Answer: 0.3464 (correct upto 4 decimal places )
Step-by-step explanation:
[tex]\sqrt{3/25}[/tex]= [tex]\sqrt{3} /\sqrt{25\\}[/tex] (as the square root of 25 is 5)
=1.73205/5
=0.3464
Step 1: –10 + 8x < 6x – 4
Step 2: –10 < –2x – 4
Step 3: –6 < –2x
Step 4: ________
What is the final step in solving the inequality –2(5 – 4x) < 6x – 4?
x < –3
x > –3
x < 3
x > 3
Answer:
x<3
Step-by-step explanation:
[tex] - 2(5 - 4x) < 6x - 4 \\ - 10 + 8x < 6x - 4 \\ 8x - 6x < - 4 + 10 \\ 2x < 6 \\ x < 3[/tex]
HELPPPPPP ME PLEASEEEEE!!
Answer:
Step-by-step explanation:
The quadratic formula is y=ax^2+bx+c
If we move everything to the left side of the equation,
-6x^2=-9x+7 becomes
-6x^2+9x-7=0
a=-6, b=9, c=-7, so the third answer choice
Find the length of side a. 13, 5 B on a right triangle
In a right triangle, the length of side "a" is 12.
The Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides, can be used to find the length of side "a" in a right triangle with sides of 13 and 5 units.
Let's assign "a" as the unknown side. According to the Pythagorean theorem, we have the equation: [tex]a^{2}[/tex] = [tex]13^{2}[/tex] - [tex]5^{2}[/tex].
Simplifying the equation, we get [tex]a^{2}[/tex] = 169 - 25, which becomes [tex]a^{2}[/tex] = 144.
To solve for "a," we take the square root of both sides: a = √144.
The square root of 144 is 12. Therefore, side "a" has a length of 12 units.
In summary, using the Pythagorean theorem, we determined that side "a" in the right triangle with side lengths 13 and 5 units has a length of 12 units.
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Please help me I don't understand what to do in order to solve this question
Find x, the angle inscribed in the circle
x+y+2x=1,x-y+z=-5,3x+y+z=3.
Hence, The solution is:
x = 1
y = - 2
z = 2
Step-by-step explanation:
Combine Like Terms:3x + y = 1
Combine The Equations:x - y + z = 5
3x + y + z = 3
Eliminate Variables by Method of Elimination:x + y = -1
Unite The System of Linear Equations in Two Variables:x + y = -1
3x + y = 1
Obtain the solution:x = 1
y = -2
Substitute into an original equation:1 - (-2) + z = 5
Evaluate the Value of the Variable:z = 2
Solve a Three Variable System:Hence, The Solution is: x = 1, y = -2, z = 2
I hope this helps you!
3.
Your family is planning a road trip stretching from coast to coast for this summer. The route and the time frame are nearly set; now you need to plan out the finances. Your parents have decided that rental of an RV will be cheaper than staying in hotels, but they would like an estimate on the total cost. Can you help them?
a. To rent an RV, the following costs apply: $125 per day, plus 32 cents per mile. Additionally, to drop off the RV on the other side of the country, there is an extra fee of $2,500. Write an equation to describe the total cost of RV rental.
b. Your parents have two options for their road trip plans. The first option stretches over 3500 miles and includes fewer stops but more beautiful scenery. It will take about a week and a half (11 days). The second option stretches over just 3000 miles, but it includes more overnight stops and will therefore take two weeks (14 days). Which of these two options is cheaper?
c. Your little sister really wants to take the two-week trip, but your parents really want to keep the RV rental cost under $5,000. You can compromise by either taking a more direct route (lessening the miles) or by stopping for less overnight stays (lessening the days of the rental). What would the domains be for these two compromises? Justify why you think your domains are correct.
d. Write and solve equations to find how many miles or how many days you would have to eliminate in order to stay under the $5,000 budget. Explain each step as you solve your equations. Finally, make a recommendation to your parents about which compromise you think is best.
a. An equation to describe the total cost of RV rental:
Cost = (125 * d) + (0.32 * m) + 2500
b. Comparing the two costs will determine which option is cheaper.
