you the total, I, which then allows you to calculate Ohm’s law for the other individual resistors. The total voltage spread across the three resistors should equal the total number of voltage periods. The power is determined by P 5 I 3 V.
Answer:
Measurements/cor. units Resistor 1 Resistor 2 Resistor 3 Total
V (volts) 24V 16V 12.63V 120 V
I (A – amperes) 4.8A 2.13A 1.34A 5.45A
R (Ω – ohms) 5.0 Ω 7.5 Ω 9.5 Ω 22Ω
P (W – work) 115.2W 34.08W 16.92W 2,640W
A roller coaster travels around a vertical 8-m radius loop. Determine the speed at the top of the loop if the normal force exerted by the seats on the passengers is equal to ¼ of their weight.
Answer:
[tex]v=10m/sec[/tex]
Explanation:
From the question we are told that
Radius of vertical r= 8m
Force exerted by passengers is 1/4 of weight
Generally the net force acting on top of the roller coaster is give to be
[tex]F_N+Fg[/tex]
where
[tex]F_N =forceof the normal[/tex]
[tex]Fg= force due to gravity[/tex]
Generally the net force is given to be [tex]FC(force towards center)[/tex]
[tex]F_C =F_N + Fg[/tex]
[tex]F_N =F_C -Fg[/tex]
[tex]F_N=F_C-F_g[/tex]
[tex]F_N=\frac{mv^2}{R} -mg[/tex]
Mathematical we can now derive V
[tex]m_g + \frac{8m}{4}= \frac{mv^2}{8}[/tex]
[tex]\frac{5mg}{4} =\frac{mv^2}{8}[/tex]
[tex]v^2 =\frac{40*10}{4}[/tex]
[tex]v=10m/sec[/tex]
Therefore the speed of the roller coaster is given ton be [tex]v=10m/sec[/tex]
[tex]v=10m/s[/tex]
Given:
Radius of vertical r= 8m
To find:
Force exerted by passengers is 1/4 of weight
Generally the net force acting on top of the roller coaster is give to be
[tex]F_N+F_g[/tex]
where
[tex]F_N=\text{Force of Normal}[/tex] and [tex]F_g=\text{Force due to gravity}[/tex]
Generally the net force is given to be [tex]FC- \text{Force towards centre}[/tex]
[tex]F_C=F_N+F_g\\\\F_N=F_C+F_g\\\\F_N=\frac{mv^2}{r} -mg[/tex]
Mathematically we can now derive V
[tex]mg-\frac{8m}{4} =\frac{mv^2}{8}\\\\\frac{5mg}{4}=\frac{mv^2}{8}\\\\v^2=\frac{40*10}{4} \\\\v=10m/s[/tex]
Therefore, the speed of the roller coaster is given to be 10m/s.
Learn more:
brainly.com/question/25834521
A cylindrical tank of radius R, filled to the top with a liquid, has a small hole in the side, of radius r, at distance d below the surface. Find an expression for the volume flow rate Q through the hole. Do not leave in terms of velocities, only leave in terms of r, R and d.
Answer:
Explanation:
v₁ , v₂ be velocity of flow of water at the surface and hole , h₁ and h₂ be height of surface and hole , P₁ and P₂ be pressure at surface and hole .
Using Bernoulli's formula for flow of liquid in tank
1/2 ρ v₁² + ρgh₁ + P₁ = 1/2 ρ v₂² + ρgh₂ + P₂
P₁ = P₂
1/2 ρ v₁² + ρgh₁ = 1/2 ρ v₂² + ρgh₂
1/2 ( v₁² - v₂² ) = g(h₂ -h₁ )
v₁² - v₂² = - 2gd
a₁ v₁ = a₂ v₂
π R² v₁ = π r² v₂
v₁ = r² v₂ / R²
v₁² - v₂² = -2gd
r⁴ v₂² / R⁴ - v₂² = -2gd
v₂² ( R⁴ - r⁴ ) = 2gd R⁴
v₂² = 2gd R⁴ / ( R⁴ - r⁴ )
v₂ = √ [ 2gd R⁴ / ( R⁴ - r⁴ ) ]
Compare and contrast Infra-red, visible light and UV.
Answer:
The EM radiation most immediately lower-frequency than visible light is called infrared, and the EM radiation most immediately higher-frequency is called ultraviolet.