c. For the more direct route: m ≤ 3500
For fewer overnight stays: d ≤ 14
These domains ensure that we don't exceed the original values for miles and days.
d. I recommend compromising by lessening the number of days of the rental. By reducing the rental period to 11 days, you can stay within the $5,000 budget while still allowing your little sister to take the two-week trip.
a. To write an equation for the total cost of RV rental, we can use the given information. The cost per day is $125, and there is an additional charge of 32 cents per mile. Let's denote the number of days as d and the number of miles as m. The equation for the total cost of RV rental can be written as:
Cost = (125 * d) + (0.32 * m) + 2500
b. To compare the costs of the two options, we need to calculate the total cost for each. Option 1 has 3500 miles and takes 11 days, while option 2 has 3000 miles and takes 14 days. We can substitute these values into the equation from part a to find the total costs for each option. Comparing the two costs will determine which option is cheaper.
c. To compromise and stay within a budget of $5,000, we can adjust either the number of miles or the number of days. For the more direct route, we can reduce the number of miles, and for fewer overnight stays, we can reduce the number of days. The domains for these compromises would be:
For the more direct route: m ≤ 3500
For fewer overnight stays: d ≤ 14
These domains ensure that we don't exceed the original values for miles and days.
d. To find the number of miles or days to eliminate in order to stay under the $5,000 budget, we can set up equations using the total cost equation from part a. Let's denote the reduced number of miles as m' and the reduced number of days as d'. We need to solve the following equation for each compromise:
(125 * d') + (0.32 * m') + 2500 ≤ 5000
By substituting the appropriate values into the equation and solving for m' or d', we can determine how many miles or days need to be eliminated.
Based on the given information, I recommend compromising by lessening the number of days of the rental. By reducing the rental period to 11 days, you can stay within the $5,000 budget while still allowing your little sister to take the two-week trip. This compromise ensures that you don't have to sacrifice too much scenic beauty or make drastic changes to the route.
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Find the slope of the lines graphed below (-1,-11) and (-6,-7)
Answer:
m=
[tex] \frac{y2 - y1}{x2 - x1} [/tex]
where x1 is- -1
x2 is -6
y1 is -11
y2 is -7
m=
[tex] \frac{ - 7 - ( - 11)}{ - 6 - ( - 1)} [/tex]
[tex] \frac{ - 7 + 11}{ - 6 + 1} [/tex]
[tex] \frac{4}{ - 5} [/tex]
gradient is
[tex] gradient = \frac{4}{ - 5} [/tex]
A parabola can be drawn given a focus of ... 100pts
Answer:
The parabola has a vertex at (3, -4), has a p-value of -6 and it opens downwards.
Step-by-step explanation:
The given directrix of the parabola is y = 2, which is a horizontal line.
This means that the parabola is vertical, with a vertical axis of symmetry.
The focus of a parabola is a fixed point located inside the curve. The y-coordinate of the given focus is y = -10. As this is below the directrix, it means that the parabola opens downwards.
The standard form of a vertical parabola is:
[tex]\boxed{(x-h)^2=4p(y-k)}[/tex]
where:
Vertex = (h, k)Focus = (h, k+p)Directrix: y = (k - p)Axis of symmetry: x = hAs the focus is (3, -10), then:
[tex](h, k+p)=(3,-10)[/tex]
[tex]\implies h = 3[/tex]
[tex]\implies k+p=-10[/tex]
As the directrix is y = 2, then:
[tex]k - p=2[/tex]
To find the value of k, sum the equations involved k and p to eliminate p:
[tex]\begin{array}{crcccr}&k &+& p& =& -10\\+&k& -& p& = &2\\\cline{2-6}&2k&&& =& -8\\\cline{2-6}\\\implies &k&&&=&-4\end{array}[/tex]
To find the value of p, substitute the found value of k into one of the equations:
[tex]-4-p=2[/tex]
[tex]p=-4-2[/tex]
[tex]p=-6[/tex]
Therefore, the values of h, k and p are:
h = 3k = -4p = -6The parabola has a vertex at (3, -4), has a p-value of -6 and it opens downwards.