Calculate the translational speed of a cylinder when it reaches the foot of an incline 7.05 mm high. Assume it starts from rest and rolls without slipping.
Height is 7.05 m and not 7.05 mm
Answer:
9.603 m/s
Explanation:
We are dealing with rotation, so velocity of centre of mass is given by;
v_cm = Rω
Since we are working with a solid cylinder, moment of inertia of the cylinder is; I = ½mR²
Since it is rolled from the top to the bottom, at the top it will have potential energy(mgh) while at the bottom it will have kinetic energy (rotational plus translational kinetic energy).
Using conservation of energy, we have:
P.E = K.E_t + K.E_r
Formula for rotational and kinetic energy here are;
K.E_t = ½mv²
K.E_r = ½Iω²
mgh = ½mv² + ½Iω²
Since we want to find translational speed(v), let's get rid of ω.
Earlier, we saw that v_cm = Rω
Thus; ω = v/R
Also, we know that I = ½mR².
Thus;
mgh = ½mv² + ½(½mR²)(v/R)²
This gives;
mgh = ½mv² + ¼mv²
Divide through by m to get;
gh = v²(½ + ¼)
gh = ¾v²
Making v the subject gives;
v = √(4gh/3)
v = √((4 × 9.81 × 7.05)/3)
v = 9.603 m/s
What us the difference in the ways objects move at a speed of a car and an object mkvinf close to the speed of light?
Answer:
The difference is in who or what is observing the speed.
Explanation:
Giving that speed is relative between the objects and the reference point from which it is being observed.
It is concluded that speed alone has no direct effect on a moving object, hence it is just a determining unit for the difference in distance between two objects.
Therefore, in this case, the difference is in who or what is observing the speed.
Based on the three-cell model of global circulation, surface winds diverge in the vicinity of:________.
a. the polar front
b. subpolar lows
c. the equator
d. the north and south poles
Answer:
a. the polar front
Explanation:
When the surface winds move towards the pole at angles that range from 30 to 60 degrees, they usually collide with cold air moving towards the equator. Since these two winds do not mix with ease, the polar front helps to separate them.
The three-cell model assumes that the earth is entirely filled with water thus removing any interactions with the land. It also assumes that there are no seasons nor Coriolis force.
I’m confused help me
Answer:
you select what ever feels right to you if you think what it tells you is true then you would say strongly agree and if you don't agree then it would be any of the other options
what is the answer to what does a 150 kg roller coaster traveling at 10m/s has how much kinetic energy
An athlete swings a 6.90-kg ball horizontally on the end of a rope. The ball moves in a circle of radius 0.830 m at an angular speed of 0.680 rev/s.
(a) What is the tangential speed of the ball?
m/s
(b) What is its centripetal acceleration?
m/s2
(c) If the maximum tension the rope can withstand before breaking is 110 N, what is the maximum tangential speed the ball can have?
m/s
Answer:
a) 0.5644 m/s
b) ~0.384 m/s^2
c) ~3.638 m/s
Explanation:
a) Tangential speed is found be the radius*rotational speed, so it is 0.83*0.68 = 0.5644 m/s
b) Centripetal acceleration is found by v^2/r, so it is (0.5644^2)/0.83 = ~0.384 m/s^2
c) Let the tangential speed be v. The maximum centripetal force 110 N (as given). Centripetal force = mass*centripetal acceleration = mass*v^2/r (because centripetal acceleration is found by v^2/r). Inputting the values from the problem and solving for v, we get:
110 = 6.9*v^2/0.83
v = sqrt(110*0.83/6.9) = ~3.638 m/s
I hope this helps! :)
Do you think antiseptic creams and lotions play an important part in our day
to day life?
Answer:
no, otherwise they just cause a side effect on our lives
Two identical blocks fall a distance H. One falls directly down, the other slides down a frictionless incline. Which has the larger speed at the bottom?
The question incomplete, the complete question is;
Two identical blocks fall a distance H. One falls directly down, the other slides down a frictionless incline.
(A)the one falling vertically
(B)the one on the incline
(C)Both have the same speed.
(D)cannot be determined
Answer:
(C)Both have the same speed.
Explanation:
When we consider the question closely, we will discover that an object falling down a frictionless incline is comparable to an object falling freely under gravity.
In both instances, the acceleration of objects is just the same irrespective of mass.
Hence, the object falling vertically and the object sliding down a frictionless plane will have the same speed at the bottom.
Which of the following terms refers to the gas that escapes a comet?
O Adust tail
OAplasma tail
O An asteroid
O Ameteorite
Answer:
The correct option is "a plasma tail"
Explanation:
Gases escaping from a comet are ionized by ultraviolent rays from the sun. These ionized gases are then carried away from the sun by the solar wind to form the plasma tail. While the plasma tail is made up of gases, the dust tail is made up of tiny solid particles (dust) that escapes from the comet and are also pushed away from the sun.
A hockey puck sliding on smooth ice at 4 m/s comes to a 1-m-high hill. Will it make it to the top of the hill?
Answer:
No it will not make to the top of the hill
Explanation:
From the question we are told that
The velocity is [tex]v = 4 \ m/s[/tex]
The height of the hill is [tex]h = 1 \ m[/tex]
Generally from the law of energy conservation we have that
The kinetic energy of the pluck at the level position = The potential energy of the pluck at the maximum height the pluck can get to
So
[tex]\frac{1}{2} * m * v^2 = m * g * h_{max}[/tex]
=> [tex]\frac{1}{2} * v^2 = g * h_{max}[/tex]
=> [tex]h_{max} = \frac{0.5 * v^2}{g}[/tex]
=> [tex]h_{max} = 0.8163 \ m[/tex]
Given that the maximum height which the pluck can get to at this speed given in the question is less than the height of the hill then conclusion will be that the pluck will not make it to the top of the hill
why is heat called a form of energy?
Answer:
Because heat can be converted from one form to another.
Heat is also does work, for example it sets water molecules into motion when boiling ( convection currency ).
since energy is the ability to do work, heat does work.
A ball is thrown horizontally from the top of a building 100m high. The ball strikes the ground at a point 120 m horizontally away from and below the point of release. What is the magnitude of its velocity just before it strikes the ground?
Answer:
44.3 m/s
Explanation:
Given that a ball is thrown horizontally from the top of a building 100m high. The ball strikes the ground at a point 120 m horizontally away from and below the point of release.
What is the magnitude of its velocity just before it strikes the ground ?
The parameters given are:
Height H = 100m
Since the ball is thrown from a top of a building, initial velocity U = 0
Let g = 9.8m/s^2
Using third equation of motion
V^2 = U^2 + 2gH
Substitute all the parameters into the formula
V^2 = 2 × 9.8 × 100
V^2 = 200 × 9.8
V^2 = 1960
V = 44.27 m/s
Therefore, the magnitude of its velocity just before it strikes the ground is 44.3 m/s approximately
Fon of the assignment will be graded by your teacher Question: In a lab experiment, A square of black paper and a square of white paper are place directly under 100-watt lamps for 30 minutes. Predict what happens to the temperature of each paper during the experiment.
Answer: OVERVIEW
Students will use black and white construction paper and a light source to learn that dark objects
absorb more light and reflect less light than bright objects. The activity also demonstrates the conversion
of radiant light energy into heat energy.
CONCEPTS
• Dark surfaces absorb more visible light energy than bright surfaces
• Dark surfaces reflect less visible light energy than bright surfaces
• Energy can change forms, in this case from radiant light energy to heat
• Clouds, being bright, reflect significant amounts of sunlight and help to regulate Earth’s temperature
MATERIALS
• 2 thermometers
• Flood lamp, desk lamp, or area in direct sunlight
• Ruler
• Construction paper, 1 piece white, 1 piece black, or 2 sheets photocopy paper
• Scissors
• Cellophane tape or rubber bands
• 2 empty metal food cans, same size (be sure rims are not jagged)
PREPARATION
The paper and the cans can be prepared beforehand or prepared as part of the activity (see Procedure).
Although two cans with their tops completely removed can be used, the experiment will be more effective
(have fewer external effects), if only holes are placed in the cans’ lids, e.g., two holes from a bottle opener
to empty material out of the can, and one center hole created with an awl for the thermometer. Only one
hole is actually needed for the experiment - for the thermometer. Cans can optionally be filled with water,
or this can be done as a separate experiment to demonstrate the higher heat capacity of water compared to
air.
You can either use a flood lamp or a desk lamp (light bulb) to simulate sunlight, as described here, or
you can place the cans on a windowsill (window closed) or other sheltered area in direct sunlight. A flood
lamp will be the most effective option, causing the largest temperature increases.