The parabola has a vertex at (3, -4), has a p-value of -6 and it opens downwards.
How to determine the equation and vertex of a parabola?In Mathematics, the standard form of the equation of the directrix lines for any parabola is given by this mathematical equation:
(x - h)² = 4p(y - k).
Where:
h and k are the vertex.p is a point.Since the directrix is horizontal, the axis of symmetry would be vertical. This ultimately implies that, we would have the following parameters;
directrix is y = 2
Focus, (h, k + p) = (3, -10)
Next, we would determine the value of k as follows;
k + p = -10 .......equation 1
k - p = 2 .......equation 2
By solving the equations simultaneously, we have:
2k = -8
k = -4
For the value of p, we have the following from equation 2:
k - p = 2
-4 - p = 2
p = -4 - 2
p = -6
In conclusion, we can logically deduce that the parabola opens downward because the p-value is negative.
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Which system has the same solution as the system of equations shown?
3x + 2y = -5
2x + 3y = 5
Step-by-step explanation:
To find a system with the same solution as the given system, we can multiply both sides of both equations by a nonzero constant, which will result in a system that is equivalent to the original one.
For example, let's multiply the first equation by 2 and the second equation by 3:
First equation (multiplied by 2):
6x + 4y = -10
Second equation (multiplied by 3):
6x + 9y = 15
The new system of equations is:
6x + 4y = -10
6x + 9y = 15
This system has the same solution as the original system because it's just a scalar multiple of the original system.
What are all ordered triples of positive integers (x,y,z) whose products is 4 times their sum, If x < y
We can conclude that there are no ordered triples of positive integers (x, y, z) that satisfy the given equation and the condition x < y.
We are given that the product of three positive integers (x, y, z) is equal to four times their sum:
xyz = 4(x + y + z)
Rearranging the equation, we get:
xyz - 4x - 4y - 4z = 0
We can factor out a common factor of 4 from the terms on the right-hand side:
4(xy - x - y - z) = 0
Now, we have two cases to consider:
Case 1: xy - x - y - z = 0
In this case, we can rewrite the equation as:
x(y - 1) - (y + z) = 0
From this equation, we observe that (y + z) must be divisible by (y - 1). Since x < y, the minimum value of (y - 1) is 1, which means (y + z) should also be 1. However, since we are looking for positive integers, this case does not yield any solutions.
Case 2: xy - x - y - z = 4
In this case, we can rewrite the equation as:
x(y - 1) - (y + z) = 4
Similarly, we observe that (y + z) must be divisible by (y - 1), and now (y - 1) can take on a minimum value of 2. We can analyze different possibilities based on this:
If (y - 1) = 2, then (y + z) = 2. Since we are dealing with positive integers, the only possibility is y = 3 and z = -1, which does not satisfy the condition.
If (y - 1) = 3, then (y + z) = 3. The only possibility is y = 4 and z = -1, which also does not satisfy the condition.
If (y - 1) = 4, then (y + z) = 4. The only possibility is y = 5 and z = -1, which does not satisfy the condition.
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50 PTS!!!!!!!!!!! I NEED HELP!!!!!
Answer this question based on the table above. Choose the right answer.
Is the statement true that between 1966 and 1976 the average number of miles flown per passenger increased by one-third. (Yes or no)
Answer:
No
Step-by-step explanation:
To determine if the average number of miles flown per passenger increased by one-third between 1966 and 1976, we need to compare the increase in miles flown during that period.
According to the given table:
In 1966, the average number of miles flown per passenger was 711 miles.In 1976, the average number of miles flown per passenger was 831 miles.To find the increase in miles flown, subtract the 1966 value from the 1976 value:
[tex]\begin{aligned}\sf Increase\; in\; miles\; flown &= \sf 831 \;miles - 711\; miles\\&= \sf 120\; miles\end{aligned}[/tex]
Therefore, the average number of miles flown per passenger between 1966 and 1976 increased by 120 miles.