PROCEDURE
Engagement
Discuss whether dark surfaces (e.g., asphalt) or bright surfaces (e.g., concrete) tend to get hotter in
sunlight. Which would you rather walk on during the day in the summertime? What color are solar cells,
for example those found on some calculators or freeway call boxes?
Explanation: I hope this helps! ∧ ∧
⊂∵→ω←∵⊃
A sinusoidal wave with wavelength 0.500 m travels along a string. The maximum transverse speed of a point on the string is. 4.00 m/s and the maximum transverse acceleration is 1.00 x 105 m/s2. What is the propagation speed of the wave
Answer:
The velocity [tex]v = 1989.2 \ m/s[/tex]
Explanation:
From the question we are told that
The wavelength is [tex]\lambda = 0.500 \ m[/tex]
The maximum transverse speed is [tex]v = 4.0 \ m/s[/tex]
The maximum transverse acceleration is [tex]a = 1.00 *10^{5} \ m/s^2[/tex]
Generally the frequency of the wave is mathematically represented as
[tex]f = \frac{w}{2 \pi }[/tex]
Here w is the angular speed which is mathematically evaluated as
[tex]w = \frac{a}{v}[/tex]
=> [tex]w = \frac{1.00 *10^{5}}{4}[/tex]
=> [tex]w = 25000 \ rad/sec[/tex]
So
[tex]f = \frac{ 25000 }{2 * 3.142 }[/tex]
=> [tex]f = \frac{ 25000 }{2 * 3.142 }[/tex]
=> [tex]f = 3978.4 \ Hz[/tex]
Gnerally the propagation speed of the wave is mathematically represented as
[tex]v = f * \lambda[/tex]
=> [tex]v = 3978.4 * 0.500[/tex]
=> [tex]v = 1989.2 \ m/s[/tex]
What is the relationship between the type of energy sublevels present and the
principal energy level?
For the following types of electromagnetic radiation, how do the wavelength, frequency, and photon energy change as one goes from the top of the list to the bottom?
a. radio waves
b. infared radiation
c. visible light
d. ultraviolet radiation
e. gamma radiation
Answer:
Wavelength, frequency and the photon energy changes as the one goes across the ranges of the electro-magnetic radiations.
Explanation:
Electro-magnetic radiations may be defined as the form of energy that is radiated or given by the electro-magnetic radiations. The visible light that we can see is the one of the electro-magnetic radiations. Other forms are the radio waves, gamma waves, UV rays, infrared radiations, etc.
The wavelength of the radiations decreases as we go from a. radio waves -- b. infrared radiation -- c. visible light -- d. ultraviolet radiation -- e. gamma radiation.
The frequency of the radiations increases when we move from a. radio waves -- b. infrared radiation -- c. visible light -- d. ultraviolet radiation -- e. gamma radiation.
The photon energy of the radiations increases when we move from a. radio waves -- b. infrared radiation -- c. visible light -- d. ultraviolet radiation -- e. gamma radiation.
A stone is dropped into a deep well and is heard to hit the water 5 s after being dropped. Determine the depth of the well.
Answer:
122.5 m
Explanation:
From the question given above, the following data were obtained:
Time (t) = 5 s
Depth (h) =?
The depth of the well can be obtained as:
NOTE: Acceleration due to gravity (g) = 9.8 m/s²
h = ½gt²
h = ½ × 9.8 × 5²
h = 4.9 × 25
h = 122.5 m
Thus, the depth of the well is 122.5 m
A hydrogen atom that has lost its electron is moving east in aregion where the magnetic field is directed from south to north. Itwill be deflected:_____________
a. up
b. down
c. not at all
Answer:
a. up
Explanation:
As per the rule of Fleming left hand, the three fingers should be places in a perpendicular manner i.e. mutually also.
The fore finger depicts the field direction
The middle finger depicts the velocity
And, the thumb finger depicts the force direction that experienced on that particle i.e. charged
So the electrons would be deflects to up
Hence, the correct option is a.
(a) What is lightning?