To check if the increase is one-third of the initial value, we need to calculate one-third of the 1966 value:
[tex]\begin{aligned}\sf One\;third \;of \;711 \;miles &= \sf \dfrac{1}{3} \times 711\; miles\\\\ &= \sf \dfrac{711}{3} \; miles\\\\&=\sf 237\;miles\end{aligned}[/tex]
Since the increase in miles flown (120 miles) is not equal to one-third of the initial 1966 value (237 miles), the statement that the average number of miles flown per passenger increased by one-third between 1966 and 1976 is not true.
Sam is a waiter at a local restaurant where he earns wages of $7 per hour. Sam figures that he also earns about $5 in tips for each person he serves. Sam works 6 hours on a particular day. If n represents the number of people Sam serves that day, which of the following functions could Sam use to figure E , his total earnings for the day?
The function Sam can use to figure his total earnings for the day, based on the number of people he serves, is E(n) = 42 + 5n.
To calculate Sam's total earnings for the day, we need to consider both his hourly wages and the tips he receives based on the number of people he serves. Let's break it down step by step.
First, we know that Sam earns $7 per hour as his wage. Since he works for 6 hours, his earnings from wages alone would be $7 multiplied by 6, which equals $42.
Next, Sam also earns about $5 in tips for each person he serves. We can represent the number of people Sam serves as "n". Therefore, his total tip earnings would be $5 multiplied by "n", which gives us 5n.
To calculate Sam's total earnings for the day, we add his earnings from wages and tips together. So the function representing his total earnings, "E", can be written as:
E(n) = 7(6) + 5n
Simplifying further, we get:
E(n) = 42 + 5n
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I need help with 53 please
Answer:
53)
[tex]f(x) = \frac{7(x - 4)(x + 6)}{(x + 4)(x + 5)} [/tex]
James wants to have earned $6,180 amount of interest in 28 years. Currently he finds
that his annual interest rate is 6.12%. Calculate how much money James needs to invest
as his principal in order to achieve this goal.
Answer:
$3606.44
Step-by-step explanation:
The question asks us to calculate the principal amount that needs to be invested in order to earn an interest of $6180 in 28 years at an annual interest rate of 6.12%.
To do this, we need to use the formula for simple interest:
[tex]\boxed{I = \frac{P \times R \times T}{100}}[/tex],
where:
I = interest earned
P = principal invested
R = annual interest rate
T = time
By substituting the known values into the formula above and then solving for P, we can calculate the amount that James needs to invest:
[tex]6180 = \frac{P \times 6.12 \times 28}{100}[/tex]
⇒ [tex]6180 \times 100 = P \times 171.36[/tex] [Multiplying both sides by 100]
⇒ [tex]P = \frac{6180 \times 100}{171.36}[/tex] [Dividing both sides of the equation by 171.36]
⇒ [tex]P = \bf 3606.44[/tex]
Therefore, James needs to invest $3606.44.
The slope of line BD is
y
2b
2a-c
E(a, b)
A(0, 0)
G
B(2a, 2b)
D(c, 0)
F
LL
C(2c, 0)
What is the equation of BD, simplified?
y - y₁ = m(x − x₁)
(x-c)
= √2²²= c)
2b
2a -
y -0 =
0 y = | D x - (₂22bcc)
b
C
1
2a -
0 y =
0 y = | 2²0 |x-12 2²0-c
2a
2a C
0 y = ( 2b )x - ( 2bc)
(2a-c) (2a - 2c)
Answer:
(c) y = 2b/(2a -c)x -2bc/(2a -c)
Step-by-step explanation:
Given the equation of line BD in point-slope form you want the simplified equation.
y -0 = (2b/(2a -c))(x -c)
SimplifiedThe equation is simplified by using the distributive property to eliminate parentheses.
[tex]y-0=\dfrac{2b}{2a-c}(x -c)\\\\\\y=\dfrac{2b}{2a-c}x-\dfrac{2b}{2a-c}c\\\\\\\boxed{y=\dfrac{2b}{2a-c}x-\dfrac{2bc}{2a-c}}\qquad\text{matches choice C}[/tex]
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The hip width x of adult females is normally distributed with a mean of 37.6 cm and a standard deviation of 4.36 cm. The maximum width of an aircraft seat that will accommodate 98% of all adult women is about: (Give your answer to one decimal places if necessary.)
Answer:
Step-by-step explanation:
To find the maximum width of an aircraft seat that will accommodate 98% of all adult women, we need to determine the corresponding z-score for the 98th percentile of the normal distribution.
First, we find the z-score corresponding to the 98th percentile using a standard normal distribution table or calculator. The z-score for the 98th percentile is approximately 2.05.
Next, we use the z-score formula to find the corresponding value in the original distribution:
z = (x - μ) / σ
Solving for x (the maximum width of the aircraft seat):
x = z * σ + μ
Substituting the values given:
x = 2.05 * 4.36 + 37.6
x ≈ 45.98
Therefore, the maximum width of an aircraft seat that will accommodate 98% of all adult women is approximately 46 cm (rounded to one decimal place).
Find the limit (if the limit exists). Solve in two different ways.
The limit of the trigonometric expression is equal to 0.
How to determine the limit of a trigonometric expression
In this problem we find the case of a trigonometric expression, whose limit must be found. This can be done by means of algebra properties, trigonometric formula and known limits. First, write the entire expression below:
[tex]\lim_{\Delta x \to 0} \frac{\cos (\pi + \Delta x) + 1}{\Delta x}[/tex]
Second, use the trigonometric formula cos (π + Δx) = - cos Δx to simplify the resulting formula:
[tex]\lim_{\Delta x \to 0} \frac{1 - \cos \Delta x}{\Delta x}[/tex]
Third, use known limits to determine the result:
0
The limit of the trigonometric function [cos (π + Δx) + 1] / Δx evaluated at Δx → 0 is equal to 0.
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15 yd
12 yd
20 yd
9 yd
Answer:
1080yd³
Step-by-step explanation:
1/2x12x9=54
54x20=1080
Determine the equation of the ellipse with foci... 100points
The equation of the ellipse with foci (7, 17) and (7, -13), and a major axis of length 34 is[tex](x^2/289) + (y^2/225) = 1.[/tex]
To determine the equation of an ellipse given its foci and the length of its major axis, we need to use the standard form equation for an ellipse. The standard form equation for an ellipse centered at the origin is:
[tex](x^2/a^2) + (y^2/b^2) = 1[/tex]
where 'a' represents the semi-major axis and 'b' represents the semi-minor axis.
In this case, we know that the distance between the foci is equal to 2a, which means a = 34/2 = 17. The foci of the ellipse are given as (7, 17) and (7, -13). The foci lie on the major axis of the ellipse, and since their y-coordinates differ by 30 (17 - (-13) = 30), the length of the major axis is equal to 2b, which means b = 30/2 = 15.
Now we have the values of a and b, so we can substitute them into the standard form equation:
[tex](x^2/17^2) + (y^2/15^2) = 1[/tex]
Simplifying further, we have:
[tex](x^2/289) + (y^2/225) = 1[/tex]
Therefore, the equation of the ellipse with foci (7, 17) and (7, -13), and a major axis of length 34 is:
[tex](x^2/289) + (y^2/225) = 1.[/tex]
This equation represents an ellipse centered at the point (0, 0) with a semi-major axis of length 17 and a semi-minor axis of length 15.
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Answer:
The equation of the ellipse with foci (7, 17) and (7, -13), and a major axis of length 34 is
To determine the equation of an ellipse given its foci and the length of its major axis, we need to use the standard form equation for an ellipse. The standard form equation for an ellipse centered at the origin is:
where 'a' represents the semi-major axis and 'b' represents the semi-minor axis.
In this case, we know that the distance between the foci is equal to 2a, which means a = 34/2 = 17. The foci of the ellipse are given as (7, 17) and (7, -13). The foci lie on the major axis of the ellipse, and since their y-coordinates differ by 30 (17 - (-13) = 30), the length of the major axis is equal to 2b, which means b = 30/2 = 15.