If an electric iron of 1200W is used for 30minutes every day, find electric energy consumed in the month of November. Also calculate bill amount if the rate of 1 unit = Rs 2
Answer:
Electric energy produced in the month of April is 18 kWh
Explanation:
Given
P = 1200 W = 1.2 kW
Use time per day = 30 minutes = 1 / 2 hrs
We know,
No. of days in April = 30 days
Total time iron being used
T = 1 / 2 * 30 = 15 hrs
We know,
Energy consumed = Pt
Substituting the value of P and T
= 1.2 kW * 15 hr
= 18 kWh
Hence,
Electric energy produced in the month of April is 18 kWh
What is the potential energy of a spring that is compressed 0.65 m by a 25 kg block if the spring constant is 95 N/m?
A. 1.6J
B. 7.9J
C. 15J
D. 20J
Answer:
D. 20J
Explanation:
Answer:
20 JExplanation:
yes
In the attachment there is a density column where there is colour
Question: tell me why is the red at the bottom of the density column if it is the least dense
Jared is driving around a traffic circle. If he is traveling at a speed of 7.1 m/s, and it takes his 5.8 s to complete an entire loop around the traffic circle, what is the radius of the traffic circle?
A. 7.1 m
B. 6.6 m
C. 9.4 m
D. 5.6 m
Answer:
B. 6.6 m
Explanation:
Given;
speed of Jared , v = 7.1 m/s
time taken, T = 5.8 s
let the radius of the traffic circle = r
The speed of Jared is calculated as;
[tex]v = \frac{2\pi r}{T}[/tex]
Where;
v is speed of Jared
T is period of the motion
r is radius of the traffic circle
[tex]r = \frac{vT}{2\pi} \\\\r = \frac{7.1 \ \times \ 5.8}{2\pi} \\\\r = 6.55 \ m\\\\r = 6.6 \ m[/tex]
Therefore, the radius of the traffic circle is 6.6 m.
Sugar crystals enter a dryer at the rate of 1000 kg h-1 and at 20% w.b. moisture content. They leave the dryer at 3% w.b. moisture content. If the drying process requires 3000 kJ kg-1 of water removed, estimate the amount of heat required per hour and the rate of dry crystals out of the dryer.
Answer:
The dryer evaporate 200 - 24.74 kg of water per hour
To remove 1kg of water it need 3000 K J
So to remove, 175.26 Kg
it need 5.257x [tex]10^{5}[/tex] KJ of heat per hour.
Explanation:
In one hour, the amount of sugar entering = 1000 kg
w.b moisture content is defined as,
weight of water / weight of water + weight of dry
[tex]W_{w}[/tex]/[tex]W_{w}[/tex] + [tex]W_{d}[/tex] x 100
[tex]W_{w}[/tex] + [tex]W_{d}[/tex] = 1000 kg when entering
it has 20% moisture content when entering
[tex]W_{w}[/tex] = 0.2 x 1000 = 200 kg
when leaving it has 3% moisture content then weight of dry material
[tex]W_{d}[/tex] = 1000 - 200 = 800 Kg
[tex]\frac{W_{w}^{'} }{W_{w}^{'} + W_{d}^{'} }[/tex] = 0.03
[tex]\frac{W_{w}^{'} }{W_{w}^{'} + 800 }[/tex] = 0.03
[tex]W_{w} ^{'}[/tex] = 0.03 x [tex]W_{w} ^{'}[/tex] + 0.03 x 800
[tex]W_{w} ^{'}[/tex] = 24.74 kg
When leaving the dryer, the crystals has total weight of the water = 24.74 kg per hour.
The dryer evaporate 200 - 24.74 kg of water per hour
To remove 1kg of water it need 3000 K J
So to remove, 175.26 Kg
it need 5.257x [tex]10^{5}[/tex] KJ of heat per hour.
An object has an average acceleration of + 6.24 m/s ^ 2 for 0.300 s . At the end of this time the object's velocity is + 9.31 m/s . What was the object's initial velocity?
Answer:
initial velocity = 7.44 m/s (3 s.f.)
Explanation:
a = 6.24 m/s² t = 0.300 s v = 9.31 m/s u = ?
v = u + at
9.31 = u + (6.24 x 0.300)
9.31 = u + 1.872
u = 7.438
= 7.44 m/s (3 s.f.)
Hope this helps!
a slingshot is used to shoot a small ball upward into the air; when the pouch is released, the sling propels the ball upward. assuming no air resistance, as the ball is propelled upward, what kind of energy transformation is taking place
kinetic to gravitational potential
gravitational potential to kinetic
gravitational potential to chemical
chemical to kinetic
Explanation:
kinetic to gravitational