Now we have the values of a and b, so we can substitute them into the standard form equation:
Simplifying further, we have:
Therefore, the equation of the ellipse with foci (7, 17) and (7, -13), and a major axis of length 34 is:
This equation represents an ellipse centered at the point (0, 0) with a semi-major axis of length 17 and a semi-minor axis of length 15.
Show that y₁(t) = e^ãt cos(μt) and
y₂(t) = e^ãt sin(μt)
are a fundamental set of solutions and state the general solution.
The functions y₁(t) = e^ãt cos(μt) and y₂(t) = e^ãt sin(μt) are a fundamental set of solutions because they are linearly independent and satisfy the given homogeneous linear differential equation, allowing for the formation of the general solution.
To show that y₁(t) = e^ãt cos(μt) and y₂(t) = e^ãt sin(μt) are a fundamental set of solutions, we need to demonstrate two things: linear independence and satisfaction of the given homogeneous linear differential equation.
First, let's consider linear independence. We can prove it by showing that there is no constant c₁ and c₂, not both zero, such that c₁y₁(t) + c₂y₂(t) = 0 for all t.
Now, let's verify that y₁(t) and y₂(t) satisfy the homogeneous linear differential equation. If the given differential equation is of the form ay''(t) + by'(t) + cy(t) = 0, we can substitute y₁(t) and y₂(t) into the equation and verify that it holds true.
Once we have established linear independence and satisfaction of the differential equation, we can state that the general solution to the homogeneous linear differential equation is given by y(t) = c₁y₁(t) + c₂y₂(t), where c₁ and c₂ are arbitrary constants. This general solution represents the linear combination of the fundamental set of solutions.
In summary, y₁(t) = e^ãt cos(μt) and y₂(t) = e^ãt sin(μt) form a fundamental set of solutions for the given differential equation, and the general solution is given by y(t) = c₁y₁(t) + c₂y₂(t).
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{y=4x−19.4
y=0.2x−4.2
Answer:The solution of the linear equations y = 4x − 19.4 and y = 0.2x − 4.2 will be (4, -3.4). Then the correct option is A.
What is the solution to the equation?
The allocation of weights to the important variables that produce the calculation's optimum is referred to as a direct consequence.
The equations are given below.
y = 4x − 19.4 ...1
y = 0.2x−4.2 ...2
From equations 1 and 2, then we have
4x - 19.4 = 0.2x - 4.2
3.8x = 15.2
x = 4
Then the value of the variable 'y' will be calculated as,
y = 4 (4) - 19.4
y = 16 - 19.4
y = - 3.4
The solution of the linear equations y = 4x − 19.4 and y = 0.2x − 4.2 will be (4, -3.4). Then the correct option is A.
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Triangle RST with (2,0), s(-2,-3), and t(-2,3) reflected over the y axis. Find the coordinates and vertices
I
Step-by-step explanation:
The coordinates and vertices
which reflected over the y- axis are
r(-2,0) , s(2,-3) , and t(2,3).
answer following question
Answer:
Option (C), 8 am
Step-by-step explanation:
Newton's Law of Cooling is a mathematical model that describes the cooling process of an object. It states that the rate of change of temperature of an object is proportional to the difference between its temperature and the surrounding temperature.
The equation representing Newton's Law of Cooling is:
[tex]\dfrac{dT}{dt} = -k (T_0 - T_A)[/tex]
Where...
"dT/dt" is the rate of change of temperature with respect to time."k" is the cooling constant."T_0" is the temperature of the object."T_a" is the surrounding temperature.After solving the differential equation we get the following function:
[tex]T(t)=T_A+(T_0-T_A)e^{-kt}[/tex]
[tex]\hrulefill[/tex]
Given:
[tex]T_0=98.6 \ \textdegree F \ \text{(This is the average human body temperature)}\\\\T_f=T(t)=80\ \textdegree F \\\\T_A=40 \ \textdegree F \\\\k=0.1947[/tex]
Find:
[tex]T(??)= \ 80 \ \textdegree F[/tex]
Substituting the values into the formula:
[tex]T(t)=T_A+(T_0-T_A)e^{-kt}\\\\\\\Longrightarrow 80=40+(98.6-40)e^{-0.1947t}\\\\\\\Longrightarrow 80=40+58.6e^{-0.1947t}\\\\\\\Longrightarrow 40=58.6e^{-0.1947t}\\\\\\\Longrightarrow 0.682594=e^{-0.1947t}\\\\\\\Longrightarrow \ln(0.682594)=-0.1947t\\\\\\\Longrightarrow t=\dfrac{\ln(0.682594)}{-0.1947} \\\\\\\therefore \boxed{t \approx 2 \ \text{hours}}[/tex]
Thus, we can conclude the time of death was at 8 am.
Please help me with this question
An estimate for the mean is 47.6 kg.
How to calculate the mean for the set of data?In Mathematics and Geometry, the mean for this set of data can be calculated by using the following formula:
Mean = [F(x)]/n
Cumulative frequency = 10 + 7 + 2 + 8 + 3
Cumulative frequency = 30
For the total number of data based on the frequency, we have;
Total weight, F(x) = 10(40) + 7(52.5) + 2(65) + 8(77.5) + 3(90)
Total weight, F(x) = 40 + 367.5 + 130 + 620 + 270
Total weight, F(x) = 1427.5
Now, we can calculate the mean weight as follows;
Mean = 1427.5/30
Mean = 47.6 kg.
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A circles radius is 1 1/3 yard whats the perimeter
Step-by-step explanation:
Perimeter = pi * diameter
radius = 1 1/3 yard then diameter = 2 2/3 yd
perimter = pi * 2 2/3 yds = 8.38 yds
50 Points! Multiple choice geometry question. Photo attached. Thank you!
The correct option that would be sufficient to prove the right triangles ∆WXZ and ∆WYX is (A) WZ/WX = XW/YW
How to evaluate the corresponding ratio of the right trianglesThe perpendicular height of the right triangle divides the triangle in two triangles with the same proportions as the original triangle.
Considering the smaller right triangle ∆WXZ and the bigger triangle ∆WYX;
the side WZ of ∆WXZ will correspond to the side WX of ∆WYX and similarly, side XW of ∆WXZ will correspond to the side of ∆WYX
so we can we the proportion as;
WZ/WX = XW/YW
Therefore, the proportion WZ/WX = XW/YW would be sufficient to prove the right triangles ∆WXZ and ∆WYX
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If sin 0=8/17, and tan0<0, what is cos(0)
Use exact values. No decimals.
(0 means theta)
Answer: -15/17
Step-by-step explanation:
sin ∅ = 8/17
If you drew a a line in the 2rd quadrant because tan ∅ <0, which means tan∅ is negative.
Tan∅= sin∅/cos∅
they told you sin∅ is positive which is related to your y.
but cos∅ needs to be negative which is related to x
This happens in the second quadrant x is negative and y is positive.
Now we know which way to draw our line. Label the opposite of the angle 8 and the hypotenuse 17 because sin∅ = 8/17
Use pythagorean to find adjacent.
17² = 8² + a²
225 = a²
a = 15
The adjacent is negative because the adjacent is on the x-axis in the negative direction.
cos ∅ = adj/hyp
cos∅ = -15/17
Answer: -15/17
Step-by-step explanation:
In the first quadrant, all sine, cosine and tan are all positive. In the second quadrant, only sine is positive. Third quadrant, only tangent is positive and fourth quadrant, only cosine is positive.
Therefore, when sine is positive and tan is negative, the angle can only be in quadrant 2. Then draw the triangle. Draw a triangle with the angle from the origin, with the opposite leg from the angle with value of 8 and the hypotenuse of value 17. Since cosine is what the question is asking for, and we know the data given forms an right triangle, the value of the other leg is 15. It is an 8-15-17 special triangle or use the Pythagorean Theorem.
Finally, taking the cosine of the angle from the origin gives -15/17 since it is in quadrant 2.
Average rate of change
Here is a unit circle with point P at (1, 0) Find the coordinates of P after the circle rotates the given amount counter clockwise around its center
1. 1/3 of a full rotation: ?
2 1/2 of a full rotation: ?
3. 2/3 of a full rotation: ?
1. 1/3 of a full rotation: The coordinates of point P after rotating 1/3 of a full rotation counterclockwise are approximately (0.5, 0.866).
2. 1/2 of a full rotation: The coordinates of point P after rotating 1/2 of a full rotation counterclockwise are (-1, 0).
3. 2/3 of a full rotation: The coordinates of point P after rotating 2/3 of a full rotation counterclockwise are approximately (-0.5, -0.866).
1/3 of a full rotation:
To find the coordinates of point P after rotating 1/3 of a full rotation counter clockwise, we need to determine the angle of rotation.
A full rotation around the unit circle is 360 degrees or 2π radians.
Since 1/3 of a full rotation is (1/3) [tex]\times[/tex] 360 degrees or (1/3) [tex]\times[/tex] 2π radians, we have:
Angle of rotation = (1/3) [tex]\times[/tex] 2π radians
Now, let's use the properties of the unit circle to find the new coordinates.
At the initial position, point P is located at (1, 0).
Rotating counterclockwise by an angle of (1/3) [tex]\times[/tex] 2π radians, we move along the circumference of the unit circle.
The new coordinates of point P after the rotation will be (cos(angle), sin(angle)).
Substituting the angle of rotation into the cosine and sine functions, we get:
New coordinates of P = (cos((1/3) [tex]\times[/tex] 2π), sin((1/3) [tex]\times[/tex] 2π))
Calculating the values:
cos((1/3) [tex]\times[/tex] 2π) ≈ 0.5
sin((1/3) [tex]\times[/tex] 2π) ≈ 0.866
Therefore, the coordinates of point P after rotating 1/3 of a full rotation counterclockwise are approximately (0.5, 0.866).
1/2 of a full rotation:
Following a similar process, when rotating 1/2 of a full rotation counterclockwise, we have an angle of (1/2) [tex]\times[/tex] 2π radians.
New coordinates of P = (cos((1/2) [tex]\times[/tex] 2π), sin((1/2) [tex]\times[/tex] 2π))
Calculating the values:
cos((1/2) [tex]\times[/tex] 2π) = cos(π) = -1
sin((1/2) [tex]\times[/tex] 2π) = sin(π) = 0
Therefore, the coordinates of point P after rotating 1/2 of a full rotation counterclockwise are (-1, 0).
2/3 of a full rotation:
For a rotation of 2/3 of a full rotation counterclockwise, the angle is (2/3) [tex]\times[/tex] 2π radians.
New coordinates of P = (cos((2/3) [tex]\times[/tex] 2π), sin((2/3) [tex]\times[/tex] 2π))
Calculating the values:
cos((2/3) [tex]\times[/tex] 2π) ≈ -0.5
sin((2/3) [tex]\times[/tex] 2π) ≈ -0.866
Therefore, the coordinates of point P after rotating 2/3 of a full rotation counterclockwise are approximately (-0.5, -0.866).
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Given: AB || DC and m22=m24
Prove: AD || BC
D
4
2
1. AB||DC
2. m22-m24
B
Statements
3
3. 21 and 24 are supplements
4. ?
5. m21+m22-180°
6. 21 and 22 are supplements
7. AD BC
Reasons
1. given
2. given
3. same side interior angles thm.
4. def. of supplementary angles
5. substitution
def. of supplementary angles
converse same side interior angles thm
6.
7.
The missing statement 4 of the two column proof of AD ║ BC is:
Statement 4: m∠1 + m∠4 = 180°
How to complete the two column proof?The complete two column proof to show that AD || BC is as follows:
Statement 1: AD ║ DC
Reason 1: Given
Statement 2: m∠2 = m∠4
Reason 2: Given
Statement 3: ∠1 and ∠3 are supplements
Reason 3: Same side interior angles theorem
Statement 4: m∠1 + m∠4 = 180°
Reason 4: Def. of Supplementary angles
Statement 5: m∠1 + m∠2 = 180°
Reason 5: Substitution
Statement 6: ∠1 and ∠2 are supplements
Reason 6: Def. of Supplementary angles
Statement 7: AD ║ BC
Reason 7: Converse same side interior angles thm
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